Starting from either benzene or phenol how MON-0585 can be synthesized is to be stated. Concept introduction: Benzene is subjected to Friedal-Crafts reaction by treating with isopropyl chloride in the presence of AlCl 3 . The isopropylbenzene is brominated in the benzyl position by reaction with NBS. The bromocompound obtained is treated with phenol in the presence of AlCl 3 when a p-substituted phenol is produced. The p-substituted phenol when subjected to another Friedal-Crafts reaction with tert-butylchloride in the presence of AlCl 3 will produce MON-0585. To state: Starting from benzene how MON-0585 can be synthesized.

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5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3

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Chapter 16.SE, Problem 65AP

Interpretation Introduction

Interpretation:

Starting from either benzene or phenol how MON-0585 can be synthesized is to be stated.

Concept introduction:

Benzene is subjected to Friedal-Crafts reaction by treating with isopropyl chloride in the presence of AlCl₃. The isopropylbenzene is brominated in the benzyl position by reaction with NBS. The bromocompound obtained is treated with phenol in the presence of AlCl₃ when a p-substituted phenol is produced. The p-substituted phenol when subjected to another Friedal-Crafts reaction with tert-butylchloride in the presence of AlCl₃ will produce MON-0585.

To state:

Starting from benzene how MON-0585 can be synthesized.

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5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3

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