Organic Chemistry
Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
Question
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Chapter 16.SE, Problem 47AP
Interpretation Introduction

a) Bromobenzene

Interpretation:

The major product(s) formed when bromobenzene is nitrated is to be given. Whether it will react faster or slower than benzene is also to be stated.

Concept introduction:

Monosubstituted benzenes can be nitrated using a mixture of Conc. HNO3 and H2SO4. Electron releasing substituent groups, excep halogens, activate the ring and direct the incoming electrophile to the o- and p-positions. Compounds with these substituent groups are more reactive than benzene. Halogens are o- and p-directors but they deactivate the ring. Hence halobenzenes are less reactive than benzene. Electron withdrawing substituent groups deactivate the ring and direct the incoming electrophile to the m-position. Compounds with these substituent groups are less reactive than benzene.

To give:

The major products formed when bromobenzene is nitrated and to state whether it will react faster or slower than benzene.

Expert Solution
Check Mark

Answer to Problem 47AP

The major products formed when bromobenzene is nitrated are o-bromonitrobenzene and p-bromonitrobenzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  1

Bromobenzene will react slower than benzene.

Explanation of Solution

Bromine is an o- and p-directing group. It also has considerable electron withdrawing inductive effect which deactivates the ring. Hence bromobenzene is less reactive than benzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  2

Conclusion

The major products formed when bromobenzene is nitrated are o-bromonitrobenzene and p-bromonitrobenzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  3

Bromobenzene will react slower than benzene.

Interpretation Introduction

b) Benzonitrile

Interpretation:

The major product(s) formed when benzonitrile is nitrated is to be given. Whether it will react faster or slower than benzene is also to be stated.

Concept introduction:

Monosubstituted benzenes can be nitrated using a mixture of Conc. HNO3 and H2SO4. Electron releasing substituent groups, except halogens, activate the ring and direct the incoming electrophile to the o- and p-positions. Compounds with these substituents are more reactive than benzene. Halogens are o- and p-directors but they deactivate the ring. Hence halobenzenes are less reactive than benzene. Electron withdrawing substituent groups deactivate the ring and direct the incoming electrophile to the m-position. Compounds with these substituents are less reactive than benzene.

To give:

The major products formed when benzonitrile is nitrated and to state whether it will react faster or slower than benzene.

Expert Solution
Check Mark

Answer to Problem 47AP

The major product formed when benzonitrile is nitrated is m-nitrobenzonitrile.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  4

Benzonitrile will react slower than benzene.

Explanation of Solution

The cyanide group is strongly electron withdrawing in nature. Hence it is a meta director. The attraction of electrons away from the ring reduces the electron density in the ring. Thus benzonitrile reacts slower than benzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  5

Conclusion

The major product formed when benzonitrile is nitrated is m-nitrobenzonitrile.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  6

Benzonitrile will react slower than benzene.

Interpretation Introduction

c) Benzoic acid

Interpretation:

The major product(s) formed when benzoic acid is nitrated is to be given. Whether it will react faster or slower than benzene is also to be stated.

Concept introduction:

Monosubstituted benzenes can be nitrated using a mixture of Conc. HNO3 and H2SO4. Electron releasing substituent groups, except halogens, activate the ring and direct the incoming electrophile to the o- and p-positions. Compounds with these substituents are more reactive than benzene. Halogens are o- and p-directors but they deactivate the ring. Hence halobenzenes are less reactive than benzene. Electron withdrawing substituent groups deactivate the ring and direct the incoming electrophile to the m-position. Compounds with these substituents are less reactive than benzene.

To give:

The major products formed when benzoic acid is nitrated and to state whether it will react faster or slower than benzene.

Expert Solution
Check Mark

Answer to Problem 47AP

The major product formed when benzoic acid is nitrated is m-nitrobenzoic acid.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  7

Benzoic acid will react slower than benzene.

Explanation of Solution

The C=O in carboxyl group is strongly electron withdrawing in nature. Hence it is a meta director. The attraction of electrons away from the ring reduces the electron density in the ring. Thus benzoic acid reacts slower than benzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  8

Conclusion

The major product formed when benzoic acid is nitrated is m-nitrobenzoic acid.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  9

Benzoic acid will react slower than benzene.

