Chapter ISG, Problem 5.4.1.6P

To determine

To explain why or why not.

Answer to Problem 5.4.1.6P

Yes agree.

Explanation of Solution

Given information:

If k is a real number then the solution set of compound in equality xk is a set of all real numbers.

Inequality are,

xk

Calculation:

Let $k=0$ , substituting the values,

  $x<0$

Or

  $x>0$

Solution set: {x|x<0 or x>0}

The graph of solution set is given below

For x<0,

  

Interval notation is,

  

For x>0,

  

Interval notation is,

  

For $x<0ORx>0$

  

Interval notation is,

  

Real numbers includes all rational numbers, such as integers and fractions, and all the irrational numbers such as

In solution set x<0 are numbers which are real numbers

In solution set x>0 are numbers which are real numbers

Hence, yes agree.