Organic Chemistry
Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
Question
Book Icon
Chapter 16.SE, Problem 47AP
Interpretation Introduction

a) Bromobenzene

Interpretation:

The major product(s) formed when bromobenzene is nitrated is to be given. Whether it will react faster or slower than benzene is also to be stated.

Concept introduction:

Monosubstituted benzenes can be nitrated using a mixture of Conc. HNO3 and H2SO4. Electron releasing substituent groups, excep halogens, activate the ring and direct the incoming electrophile to the o- and p-positions. Compounds with these substituent groups are more reactive than benzene. Halogens are o- and p-directors but they deactivate the ring. Hence halobenzenes are less reactive than benzene. Electron withdrawing substituent groups deactivate the ring and direct the incoming electrophile to the m-position. Compounds with these substituent groups are less reactive than benzene.

To give:

The major products formed when bromobenzene is nitrated and to state whether it will react faster or slower than benzene.

Expert Solution
Check Mark

Answer to Problem 47AP

The major products formed when bromobenzene is nitrated are o-bromonitrobenzene and p-bromonitrobenzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  1

Bromobenzene will react slower than benzene.

Explanation of Solution

Bromine is an o- and p-directing group. It also has considerable electron withdrawing inductive effect which deactivates the ring. Hence bromobenzene is less reactive than benzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  2

Conclusion

The major products formed when bromobenzene is nitrated are o-bromonitrobenzene and p-bromonitrobenzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  3

Bromobenzene will react slower than benzene.

Interpretation Introduction

b) Benzonitrile

Interpretation:

The major product(s) formed when benzonitrile is nitrated is to be given. Whether it will react faster or slower than benzene is also to be stated.

Concept introduction:

Monosubstituted benzenes can be nitrated using a mixture of Conc. HNO3 and H2SO4. Electron releasing substituent groups, except halogens, activate the ring and direct the incoming electrophile to the o- and p-positions. Compounds with these substituents are more reactive than benzene. Halogens are o- and p-directors but they deactivate the ring. Hence halobenzenes are less reactive than benzene. Electron withdrawing substituent groups deactivate the ring and direct the incoming electrophile to the m-position. Compounds with these substituents are less reactive than benzene.

To give:

The major products formed when benzonitrile is nitrated and to state whether it will react faster or slower than benzene.

Expert Solution
Check Mark

Answer to Problem 47AP

The major product formed when benzonitrile is nitrated is m-nitrobenzonitrile.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  4

Benzonitrile will react slower than benzene.

Explanation of Solution

The cyanide group is strongly electron withdrawing in nature. Hence it is a meta director. The attraction of electrons away from the ring reduces the electron density in the ring. Thus benzonitrile reacts slower than benzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  5

Conclusion

The major product formed when benzonitrile is nitrated is m-nitrobenzonitrile.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  6

Benzonitrile will react slower than benzene.

Interpretation Introduction

c) Benzoic acid

Interpretation:

The major product(s) formed when benzoic acid is nitrated is to be given. Whether it will react faster or slower than benzene is also to be stated.

Concept introduction:

Monosubstituted benzenes can be nitrated using a mixture of Conc. HNO3 and H2SO4. Electron releasing substituent groups, except halogens, activate the ring and direct the incoming electrophile to the o- and p-positions. Compounds with these substituents are more reactive than benzene. Halogens are o- and p-directors but they deactivate the ring. Hence halobenzenes are less reactive than benzene. Electron withdrawing substituent groups deactivate the ring and direct the incoming electrophile to the m-position. Compounds with these substituents are less reactive than benzene.

To give:

The major products formed when benzoic acid is nitrated and to state whether it will react faster or slower than benzene.

Expert Solution
Check Mark

Answer to Problem 47AP

The major product formed when benzoic acid is nitrated is m-nitrobenzoic acid.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  7

Benzoic acid will react slower than benzene.

Explanation of Solution

The C=O in carboxyl group is strongly electron withdrawing in nature. Hence it is a meta director. The attraction of electrons away from the ring reduces the electron density in the ring. Thus benzoic acid reacts slower than benzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  8

Conclusion

The major product formed when benzoic acid is nitrated is m-nitrobenzoic acid.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  9

Benzoic acid will react slower than benzene.

Interpretation Introduction

d) Nitrobenzene

Interpretation:

The major product(s) formed when nitrobenzene is nitrated is to be given. Whether it will react faster or slower than benzene is also to be stated.