Interpretation Introduction

d) Nitrobenzene

Interpretation:

The major product(s) formed when nitrobenzene is nitrated is to be given. Whether it will react faster or slower than benzene is also to be stated.

Concept introduction:

Monosubstituted benzenes can be nitrated using a mixture of Conc. HNO3 and H2SO4. Electron releasing substituent groups, except halogens, activate the ring and direct the incoming electrophile to the o- and p-positions. Compounds with these substituents are more reactive than benzene. Halogens are o- and p-directors but they deactivate the ring. Hence halobenzenes are less reactive than benzene. Electron withdrawing substituent groups deactivate the ring and direct the incoming electrophile to the m-position. Compounds with these substituents are less reactive than benzene.

To give:

The major products formed when nitrobenzene is nitrated and to state whether it will react faster or slower than benzene.

Expert Solution
Check Mark

Answer to Problem 47AP

The major product formed when nitrobenzene is nitrated is m-dinitrobenzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  10

Nitrobenzene will react slower than benzene.

Explanation of Solution

The nitro group is strongly electron withdrawing in nature. Hence it is a meta director. The attraction of electrons away from the ring reduces the electron density in the ring. Thus nitrobenzene reacts slower than benzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  11

Conclusion

The major product formed when nitrobenzene is nitrated is m-dinitrobenzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  12

Nitrobenzene will react slower than benzene.

Interpretation Introduction

e) Benzenesulfonic acid

Interpretation:

The major product(s) formed when benzenesulfonic acid is nitrated is to be given. Whether it will react faster or slower than benzene is also to be stated.

Concept introduction:

Monosubstituted benzenes can be nitrated using a mixture of Conc. HNO3 and H2SO4. Electron releasing substituent groups, except halogens, activate the ring and direct the incoming electrophile to the o- and p-positions. Compounds with these substituents are more reactive than benzene. Halogens are o- and p-directors but they deactivate the ring. Hence halobenzenes are less reactive than benzene. Electron withdrawing substituent groups deactivate the ring and direct the incoming electrophile to the m-position. Compounds with these substituents are less reactive than benzene.

To give:

The major products formed when benzenesulfonic acid is nitrated and to state whether it will react faster or slower than benzene.

Expert Solution
Check Mark

Answer to Problem 47AP

The major product formed when benzenesulfonic acid is nitrated is m-nitro benzenesulfonic acid.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  13

Benzenesulfonic acid will react slower than benzene.

Explanation of Solution

The sulfonic acid group is strongly electron withdrawing in nature. Hence it is a meta director. The attraction of electrons away from the ring reduces the electron density in the ring. Thus benzenesulfonic acid reacts slower than benzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  14

Conclusion

The major product formed when benzenesulfonic acid is nitrated is m-nitro benzenesulfonic acid.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  15

Benzenesulfonic acid will react slower than benzene.

Interpretation Introduction

f) Methoxybenzene

Interpretation:

The major product(s) formed when methoxybenzene is nitrated is to be given. Whether it will react faster or slower than benzene is also to be stated.

Concept introduction:

Monosubstituted benzenes can be nitrated using a mixture of Conc. HNO3 and H2SO4. Electron releasing substituent groups, except halogens, activate the ring and direct the incoming electrophile to the o- and p-positions. Compounds with these substituents are more reactive than benzene. Halogens are o- and p-directors but they deactivate the ring. Hence halobenzenes are less reactive than benzene. Electron withdrawing substituent groups deactivate the ring and direct the incoming electrophile to the m-position. Compounds with these substituents are less reactive than benzene.

To give:

The major products formed when methoxybenzene is nitrated and to state whether it will react faster or slower than benzene.

Expert Solution
Check Mark

Answer to Problem 47AP

The major products formed when methoxybenzene is nitrated are o-nitromethoxybenene and p-nitromethoxybenene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  16

Methoxybenzene will react faster than benzene.

