Starting from benzene and an acid chloride how to prepare diphenylmethane, (Ph) 2 CH 2 , is to be shown. Concept introduction: Friedal-Crafts acylation of benzene with an aromatic acid chloride leads to the formation of a diaryl ketone which when reduced with H 2 /Pd yields the corresponding diarylmethane. To show: Starting from benzene and acid chloride how to prepare diphenylmethane.

Question

5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3

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Question

Chapter 16.9, Problem 21P

Interpretation Introduction

Interpretation:

Starting from benzene and an acid chloride how to prepare diphenylmethane, (Ph)₂CH₂, is to be shown.

Concept introduction:

Friedal-Crafts acylation of benzene with an aromatic acid chloride leads to the formation of a diaryl ketone which when reduced with H₂/Pd yields the corresponding diarylmethane.

To show:

Starting from benzene and acid chloride how to prepare diphenylmethane.

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5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3

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