Chapter ISG, Problem 6.2.7P

a.

To determine

To draw and label diagram.

Explanation of Solution

Given information:

A rectangle with diagonal walkaway.

  

The length of rectangle is 10 feet longer than twice the breadth of rectangle.

b.

To determine

Write and solve the equation.

Answer to Problem 6.2.7P

Length is 90 feet and width is 40 feet.

Explanation of Solution

Given information:

Perimeter of triangle=260 feet.

Calculation:

Let length of triangle= x and breadth be y

According to question,

  $x=10+2y$  -(1)

Perimeter of rectangle= $2(length+breadth)$

Substituting value,

Perimeter= $2(x+y)$

Putting value of x in perimeter,

Perimeter= $2(10+2y+y)$

Solving equation,

Perimeter= $20+6y$

Putting value of perimeter,

  $6y=240$

Dividing equation,

  $y=40$

Put value of y in (1)

  $x=10+2(40)$

Solving,

  $x=10+80$

Hence, $x=90$

Length is 90 feet and width is 40 feet.

c.

To determine

To find area of garden

Answer to Problem 6.2.7P

Area of garden is $3600fee{t}^2$

Explanation of Solution

Given information:

A rectangle of perimeter 260 feet.

Formula used:

Area of triangle= $length\times breadth$

Calculation:

Length of rectangle=90feet

Breadth of rectangle=40feet

Substituting values in area,

Area= $90\times 40$

Solving,

Area= $3600fee{t}^2$

Hence, area of garden is $3600fee{t}^2$