Explanation of Solution

The methoxy group is electron releasing in nature. Hence it is an o- and p-director. The attraction of electrons towards the ring increases the electron density in the ring. Thus methoxybenzene reacts faster than benzene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  17

Conclusion

The major products formed when methoxybenzene is nitrated are o-nitromethoxybenene and p-nitromethoxybenene.

Organic Chemistry, Chapter 16.SE, Problem 47AP , additional homework tip  18

Methoxybenzene will react faster than benzene.

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Chapter 16 Solutions

Organic Chemistry

Ch. 16.4 - Prob. 11PCh. 16.4 - Acetanilide is less reactive than aniline toward...Ch. 16.4 - Prob. 13PCh. 16.5 - At what position would you expect electrophilic...Ch. 16.5 - Show the major product(s) from reaction of the...Ch. 16.6 - The herbicide oxyfluorfen can be prepared by...Ch. 16.7 - Treatment of p-bromotoluene with NaOH at 300°C...Ch. 16.8 - Prob. 18PCh. 16.8 - Prob. 19PCh. 16.8 - Prob. 20PCh. 16.9 - Prob. 21PCh. 16.10 - Prob. 22PCh. 16.10 - Prob. 23PCh. 16.SE - Prob. 24VCCh. 16.SE - The following molecular model of a...Ch. 16.SE - Prob. 26VCCh. 16.SE - Prob. 27VCCh. 16.SE - Aromatic iodination can be carried out with a...Ch. 16.SE - Prob. 29MPCh. 16.SE - The carbocation electrophile in a Friede1-Crafts...Ch. 16.SE - Prob. 31MPCh. 16.SE - The nitroso group, —N=O, is one of the few...Ch. 16.SE - Triphenylmethane can be prepared by reaction of...Ch. 16.SE - Using resonance structures of the intermediates,...Ch. 16.SE - Benzene and alkyl -substituted benzenes can be...Ch. 16.SE - Prob. 36MPCh. 16.SE - Hexachlorophene, a substance used in the...Ch. 16.SE - Benzenediazonium carboxylate decomposes when...Ch. 16.SE - 4-Chloropyridine undergoes reaction with...Ch. 16.SE - Propose a mechanism to account for the following...Ch. 16.SE - In the Gatterman-Kochreaction, a formyl group...Ch. 16.SE - Treatment of p-tert-butylphenol with a strong acid...Ch. 16.SE - Benzyl bromide is converted into benzaldehyde by...Ch. 16.SE - Prob. 44MPCh. 16.SE - Prob. 45MPCh. 16.SE - Prob. 46APCh. 16.SE - Prob. 47APCh. 16.SE - Prob. 48APCh. 16.SE - Predict the major monoalkylation products you...Ch. 16.SE - Name and draw the major product(s) of...Ch. 16.SE - Prob. 51APCh. 16.SE - Prob. 52APCh. 16.SE - What product(s) would you expect to obtain from...Ch. 16.SE - Prob. 54APCh. 16.SE - How would you synthesize the following substances...Ch. 16.SE - Prob. 56APCh. 16.SE - Prob. 57APCh. 16.SE - Prob. 58APCh. 16.SE - Prob. 59APCh. 16.SE - Prob. 60APCh. 16.SE - Prob. 61APCh. 16.SE - Prob. 62APCh. 16.SE - Prob. 63APCh. 16.SE - How would you synthesize the following substances...Ch. 16.SE - Prob. 65APCh. 16.SE - Prob. 66APCh. 16.SE - Draw resonance structures of the intermediate...Ch. 16.SE - Prob. 68APCh. 16.SE - p-Bromotoluene reacts with potassium amide to give...Ch. 16.SE - Prob. 70APCh. 16.SE - Prob. 71APCh. 16.SE - Prob. 72APCh. 16.SE - Use your knowledge of directing effects, along...Ch. 16.SE - Identify the reagents represented by the letters...Ch. 16.SE - Phenols (ArOH) are relatively acidic, and the...Ch. 16.SE - Prob. 76APCh. 16.SE - Prob. 77APCh. 16.SE - Melamine, used as a fire retardant and a component...
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