Organic And Biological Chemistry
Organic And Biological Chemistry
7th Edition
ISBN: 9781305081079
Author: STOKER, H. Stephen (howard Stephen)
Publisher: Cengage Learning,
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Chapter 1, Problem 1.133EP

(a)

Interpretation Introduction

Interpretation:

Structural formula for all the possible monochlorinated products obtained from halogenation of ethane has to be written.

Concept Introduction:

Alkanes are linear chain saturated hydrocarbons.  The reactivity of alkanes are very less.  They can be heated for a very long time in strong acids and bases without any reaction.  Even strong reducing and strong oxidizing agents have less effect on alkanes.

Alkanes are not completely inert.  Two important reactions that alkanes undergo are combustion and halogenation.

Combustion reaction is the one where reaction occurs between substance and oxygen which proceeds with evolution of light and heat.  Due to the heat produced when alkanes are made to undergo combustion with oxygen, it is used as fuel.

Halogenation is a chemical reaction between a substance and halogen.  The product of halogenation reaction is that one or more halogens are incorporated into molecules of the substance.  Halogenation of hydrocarbon gives hydrocarbon derivatives as product where halogen atoms are substituted instead of hydrogen atoms.

Halogenation reaction of alkane is an example of substitution reaction.  This is a reaction where a part of reacting molecule replaces an atom or group of atoms in hydrocarbon or hydrocarbon derivative.

Cycloalkanes are also similar to those of alkanes.  Cycloalkanes also undergo combustion and halogenation reaction.

(a)

Expert Solution
Check Mark

Answer to Problem 1.133EP

The monochlorinated product of ethane is,

Organic And Biological Chemistry, Chapter 1, Problem 1.133EP , additional homework tip  1

Explanation of Solution

Halogenation is a chemical reaction between a substance and halogen.  The product of halogenation reaction is that one or more halogens are incorporated into molecules of the substance.  Halogenation of hydrocarbon gives hydrocarbon derivatives as product where halogen atoms are substituted instead of hydrogen atoms.

Halogenation reaction of alkane is an example of substitution reaction.  This is a reaction where a part of reacting molecule replaces an atom or group of atoms in hydrocarbon or hydrocarbon derivative.

General reaction for halogenation of alkane can be given as shown below,

    RH + X2 halogenation RX + HXalkane halogen alkyl halide hydrogen halide

The halogenation reaction takes place giving a mixture of products where the hydrogen atoms present in the alkane are substituted randomly.

Given alkane is ethane.  This has a total of two carbon atoms which are of same nature.  Only one kind of hydrogen is present in ethane.  Therefore, chlorinaton of ethane will lead to the same monochlorinated product as shown below,

Organic And Biological Chemistry, Chapter 1, Problem 1.133EP , additional homework tip  2

Conclusion

The structural formula for monochlorinated product of ethane was drawn.

(b)

Interpretation Introduction

Interpretation:

Structural formula for all the possible monochlorinated products obtained from halogenation of butane has to be written.

Concept Introduction:

Alkanes are linear chain saturated hydrocarbons.  The reactivity of alkanes are very less.  They can be heated for a very long time in strong acids and bases without any reaction.  Even strong reducing and strong oxidizing agents have less effect on alkanes.

Alkanes are not completely inert.  Two important reactions that alkanes undergo are combustion and halogenation.

Combustion reaction is the one where reaction occurs between substance and oxygen which proceeds with evolution of light and heat.  Due to the heat produced when alkanes are made to undergo combustion with oxygen, it is used as fuel.

Halogenation is a chemical reaction between a substance and halogen.  The product of halogenation reaction is that one or more halogens are incorporated into molecules of the substance.  Halogenation of hydrocarbon gives hydrocarbon derivatives as product where halogen atoms are substituted instead of hydrogen atoms.

Halogenation reaction of alkane is an example of substitution reaction.  This is a reaction where a part of reacting molecule replaces an atom or group of atoms in hydrocarbon or hydrocarbon derivative.

Cycloalkanes are also similar to those of alkanes.  Cycloalkanes also undergo combustion and halogenation reaction.

(b)

Expert Solution
Check Mark

Answer to Problem 1.133EP

The monochlorinated products of butane are,

Organic And Biological Chemistry, Chapter 1, Problem 1.133EP , additional homework tip  3

Explanation of Solution

Halogenation is a chemical reaction between a substance and halogen.  The product of halogenation reaction is that one or more halogens are incorporated into molecules of the substance.  Halogenation of hydrocarbon gives hydrocarbon derivatives as product where halogen atoms are substituted instead of hydrogen atoms.

