Chapter ISG, Problem 1.5STP

To determine

When the expression is completely simplified then find the cofficient of $x^2$ term $2\left(x-1\right)+4x^2+2\left(x^2-1\right)$

Answer to Problem 1.5STP

  $3$

Explanation of Solution

Given information:

  $2\left(x-1\right)+4x^2+2\left(x^2-1\right)$

Formula used:

Simplification of equation

Calculation:

  $2\left(x-1\right)+4x^2+2\left(x^2-1\right)$

Now assume the equation is equal to 0 then

  $2\left(x-1\right)+4x^2+2\left(x^2-1\right)=0$

Multiply the 2 in the both bracket

  $2x-2+4x^2+2x^2-2=0$

Add the $x^2$ term

  $2x-2+6x^2-2=0$

Arrange the expression

  $6x^2+2x-2-2=0$

By subtracting the 2 and 2

  $6x^2+2x-4=0$

Divide by 2 both side

  $3x^2+x-2=0$

Hence, $x^2$ cofficient is $3$