Mechanics of Materials (10th Edition)
10th Edition
ISBN: 9780134319650
Author: Russell C. Hibbeler
Publisher: PEARSON
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Chapter 10.7, Problem 10.84P
To determine
The smallest yield stress for steelbased on the maximum distortion energy theory.
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Determine the resulting maximum value of the normal stress. Specify the orientation of the plane on which these maximum values occur.
**The answer is tensile stress is 0 ksi at 90 degrees.
**The answer is compressive stress is 7 ksi at 0 degrees.
Can you explain how that is? This was my thought process: I know that tensile would be zero because the force P is actually going inwards and not outwards. I know that means that there would be a compressive force. I am confused on the angles, how is a tensile force going 90 degress if there technically is no force in the tensile direction. And how is there a compressive force at 90 degrees if there is a stress? thank you!
Remake the diagram for this problem. Empasize the area of 1,2,3, 4 and refer to the solution.
No need to solve. Just the diagram
Please full solution with the drawing. Big and clear handwriting
Chapter 10 Solutions
Mechanics of Materials (10th Edition)
Ch. 10.3 - Prove that the sum of the normal strains in...Ch. 10.3 - The state of strain at the point on the arm has...Ch. 10.3 - The state of strain at the point on the pin leaf...Ch. 10.3 - The state of strain at the point on the pin leaf...Ch. 10.3 - The state of strain at the point on the leaf of...Ch. 10.3 - Use the strain transformation equations and...Ch. 10.3 - Use the strain transformation equations and...Ch. 10.3 - Use the strain transformation equations to...Ch. 10.3 - Use the strain transformation equations to...Ch. 10.3 - Use the strain- transformation equations to...
Ch. 10.3 - Use the strain transformation equations to...Ch. 10.3 - Determine the equivalent state of strain on an...Ch. 10.3 - Determine the equivalent state of strain which...Ch. 10.3 - Use the strain transformation equations to...Ch. 10.3 - Determine the equivalent state of strain, which...Ch. 10.3 - Solve Prob.103 using Mohrs circle. 103. The state...Ch. 10.3 - using Mohrs circle. 103. The state of strain at...Ch. 10.3 - Solve Prob.105 using Mohrs circle. 105. The state...Ch. 10.3 - Solve Prob.108 using Mohrs circle 108. The state...Ch. 10.3 - using Mohrs circle. 106. The state of strain at a...Ch. 10.5 - The strain at point A on the bracket has...Ch. 10.5 - Determine (a) the principal strains at A, (b) the...Ch. 10.5 - Determine (a) the principal strains at A, in the...Ch. 10.5 - The following readings are obtained for each gage:...Ch. 10.5 - The following readings are obtained for each gage:...Ch. 10.5 - The following readings are obtained for each gage:...Ch. 10.5 - The following readings are obtained from each...Ch. 10.6 - For the case of plane stress, show that Hookes law...Ch. 10.6 - to develop the strain tranformation equations....Ch. 10.6 - Determine the modulus of elasticity and Polssons...Ch. 10.6 - If it is subjected to an axial load of 15 N such...Ch. 10.6 - If it has the original dimensions shown, determine...Ch. 10.6 - If it has the original dimensions shown, determine...Ch. 10.6 - A strain gage having a length of 20 mm Is attached...Ch. 10.6 - Determine the bulk modulus for each of the...Ch. 10.6 - The strain gage is placed on the surface of the...Ch. 10.6 - Determine the associated principal stresses at the...Ch. 10.6 - Determine the applied load P. What is the shear...Ch. 10.6 - If a load of P = 3 kip is applied to the A-36...Ch. 10.6 - The cube of aluminum is subjected to the three...Ch. 10.6 - The principal strains at a point on the aluminum...Ch. 10.6 - A uniform edge load of 500 lb/in. and 350 lb/in....Ch. 10.6 - Prob. 10.45PCh. 10.6 - A single strain gage, placed in the vertical plane...Ch. 10.6 - A single strain gage, placed in the vertical plane...Ch. 10.6 - If the material is graphite for which Eg = 800 ksi...Ch. 10.6 - Determine the normal stresses x and y in the plate...Ch. 10.6 - The steel shaft has a radius of 15 mm. Determine...Ch. 10.6 - Prob. 10.51PCh. 10.6 - The A-36 steel pipe is subjected to the axial...Ch. 10.6 - Air is pumped into the steel thin-walled pressure...Ch. 10.6 - Air is pumped into the steel thin-walled pressure...Ch. 10.6 - Prob. 10.55PCh. 10.6 - The thin-walled cylindrical pressure vessel of...Ch. 10.6 - The thin-walled cylindrical pressure vessel of...Ch. 10.6 - Prob. 10.58PCh. 10.7 - A material is subjected to plane stress. Express...Ch. 10.7 - A material is subjected to plane stress. Express...Ch. 10.7 - The yield stress for a zirconium-magnesium alloy...Ch. 10.7 - Solve Prob. 1061 using the maximum distortion...Ch. 10.7 - If a machine part is made of tool L2 steel and a...Ch. 10.7 - Solve Prob.1063 using the maximum distortion...Ch. 10.7 - Prob. 10.65PCh. 10.7 - If a shaft is made of a material for which y = 75...Ch. 10.7 - Solve Prob.1066 using the maximum shear stress...Ch. 10.7 - If the material is machine steel having a yield...Ch. 10.7 - The short concrete cylinder having a diameter of...Ch. 10.7 - Prob. 10.70PCh. 10.7 - The plate is made of Tobin bronze, which yields at...Ch. 10.7 - The plate is made of Tobin bronze, which yields at...Ch. 10.7 - An aluminum alloy is to be used for a solid drive...Ch. 10.7 - If a machine part is made of titanium (TI-6A1-4V)...Ch. 10.7 - The components of plane stress at a critical point...Ch. 10.7 - The components of plane stress at a critical point...Ch. 10.7 - The 304-stainless-steel cylinder has an inner...Ch. 10.7 - The 304-stainless-steel cylinder has an inner...Ch. 10.7 - If the 2-in diameter shaft is made from brittle...Ch. 10.7 - If the 2-in diameter shaft is made from cast iron...Ch. 10.7 - If Y = 50 ksi, determine the factor of safety for...Ch. 10.7 - Prob. 10.82PCh. 10.7 - If the yield stress for steel is Y = 36 ksi,...Ch. 10.7 - Prob. 10.84PCh. 10.7 - The state of stress acting at a critical point on...Ch. 10.7 - The shaft consists of a solid segment AB and a...Ch. 10.7 - The shaft consists of a solid segment AB and a...Ch. 10.7 - Prob. 10.88PCh. 10.7 - If Y = 50 ksi, determine the factor of safety for...Ch. 10.7 - The gas tank is made from A-36 steel and has an...Ch. 10.7 - The internal loadings at a critical section along...Ch. 10.7 - If the material is machine steel having a yield...Ch. 10.7 - If the material is machine steel having a yield...Ch. 10 - In the case of plane stress, where the in-plane...Ch. 10 - The plate is made of material having a modulus of...Ch. 10 - If the material is machine steel having a yield...Ch. 10 - Determine if yielding has occurred on the basis of...Ch. 10 - The 60 strain rosette is mounted on a beam. The...Ch. 10 - Use the strain transformation equations to...Ch. 10 - If the strain gages a and b at points give...Ch. 10 - Use the strain-transformation equations and...Ch. 10 - Use the strain transformation equations to...Ch. 10 - Specify the orientation of the corresponding...
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- Problem 4: The state of plane stress shown occurs in a machine component made of a steel with oYilled = 45 ksi. Take ox= 35.6 ksi. In the context of the maximum-distortion-energy criterion, for which of the following cases will yielding occur? If yielding does not occur, determine the corresponding factor of safety. a) Txy = 9 ksi b) Txy = 18 ksi c) Txy = 20 ksi 21 ksiarrow_forwardy A B 3 in. D C 2 in. -2 in. 1.5 in. E.arrow_forward1. We can visualize the factor of safety for an arbitrary stress using a surface in principal stress space. For a ductile material that yields according to a von Mises criterion with a yield stress σy, sketch the von Mises surface in σ₁ - 02 space and sketch the stress surface that corresponds to a factor of safety FoS = 2. For a brittle material that yields according to a max normal (Rankine) criterion with a tensile strength Gyt and a compressive strength σvc = 20yt, sketch the yield surface and the surface that corresponds to a factor of safety FoS = 2.arrow_forward
- gure 1 shows a compound bar with three different diameters, d1-9mm, d2-22mm, and d3-14mm machined from solid aluminium alloy stock, subjected to a tensile load of 30kN. If Young's odulus for the alloy is 69GPA determine the stress in section 2. Answer to be provided in MPa, correct to three decimal places - do not include a unit with your answer. L1 L2 L3 d2 d3 P Figure 1arrow_forwardWhat is the true answerarrow_forwardPlease answer the question in the picture and show all of your work please. Thank you for your help!arrow_forward
- C. For Problems 10–96 through 10–105, use the data from the indicated problem for the initial stress element to draw Mohr’s circle. Then determine the stress condition on the element at the specified angle of rotation from the given x-axis. Draw the rotated element in its proper relation to the initial stress element and indicate the normal and shear stresses acting on it. JUST DO 10-96 PLEASEarrow_forwardDraw and stress tensonr with the following characteristics The stress cube visualization at point A would depict the normal stress (σ_x) acting on two opposite faces and the shear stress (τ_xy) acting tangentially on the four sides associated with torsion.arrow_forwardEngineering and truearrow_forward
- If a machine part is made of tool L2 steel and a critical point in the material is subjected to in-plane principal stresses s1 and s2 = -0.5s1, determine the magnitude of s1 in ksi that will cause yielding according to the maximum shear stress theory.arrow_forwardSOLVE CAREFULLY!! Please Write Clearly and Box the final Answer for Part A and Part B with Thank you Express your answer to three significant figures With correct unitsarrow_forwardFor the stresses given with the cube below: 1. Compute the center, radius (R), principal normal stresses (0₁ and 03), max shear stress (Tmax) and draw the Mohr's Circle. 2. Compute the normal and shear stresses when the cube is rotated 20° clockwise from the horizontal plane and draw them on the cube. 3. The yield point stress (σyp) is 6 kPa. Determine if the material will fail under stresses shown using Tresca's Hexagon. вкра акра 6 экра 8 кра экра 4краarrow_forward
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