Chapter ISG, Problem 9.1.1P

To determine

To calculate the intercept, min & max of given function $y=x^2+x+3$

Answer to Problem 9.1.1P

Intercept: y-intercept = 3

Max or Min: Min at $x=0,y=3$

Explanation of Solution

Given Information: $y=x^2+x+3$

Formula Used: Graphing Utility

Calculation:

For such equations, a graphing utility can often be used to investigate possible solutions. When a graphing utility is used to solve an equation, usually approximate solutions are obtained.

  $y=x^2+x+3$

Put the value of x in y, get:

  $\begin{array}{cc}x& y\\ -3& 9\\ -2& 5\\ -1& 3\\ 0& 3\\ 1& 5\\ 2& 9\end{array}$

  

Hence,

Intercept: y-intercept = 3

Max or Min: Min at $x=0,y=3$