Chapter ISG, Problem 9.7.8P

To determine

To find solution of system of equation algebraically.

Answer to Problem 9.7.8P

  $(0,1)$

  $(4,5)$

Explanation of Solution

Given information:

  $y=x^2-3x+1$

  $y=x+1$

Calculation:

  $y=x^2-3x+\mathrm{1.........}(1)$

  $y=x+\mathrm{1............}(2)$

put value of y from equation(2) in (1)

  $x+1=x^2-3x+1$

On solving,

  $0=x^2-3x+1-x-1$

On solving,

  $x^2-4x=0$

On solving,

  $x(x-4)=0$

On solving,

  $x=0$

  $(x-4)=0$

On solving,

  $x=0$

  $x=4$

If $x=0$

  $y=0+1$

On solving,

  $y=1$

If $x=4$

  $y=4+1$

On solving,

  $y=5$