Chapter ISG, Problem 1.5.3P

To determine

To find better set of accuracy

Answer to Problem 1.5.3P

Both sets are equally accurate.

Explanation of Solution

Given information:

Set A	Set B
17.3 g	17.1 g
18.0 g	17.8 g
17.9 g	18.6 g
17.6 g	17.3 g

Accurate weight is 17.65 grams

Calculation:

Set A,

Average of the values= $\frac{17.3+18+17.9+17.6}{4}$

Solving,

Average= $\frac{70.8}{4}$

Dividing by 4,

Average=17.7

Hence, average of set A is 17.7 grams

Set B,

Average of the values= $\frac{17.1+17.8+18.6+17.3}{4}$

Solving,

Average= $\frac{70.8}{4}$

Dividing by 4,

Average=17.7

Hence, average of set B is 17.7 grams.

Comparing both sets, both sets are equally accurate.