Halogenation reaction of alkane is an example of substitution reaction.  This is a reaction where a part of reacting molecule replaces an atom or group of atoms in hydrocarbon or hydrocarbon derivative.

General reaction for halogenation of alkane can be given as shown below,

    RH + X2 halogenation RX + HXalkane halogen alkyl halide hydrogen halide

The halogenation reaction takes place giving a mixture of products where the hydrogen atoms present in the alkane are substituted randomly.

Given alkane is butane.  Two kinds of hydrogen are present in butane.  Therefore, chlorination of butane will lead to two monochlorinated products as shown below,

Organic And Biological Chemistry, Chapter 1, Problem 1.133EP , additional homework tip  4

Conclusion

The structural formula for monochlorinated products of butane was drawn.

(c)

Interpretation Introduction

Interpretation:

Structural formula for all the possible monochlorinated products obtained from halogenation of 2-methylpropane has to be written.

Concept Introduction:

Alkanes are linear chain saturated hydrocarbons.  The reactivity of alkanes are very less.  They can be heated for a very long time in strong acids and bases without any reaction.  Even strong reducing and strong oxidizing agents have less effect on alkanes.

Alkanes are not completely inert.  Two important reactions that alkanes undergo are combustion and halogenation.

Combustion reaction is the one where reaction occurs between substance and oxygen which proceeds with evolution of light and heat.  Due to the heat produced when alkanes are made to undergo combustion with oxygen, it is used as fuel.

Halogenation is a chemical reaction between a substance and halogen.  The product of halogenation reaction is that one or more halogens are incorporated into molecules of the substance.  Halogenation of hydrocarbon gives hydrocarbon derivatives as product where halogen atoms are substituted instead of hydrogen atoms.

Halogenation reaction of alkane is an example of substitution reaction.  This is a reaction where a part of reacting molecule replaces an atom or group of atoms in hydrocarbon or hydrocarbon derivative.

Cycloalkanes are also similar to those of alkanes.  Cycloalkanes also undergo combustion and halogenation reaction.

(c)

Expert Solution
Check Mark

Answer to Problem 1.133EP

The monochlorinated products of 2-methylpropane are,

Organic And Biological Chemistry, Chapter 1, Problem 1.133EP , additional homework tip  5

Explanation of Solution

Halogenation is a chemical reaction between a substance and halogen.  The product of halogenation reaction is that one or more halogens are incorporated into molecules of the substance.  Halogenation of hydrocarbon gives hydrocarbon derivatives as product where halogen atoms are substituted instead of hydrogen atoms.

Halogenation reaction of alkane is an example of substitution reaction.  This is a reaction where a part of reacting molecule replaces an atom or group of atoms in hydrocarbon or hydrocarbon derivative.

General reaction for halogenation of alkane can be given as shown below,

    RH + X2 halogenation RX + HXalkane halogen alkyl halide hydrogen halide

The halogenation reaction takes place giving a mixture of products where the hydrogen atoms present in the alkane are substituted randomly.

Given alkane is 2-methylpropane.  Two kinds of hydrogen are present in 2-methylpropane.  Therefore, chlorination of 2-methylpropane will lead to two monochlorinated products as shown below,

Organic And Biological Chemistry, Chapter 1, Problem 1.133EP , additional homework tip  6

Conclusion

The structural formula for monochlorinated products of 2-methylpropane was drawn.

(d)

Interpretation Introduction

Interpretation:

Structural formula for all the possible monochlorinated products obtained from halogenation of cyclopentane has to be written.

Concept Introduction:

Alkanes are linear chain saturated hydrocarbons.  The reactivity of alkanes are very less.  They can be heated for a very long time in strong acids and bases without any reaction.  Even strong reducing and strong oxidizing agents have less effect on alkanes.

Alkanes are not completely inert.  Two important reactions that alkanes undergo are combustion and halogenation.

Combustion reaction is the one where reaction occurs between substance and oxygen which proceeds with evolution of light and heat.  Due to the heat produced when alkanes are made to undergo combustion with oxygen, it is used as fuel.

Halogenation is a chemical reaction between a substance and halogen.  The product of halogenation reaction is that one or more halogens are incorporated into molecules of the substance.  Halogenation of hydrocarbon gives hydrocarbon derivatives as product where halogen atoms are substituted instead of hydrogen atoms.