Concept introduction:

Monosubstituted benzenes can be nitrated using a mixture of Conc. HNO3 and H2SO4. Electron releasing substituent groups, except halogens, activate the ring and direct the incoming electrophile to the o- and p-positions. Compounds with these substituents are more reactive than benzene. Halogens are o- and p-directors but they deactivate the ring. Hence halobenzenes are less reactive than benzene. Electron withdrawing substituent groups deactivate the ring and direct the incoming electrophile to the m-position. Compounds with these substituents are less reactive than benzene.

To give:

The major products formed when nitrobenzene is nitrated and to state whether it will react faster or slower than benzene.

Expert Solution
Check Mark

Answer to Problem 47AP

The major product formed when nitrobenzene is nitrated is m-dinitrobenzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  10

Nitrobenzene will react slower than benzene.

Explanation of Solution

The nitro group is strongly electron withdrawing in nature. Hence it is a meta director. The attraction of electrons away from the ring reduces the electron density in the ring. Thus nitrobenzene reacts slower than benzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  11

Conclusion

The major product formed when nitrobenzene is nitrated is m-dinitrobenzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  12

Nitrobenzene will react slower than benzene.

Interpretation Introduction

e) Benzenesulfonic acid

Interpretation:

The major product(s) formed when benzenesulfonic acid is nitrated is to be given. Whether it will react faster or slower than benzene is also to be stated.

Concept introduction:

Monosubstituted benzenes can be nitrated using a mixture of Conc. HNO3 and H2SO4. Electron releasing substituent groups, except halogens, activate the ring and direct the incoming electrophile to the o- and p-positions. Compounds with these substituents are more reactive than benzene. Halogens are o- and p-directors but they deactivate the ring. Hence halobenzenes are less reactive than benzene. Electron withdrawing substituent groups deactivate the ring and direct the incoming electrophile to the m-position. Compounds with these substituents are less reactive than benzene.

To give:

The major products formed when benzenesulfonic acid is nitrated and to state whether it will react faster or slower than benzene.

Expert Solution
Check Mark

Answer to Problem 47AP

The major product formed when benzenesulfonic acid is nitrated is m-nitro benzenesulfonic acid.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  13

Benzenesulfonic acid will react slower than benzene.

Explanation of Solution

The sulfonic acid group is strongly electron withdrawing in nature. Hence it is a meta director. The attraction of electrons away from the ring reduces the electron density in the ring. Thus benzenesulfonic acid reacts slower than benzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  14

Conclusion

The major product formed when benzenesulfonic acid is nitrated is m-nitro benzenesulfonic acid.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  15

Benzenesulfonic acid will react slower than benzene.

Interpretation Introduction

f) Methoxybenzene

Interpretation:

The major product(s) formed when methoxybenzene is nitrated is to be given. Whether it will react faster or slower than benzene is also to be stated.

Concept introduction:

Monosubstituted benzenes can be nitrated using a mixture of Conc. HNO3 and H2SO4. Electron releasing substituent groups, except halogens, activate the ring and direct the incoming electrophile to the o- and p-positions. Compounds with these substituents are more reactive than benzene. Halogens are o- and p-directors but they deactivate the ring. Hence halobenzenes are less reactive than benzene. Electron withdrawing substituent groups deactivate the ring and direct the incoming electrophile to the m-position. Compounds with these substituents are less reactive than benzene.

To give:

The major products formed when methoxybenzene is nitrated and to state whether it will react faster or slower than benzene.

Expert Solution
Check Mark

Answer to Problem 47AP

The major products formed when methoxybenzene is nitrated are o-nitromethoxybenene and p-nitromethoxybenene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  16

Methoxybenzene will react faster than benzene.

