Mechanics of Materials (10th Edition)
10th Edition
ISBN: 9780134319650
Author: Russell C. Hibbeler
Publisher: PEARSON
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Textbook Question
Chapter 10.7, Problem 10.89P
If σY = 50 ksi, determine the factor of safety for this loading based on (a) the maximum shear stress theory and (b) the maximum distortion energy theory.
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Chapter 10 Solutions
Mechanics of Materials (10th Edition)
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Ch. 10.3 - Use the strain transformation equations to...Ch. 10.3 - Determine the equivalent state of strain on an...Ch. 10.3 - Determine the equivalent state of strain which...Ch. 10.3 - Use the strain transformation equations to...Ch. 10.3 - Determine the equivalent state of strain, which...Ch. 10.3 - Solve Prob.103 using Mohrs circle. 103. The state...Ch. 10.3 - using Mohrs circle. 103. The state of strain at...Ch. 10.3 - Solve Prob.105 using Mohrs circle. 105. The state...Ch. 10.3 - Solve Prob.108 using Mohrs circle 108. The state...Ch. 10.3 - using Mohrs circle. 106. 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- Q1: A ductile bar of aluminum 1010 alloy. Using the distortion-energy and maximum- shear-stress theories determine the factors of safety for the following plane stress states: (α) σχ = 180 MPa, σy = 100 MPa (b) σx = 180 MPa, Txy = (c) σx = -160 MPa, Txy = 150 MPa (d) Txy 100 MPa = 100 MPaarrow_forwardDetermine the factor of safety as per tresca's max shear stress theoryarrow_forwardThe block is subjected to a force V = 48 kN . What is the resulting deflection Δ?arrow_forward
- 123.41 MPa 173.41 MPa 156.16 MPa 173.41 MPa -123.41 MPa -256.16 MPa 2.22 1.68 1.94 1.94 1.68 2.22arrow_forward1. We can visualize the factor of safety for an arbitrary stress using a surface in principal stress space. For a ductile material that yields according to a von Mises criterion with a yield stress σy, sketch the von Mises surface in σ₁ - 02 space and sketch the stress surface that corresponds to a factor of safety FoS = 2. For a brittle material that yields according to a max normal (Rankine) criterion with a tensile strength Gyt and a compressive strength σvc = 20yt, sketch the yield surface and the surface that corresponds to a factor of safety FoS = 2.arrow_forwardAt a critical point in a component, the state of stress is given as Oxx = 100 MPa, Oyy = 220 MPa, Oxy = Oyx = 80 MPa and all other stress components are zero. The yield strength of the material is 468 MPa. The factor of safety on the basis of maximum shear stress theory is (round off to one decimalarrow_forward
- Q1: A ductile bar of aluminum 1010 alloy. Using the distortion-energy and maximum- shear-stress theories determine the factors of safety for the following plane stress states: (a) σx = 180 MPa, σy = 100 MPa (b) σx = 180 MPa, Txy = 100 MPa (c) σx = -160 MPa, Txy = 100 MPa = 150 MPa (d) Txyarrow_forwardThe state of plane stress at a critical point in a steel machine bracket is shown. If the yield stress for steel is sY = 36 ksi, determine if yielding occurs using the maximum distortion energy theory.arrow_forwardA brittle material has the properties Sut = 30 kpsi and Suc = 90 kpsi. Using the brittle Coulomb- Mohr and modified- Mohr theories, determine the factors of safety for the following states of plane stress: a. x = 20 kpsi, Txy = −10 kpsi b. σx = - 15 kpsi, σy = 10 kpsi, Txy = -15 kpsiarrow_forward
- A loading condition is shown below. The wires at point A and D both made from a steel with the yield strength (Sy) of 190 MPa with 2 mm diameter. Using either maximum shear stress theory or distortion energy theory, determine the maximum load P that can be applied before yielding happens in the wires.arrow_forwardDetermine the diameter of a circular rod made of ductile material with a fatigue strength (complete stress reversal) σe = 280 MPa and a tensile yield strength of 350 MPa. The member is subjected to a varying axial load from 700 kN to – 300 kN. Assume Kt = 1.8 and F.S. = 2.arrow_forwardAn ASTM cast iron has minimum ultimate strengths of 32 kpsi in tension and 95 kpsi in compression. Find the factors of safety using Coulomb Fragile Mohr (CMF) and Modified Mohr (MM) theories for the following stress state. σx = −3 kpsi, σy = −9 kpsi, τx y = −4 kpsiarrow_forward
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