Halogenation reaction of alkane is an example of substitution reaction.  This is a reaction where a part of reacting molecule replaces an atom or group of atoms in hydrocarbon or hydrocarbon derivative.

Cycloalkanes are also similar to those of alkanes.  Cycloalkanes also undergo combustion and halogenation reaction.

(d)

Expert Solution
Check Mark

Answer to Problem 1.133EP

The monochlorinated product of cyclopentane is,

Organic And Biological Chemistry, Chapter 1, Problem 1.133EP , additional homework tip  7

Explanation of Solution

Halogenation is a chemical reaction between a substance and halogen.  The product of halogenation reaction is that one or more halogens are incorporated into molecules of the substance.  Halogenation of hydrocarbon gives hydrocarbon derivatives as product where halogen atoms are substituted instead of hydrogen atoms.

Halogenation reaction of alkane is an example of substitution reaction.  This is a reaction where a part of reacting molecule replaces an atom or group of atoms in hydrocarbon or hydrocarbon derivative.

General reaction for halogenation of alkane can be given as shown below,

    RH + X2 halogenation RX + HXalkane halogen alkyl halide hydrogen halide

The halogenation reaction takes place giving a mixture of products where the hydrogen atoms present in the alkane are substituted randomly.

Given cycloalkane is cyclopentane.  Only one kind of hydrogen is present in cyclopentane.  Therefore, chlorinaton of cyclopentane will lead to the same monochlorinated product as shown below,

Organic And Biological Chemistry, Chapter 1, Problem 1.133EP , additional homework tip  8

Conclusion

The structural formula for monochlorinated product of cyclopentane was drawn.

