(a)
Interpretation:
IUPAC name for the given
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of
Root word represents the longest continuous carbon skeleton of the organic molecule.
To name an alkane, the first step is to find the longest carbon chain. The next step is to identify the substituents that are present in the longest carbon chain. The numbering has to be given in a way that the substituents get the least numbering.
(b)
Interpretation:
IUPAC name for the given alkane has to be written.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
Root word represents the longest continuous carbon skeleton of the organic molecule.
To name an alkane, the first step is to find the longest carbon chain. The next step is to identify the substituents that are present in the longest carbon chain. The numbering has to be given in a way that the substituents get the least numbering.
(c)
Interpretation:
IUPAC name for the given alkane has to be written.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
Root word represents the longest continuous carbon skeleton of the organic molecule.
To name an alkane, the first step is to find the longest carbon chain. The next step is to identify the substituents that are present in the longest carbon chain. The numbering has to be given in a way that the substituents get the least numbering.
(b)
Interpretation:
IUPAC name for the given alkane has to be written.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
Root word represents the longest continuous carbon skeleton of the organic molecule.
To name an alkane, the first step is to find the longest carbon chain. The next step is to identify the substituents that are present in the longest carbon chain. The numbering has to be given in a way that the substituents get the least numbering.
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Chapter 1 Solutions
Organic And Biological Chemistry
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- 4. Calculate the total number of sigma bonds and total number of pi bonds in each of the following compounds. a. HH :D: +1 I H-N-C-C-O-H I H b. HH H Н :N=C-C-C=C-CEC-H :0: total o H-C-H H-C = `C-H I H. 11 H-C = C= CH H total o total π total π 1 Harrow_forwardIn the following reaction, what quantity in moles of CH₃OH are required to give off 4111 kJ of heat? 2 CH₃OH (l) + 3 O₂ (g) → 2 CO₂ (g) + 4 H₂O(g) ∆H° = -1280. kJarrow_forwardIndicate the processes in the dismutation of Cu2O.arrow_forward
- 1. Consider these three reactions as the elementary steps in the mechanism for a chemical reaction. 2600 2400 2200 2000 1800 1600 1400 1200 1000 800 Potential Energy (kJ) 600 400 200 0 -200- -400 -600- -800 (i) Cl₂ (g) + Pt(s) → 2Cl (g) + Pt(s) (ii) Cl (g)+ CO (g) + Pt (s) → CICO (g) + Pt (s) Ea = 1550 kJ Ea = 2240 kJ (iii) Cl (g) + CICO (g) → Cl₂CO (g) Ea = 2350 kJ AH=-950 kJ ΔΗ = 575 ΚΙ AH=-825 kJ a. Draw the potential energy diagram for the reaction. Label the data points for clarity. The potential energy of the reactants is 600 kJ Reaction Progress b. What is the overall chemical equation? c. What is the overall change in enthalpy for the above chemical reaction? d. What is the overall amount of activation energy for the above chemical reaction? e. Which reaction intermediate would be considered a catalyst (if any) and why? f. If you were to add 2700kJ of energy to the reaction (e.g. 2700 kl of heat or electricity), would you be able to make the reaction reverse itself (i.e. have…arrow_forwarddraw the enolate anion and the carbonyl that would be needed to make this product through an aldol addition reaction.arrow_forwardDraw the Michael Adduct and the final product of the Robinson annulation reaction. Ignore inorganic byproducts.arrow_forward
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