(a)
Interpretation: If there are two bonding pairs and two non-bonding pairs of electrons of a central atom in a molecule, its shape needs to be predicted.
Concept Introduction: VSEPR theory is used to predict the molecular shape with the help of electron pairs around the central atoms of the molecule. It is based on the assumption that the shape of the molecule is such that there is minimum electronic repulsion between the valence shell and the atom.
(a)
Explanation of Solution
The total number of pairs of electrons will be the sum of bonding and non-bonding pair of electrons. Thus, it will be 4 for the given molecule. For 4 electrons, the hybridization will be
(b)
Interpretation: If there are four bonding pairs and zero non-bonding pairs of electrons of a central atom in the molecule, its shape needs to be predicted.
Concept Introduction: VSEPR theory is used to predict the molecular shape with the help of electron pairs around the central atoms of the molecule. It is based on the assumption that the shape of the molecule is such that there is minimum electronic repulsion between the valence shell and the atom.
(b)
Explanation of Solution
The total number of pairs of electrons will be the sum of bonding and non-bonding pair of electrons. Thus, it will be 4 for the given molecule. For 4 electrons, the hybridization will be
(c)
Interpretation: If there are three bonding pairs and one non-bonding pair of electrons of a central atom in the molecule, its shape needs to be predicted.
Concept Introduction: VSEPR theory is used to predict the molecular shape with the help of electron pairs around the central atoms of the molecule. It is based on the assumption that the shape of the molecule is such that there is minimum electronic repulsion between the valence shell and the atom.
(c)
Explanation of Solution
The total number of pairs of electrons will be the sum of bonding and non-bonding pair of electrons. Thus, it will be 4 for the given molecule. For 4 electrons, the hybridization will be
Chapter 8 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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- Please Don't used hand raitingarrow_forward7. For the following structure: ← Draw structure as is - NO BI H H Fisher projections (a) Assign R/S configuration at all chiral centers (show all work). Label the chiral centers with an asterisk (*). (b) Draw an enantiomer and diastereomer of the above structure and assign R/S configuration at all chiral centers (again, show all work). (c) On the basis of the R/S system, justify your designation of the structures as being enantiomeric or diastereomeric to the original structure.arrow_forwardDon't used Ai solutionarrow_forward
- 1. For the following reactions, predict the major product. Show stereochemistry where appropriate. неу b) 7 HBr XV ROOR H₂504 c) N/ H20 H+2 d) ~ Pt c) f. MCPBA -> сна сла (solvent) (1)BH 3-THE (3) Надрон B177 H20 9)arrow_forwardFor the following reactions, predict the major product. Show stereochemistry where approarrow_forwardHow is Talu home quer in Org. Chemistry propose a 3-butanal prepared from ketone? complete reaction for this, (to start from the guignand Meagent. ②what pocubble products could be produced from the reaction of : CA₂ CH₂ CH₂ dil H.504 A CH3 1 OBCH₂OH Naz Cr₂ 07 12504 NazCD 4 CH3CH2 07 AzS04 H3C H3C CH3-C - C - Atz но но + H, CH3 07 > ⑦Colts C614501 + (215) 504 кон 4arrow_forward
- Rank the following compounds most to least acidic: a) О OH 요애 OH .OH flow flow О F F F F OH F b) Ha EN-Ha CI Ha F F CI Haarrow_forwarda) b) Provide arrows to show the mechanisms and then predict the products of the following acid base reaction. Use pKas to determine which way the reaction will favor (Hint: the lower pka acid will want to dissociate) Дон OH Ha OH NH2 c) H H-O-Harrow_forwardMATERIALS. Differentiate between interstitial position and reticular position.arrow_forward
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