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Chapter 1 Solutions

Organic And Biological Chemistry

Ch. 1.5 - Prob. 2QQCh. 1.5 - Prob. 3QQCh. 1.6 - Prob. 1QQCh. 1.6 - Prob. 2QQCh. 1.6 - Prob. 3QQCh. 1.6 - Prob. 4QQCh. 1.7 - Prob. 1QQCh. 1.7 - Prob. 2QQCh. 1.8 - Prob. 1QQCh. 1.8 - Prob. 2QQCh. 1.8 - Prob. 3QQCh. 1.8 - Prob. 4QQCh. 1.8 - Prob. 5QQCh. 1.8 - Prob. 6QQCh. 1.8 - Prob. 7QQCh. 1.9 - Prob. 1QQCh. 1.9 - Prob. 2QQCh. 1.10 - Prob. 1QQCh. 1.10 - Prob. 2QQCh. 1.11 - Prob. 1QQCh. 1.11 - Prob. 2QQCh. 1.11 - Prob. 3QQCh. 1.12 - Prob. 1QQCh. 1.12 - Prob. 2QQCh. 1.12 - Prob. 3QQCh. 1.13 - Prob. 1QQCh. 1.13 - Prob. 2QQCh. 1.13 - Prob. 3QQCh. 1.14 - Prob. 1QQCh. 1.14 - Prob. 2QQCh. 1.14 - Prob. 3QQCh. 1.15 - Prob. 1QQCh. 1.15 - Prob. 2QQCh. 1.16 - Prob. 1QQCh. 1.16 - Prob. 2QQCh. 1.16 - Prob. 3QQCh. 1.17 - Prob. 1QQCh. 1.17 - Prob. 2QQCh. 1.17 - Prob. 3QQCh. 1.17 - Prob. 4QQCh. 1.18 - Prob. 1QQCh. 1.18 - Prob. 2QQCh. 1.18 - Prob. 3QQCh. 1.18 - Prob. 4QQCh. 1 - Prob. 1.1EPCh. 1 - Prob. 1.2EPCh. 1 - Prob. 1.3EPCh. 1 - Prob. 1.4EPCh. 1 - Indicate whether each of the following situations...Ch. 1 - Indicate whether each of the following situations...Ch. 1 - Prob. 1.7EPCh. 1 - Prob. 1.8EPCh. 1 - What is the difference between a saturated...Ch. 1 - What structural feature is present in an...Ch. 1 - Prob. 1.11EPCh. 1 - Prob. 1.12EPCh. 1 - Prob. 1.13EPCh. 1 - Prob. 1.14EPCh. 1 - Prob. 1.15EPCh. 1 - Prob. 1.16EPCh. 1 - Convert the expanded structural formulas in...Ch. 1 - Prob. 1.18EPCh. 1 - Prob. 1.19EPCh. 1 - Prob. 1.20EPCh. 1 - Prob. 1.21EPCh. 1 - Prob. 1.22EPCh. 1 - Prob. 1.23EPCh. 1 - Prob. 1.24EPCh. 1 - Prob. 1.25EPCh. 1 - Prob. 1.26EPCh. 1 - Indicate whether each of the following would be...Ch. 1 - Indicate whether each of the following would be...Ch. 1 - Prob. 1.29EPCh. 1 - Explain why two different straight-chain alkanes...Ch. 1 - With the help of Table 12-1, indicate how many...Ch. 1 - Prob. 1.32EPCh. 1 - How many of the numerous eight-carbon alkane...Ch. 1 - How many of the numerous seven-carbon alkane...Ch. 1 - For each of the following pairs of structures,...Ch. 1 - For each of the following pairs of structures,...Ch. 1 - Convert each of the following linear condensed...Ch. 1 - Prob. 1.38EPCh. 1 - Prob. 1.39EPCh. 1 - Prob. 1.40EPCh. 1 - Prob. 1.41EPCh. 1 - Prob. 1.42EPCh. 1 - Prob. 1.43EPCh. 1 - Prob. 1.44EPCh. 1 - Prob. 1.45EPCh. 1 - Prob. 1.46EPCh. 1 - Prob. 1.47EPCh. 1 - Prob. 1.48EPCh. 1 - Prob. 1.49EPCh. 1 - Prob. 1.50EPCh. 1 - Prob. 1.51EPCh. 1 - Prob. 1.52EPCh. 1 - Draw a condensed structural formula for each of...Ch. 1 - Draw a condensed structural formula for each of...Ch. 1 - Prob. 1.55EPCh. 1 - For each of the alkanes in Problem 12-54,...Ch. 1 - Explain why the name given for each of the...Ch. 1 - Prob. 1.58EPCh. 1 - Indicate whether or not the two alkanes in each of...Ch. 1 - Prob. 1.60EPCh. 1 - How many of the 18 C8 alkane constitutional...Ch. 1 - How many of the nine C7 alkane constitutional...Ch. 1 - Prob. 1.63EPCh. 1 - Prob. 1.64EPCh. 1 - Prob. 1.65EPCh. 1 - Prob. 1.66EPCh. 1 - Do the line-angle structural formulas in each of...Ch. 1 - Do the line-angle structural formulas in each of...Ch. 1 - 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Assign an IUPAC name to each of the following...Ch. 1 - Assign an IUPAC name to each of the following...Ch. 1 - Prob. 1.103EPCh. 1 - Prob. 1.104EPCh. 1 - Prob. 1.105EPCh. 1 - Prob. 1.106EPCh. 1 - What is the molecular formula for each of the...Ch. 1 - Prob. 1.108EPCh. 1 - Prob. 1.109EPCh. 1 - Prob. 1.110EPCh. 1 - Prob. 1.111EPCh. 1 - Prob. 1.112EPCh. 1 - Determine whether cistrans isomerism is possible...Ch. 1 - Prob. 1.114EPCh. 1 - Prob. 1.115EPCh. 1 - Prob. 1.116EPCh. 1 - Prob. 1.117EPCh. 1 - Indicate whether the members of each of the...Ch. 1 - Prob. 1.119EPCh. 1 - Prob. 1.120EPCh. 1 - Prob. 1.121EPCh. 1 - Prob. 1.122EPCh. 1 - Prob. 1.123EPCh. 1 - Which member in each of the following pairs of...Ch. 1 - Prob. 1.125EPCh. 1 - Prob. 1.126EPCh. 1 - Answer the following questions about the...Ch. 1 - Prob. 1.128EPCh. 1 - Prob. 1.129EPCh. 1 - Prob. 1.130EPCh. 1 - Write molecular formulas for all the possible...Ch. 1 - Write molecular formulas for all the possible...Ch. 1 - Prob. 1.133EPCh. 1 - Prob. 1.134EPCh. 1 - Prob. 1.135EPCh. 1 - Assign an IUPAC name to each of the following...Ch. 1 - Prob. 1.137EPCh. 1 - Prob. 1.138EPCh. 1 - Prob. 1.139EPCh. 1 - Prob. 1.140EPCh. 1 - Prob. 1.141EPCh. 1 - Prob. 1.142EPCh. 1 - Prob. 1.143EPCh. 1 - Prob. 1.144EPCh. 1 - Prob. 1.145EPCh. 1 - Prob. 1.146EPCh. 1 - Give the IUPAC names for the eight isomeric...Ch. 1 - Prob. 1.148EP
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