Genetic Analysis: An Integrated Approach (3rd Edition)
Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 8, Problem 7P

The DNA sequences shown below are from the promoter regions of six bacterial genes. In each case, the last nucleotide in the sequence (highlighted in blue) is the

+1 nucleotide that initiates transcription.

a. Examine these sequences and identify the Pribnow box sequence at approximately -10 for each promoter.

b. Determine the consensus sequence for the Pribnow box from these sequences

Chapter 8, Problem 7P, The DNA sequences shown below are from the promoter regions of six bacterial genes. In each case,

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Shown below is a schematic diagram illustrating a very short gene with 5000 bp region of an unknown Schizosaccharomyces pombe genome. (Note: Transcription starts at Transcription Start Site (TSS).) TSS 5. 3' 3 +1 (i) Name the specific regions that can be recognized by Transcription Factor IID (TF ID) and indicate the locations in the diagram above. (ii) List the mechanistic steps that can trigger the initiation of transcription by Transcription Factor IIH (TF IIH).
Consider a gene being transcribed at a constant rate k1 and being degraded with first order kinetics with a rate constant of k2. a. Write the chemical reaction for transcriptionb. Derive the instantaneous concentration of the mRNA within the cell. Explicitly list all assumptions.
Comparing the -10 regions of two E. coli promoters which have identical -35 regions revealed the sequence TATAAT for the first and GATACT for the second one.  Why does the first promoter cause a higher transcription rate than the second one? a. The transcription rate from the first promoter will be higher, because RNA polymerase will bind TATAAT with a higher affinity than GATACT.   b. It will be higher, because formation of the open promoter complex is more easily achieved with TATAAT than with GATACT.   c. It will be higher, because TATAAT of the -10 region is transcribed into UAUAAU, which forms fewer hydrogen bonds with the template strand than GAUACU.   d. a and b, but not c   e. a, b, and c

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Genetic Analysis: An Integrated Approach (3rd Edition)

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