Loose-leaf for Operations Management (The Mcgraw-hill Series in Operations and Decision Sciences)
Loose-leaf for Operations Management (The Mcgraw-hill Series in Operations and Decision Sciences)
12th Edition
ISBN: 9781259580093
Author: William J Stevenson
Publisher: McGraw-Hill Education
Question
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Chapter 7.S, Problem 3P

a)

Summary Introduction

To determine: The number of days for first 10 installations.

Introduction: Learning curve is referred as the cost curve, experience curve, efficiency curve or productivity curve. The leaving curve gives information about the cost, efficiency, productivity and performance of an organization.

a)

Expert Solution
Check Mark

Answer to Problem 3P

The number of days for first 10 installations is 56.93 days.

Explanation of Solution

Given information:

Initial unitT1=8daysLearningcurve=85%

Formula:

Tn=T1×Unitfactor

Calculation of number of days for first 10 installations:

At 85% learning curve, and 10 unit number, the unit factor is 7.116 (using learning curve coefficient table)

T110=8×7.116=56.93days (1)

The times for all 10 installations are calculated by multiplying first unit of 8 with the unit factor 7.116 which yields 56.93 days.

Hence, the number of days for first 10 installations is 56.93 days.

b)

Summary Introduction

To determine: The number of days for second 10 installations.

Introduction: Learning curve is referred as the cost curve, experience curve, efficiency curve or productivity curve. The leaving curve gives information about the cost, efficiency, productivity and performance of an organization.

b)

Expert Solution
Check Mark

Answer to Problem 3P

The number of days for second 10 installations is 42.29 days.

Explanation of Solution

Given information:

Initial unitT1=8daysLearningcurve=85%

Formula:

Tn=T1×Unitfactor

Calculation of number of days for second 10 installations:

To calculate the number of days for second 10 installations which is from 11 to 20, the numbers of days of installations for 1 to 20 have to be calculated and then it has to be subtracted from number of days of installations of 1 to 10.

Number of installation of first 20 units:

At 85% learning curve, and 20 unit number, the unit factor is 12.402 (using learning curve coefficient table)

T120=8×12.402=99.22days

The times for all 20 installations are calculated by multiplying first unit of 8 with the unit factor 12.402 which yields 99.22 days.

From the computed number of days, subtract the number of needed for first 10 installations,

Timefor11-20installations=(Timefor1-20installations-Timefor1-10installations)=99.22-56.93=42.29days

Hence, the number of days for second 10 installations is 42.29 days.

c)

Summary Introduction

To determine: The number of days for last 10 installations.

Introduction: Learning curve is referred as the cost curve, experience curve, efficiency curve or productivity curve. The leaving curve gives information about the cost, efficiency, productivity and performance of an organization.

c)

Expert Solution
Check Mark

Answer to Problem 3P

The number of days for last 10 installations is 37.51 days.

Explanation of Solution

Given information:

Initial unitT1=8daysLearningcurve=85%

Formula:

Tn=T1×Unitfactor

Calculation of number of days for last 10 installations:

To calculate the number of days for last10 installations which is from 21 to 30, the numbers of days of installations for 1 to 30 have to be calculated and then it has to be subtracted from number of days of installations of 1 to 20.

Number of installation of first 30 units:

At 85% learning curve, and 30 unit number, the unit factor is 17.091 (using learning curve coefficient table)

T130=8×17.091=136.73days

The times for all 30 installations are calculated by multiplying first unit of 8 with the unit factor 17.091 which yields 136.73 days.

From the computed number of days, subtract the number of needed for first 20 installations,

Timefor21-30installations=(Timefor1-30installations-Timefor1-20installations)=136.73-99.22=37.51days

Hence, the number of days for final 10 installations is 37.51 days.

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Students have asked these similar questions
A contractor intends to bid on a job installing 30 airport security systems. Because this will be a new line of work for the contractor, he believes there will be a learning effect for the job. After reviewing time records from a similar type of activity, the contractor is convinced that an 85 percent curve is appropriate. He estimates that the first job will take his crew eight days to install. How many days should the contractor budget fora. The first 10 installations?b. The second 10 installations?c. The final 10 installations?
The owner of Touchdown Sports Bar wants to develop a time standard for the task of mixing a specialty cocktail. In a preliminary study, he observed one of his bartenders perform this task seven times with an average of 90 seconds and a standard deviation of five seconds. What is the standard time for this task if the bartender worked at a 20 percent faster pace than is average, and an allowance of 10 percent of job time is used?
The owner of mid-sized cat motel wants to develop a time standard for the task of cleaning a cat cage. In a preliminary study, she observed one of her workers perform this task six times, with the following results: Observation 1 2 3 4 5 6 Time(Seconds) 99 87 90 81 93 90 What is the standard time for this task if the employee worked at a 50 percent faster pace than average, and an allowance of 10 percent of the workday is used?

Chapter 7 Solutions

Loose-leaf for Operations Management (The Mcgraw-hill Series in Operations and Decision Sciences)

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