Explanation of Solution

The methoxy group is electron releasing in nature. Hence it is an o- and p-director. The attraction of electrons towards the ring increases the electron density in the ring. Thus methoxybenzene reacts faster than benzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  17

Conclusion

The major products formed when methoxybenzene is nitrated are o-nitromethoxybenene and p-nitromethoxybenene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  18

Methoxybenzene will react faster than benzene.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Do the Lone Pairs get added bc its valence e's are a total of 6 for oxygen and that completes it or due to other reasons. How do we know the particular indication of such.
NGLISH b) Identify the bonds present in the molecule drawn (s) above. (break) State the function of the following equipments found in laboratory. Omka) a) Gas mask b) Fire extinguisher c) Safety glasses 4. 60cm³ of oxygen gas diffused through a porous hole in 50 seconds. How long w 80cm³ of sulphur(IV) oxide to diffuse through the same hole under the same conditions (S-32.0.0-16.0) (3 m 5. In an experiment, a piece of magnesium ribbon was cleaned with steel w clean magnesium ribbon was placed in a crucible and completely burnt in oxy cooling the product weighed 4.0g a) Explain why it is necessary to clean magnesium ribbon. Masterclass Holiday assignmen PB 2
Hi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!!    I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!

Chapter 16 Solutions

Organic Chemistry

Ch. 16.4 - Prob. 11PCh. 16.4 - Acetanilide is less reactive than aniline toward...Ch. 16.4 - Prob. 13PCh. 16.5 - At what position would you expect electrophilic...Ch. 16.5 - Show the major product(s) from reaction of the...Ch. 16.6 - The herbicide oxyfluorfen can be prepared by...Ch. 16.7 - Treatment of p-bromotoluene with NaOH at 300°C...Ch. 16.8 - Prob. 18PCh. 16.8 - Prob. 19PCh. 16.8 - Prob. 20PCh. 16.9 - Prob. 21PCh. 16.10 - Prob. 22PCh. 16.10 - Prob. 23PCh. 16.SE - Prob. 24VCCh. 16.SE - The following molecular model of a...Ch. 16.SE - Prob. 26VCCh. 16.SE - Prob. 27VCCh. 16.SE - Aromatic iodination can be carried out with a...Ch. 16.SE - Prob. 29MPCh. 16.SE - The carbocation electrophile in a Friede1-Crafts...Ch. 16.SE - Prob. 31MPCh. 16.SE - The nitroso group, —N=O, is one of the few...Ch. 16.SE - Triphenylmethane can be prepared by reaction of...Ch. 16.SE - Using resonance structures of the intermediates,...Ch. 16.SE - Benzene and alkyl -substituted benzenes can be...Ch. 16.SE - Prob. 36MPCh. 16.SE - Hexachlorophene, a substance used in the...Ch. 16.SE - Benzenediazonium carboxylate decomposes when...Ch. 16.SE - 4-Chloropyridine undergoes reaction with...Ch. 16.SE - Propose a mechanism to account for the following...Ch. 16.SE - In the Gatterman-Kochreaction, a formyl group...Ch. 16.SE - Treatment of p-tert-butylphenol with a strong acid...Ch. 16.SE - Benzyl bromide is converted into benzaldehyde by...Ch. 16.SE - Prob. 44MPCh. 16.SE - Prob. 45MPCh. 16.SE - Prob. 46APCh. 16.SE - Prob. 47APCh. 16.SE - Prob. 48APCh. 16.SE - Predict the major monoalkylation products you...Ch. 16.SE - Name and draw the major product(s) of...Ch. 16.SE - Prob. 51APCh. 16.SE - Prob. 52APCh. 16.SE - What product(s) would you expect to obtain from...Ch. 16.SE - Prob. 54APCh. 16.SE - How would you synthesize the following substances...Ch. 16.SE - Prob. 56APCh. 16.SE - Prob. 57APCh. 16.SE - Prob. 58APCh. 16.SE - Prob. 59APCh. 16.SE - Prob. 60APCh. 16.SE - Prob. 61APCh. 16.SE - Prob. 62APCh. 16.SE - Prob. 63APCh. 16.SE - How would you synthesize the following substances...Ch. 16.SE - Prob. 65APCh. 16.SE - Prob. 66APCh. 16.SE - Draw resonance structures of the intermediate...Ch. 16.SE - Prob. 68APCh. 16.SE - p-Bromotoluene reacts with potassium amide to give...Ch. 16.SE - Prob. 70APCh. 16.SE - Prob. 71APCh. 16.SE - Prob. 72APCh. 16.SE - Use your knowledge of directing effects, along...Ch. 16.SE - Identify the reagents represented by the letters...Ch. 16.SE - Phenols (ArOH) are relatively acidic, and the...Ch. 16.SE - Prob. 76APCh. 16.SE - Prob. 77APCh. 16.SE - Melamine, used as a fire retardant and a component...
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY