For the following exercises, without using Stokes’ theorem, calculate directly both the flux of curl F ⋅ N over the given surface and the circulation integral around its boundary, assuming all boundaries are oriented clockwise as viewed from above. 326. F ( x , y , z ) = y 2 i + z 2 j + x 2 k ; S is the first-octant portion of plane x + y + z = 1 .
For the following exercises, without using Stokes’ theorem, calculate directly both the flux of curl F ⋅ N over the given surface and the circulation integral around its boundary, assuming all boundaries are oriented clockwise as viewed from above. 326. F ( x , y , z ) = y 2 i + z 2 j + x 2 k ; S is the first-octant portion of plane x + y + z = 1 .
For the following exercises, without using Stokes’ theorem, calculate directly both the flux of curl
F
⋅
N
over the given surface and the circulation integral around its boundary, assuming all boundaries are oriented clockwise as viewed from above.
326.
F
(
x
,
y
,
z
)
=
y
2
i
+
z
2
j
+
x
2
k
;
S
is the first-octant portion of plane
x
+
y
+
z
=
1
.
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
Integrate V × F, F = (3y, −xz, —yz²) over the portion of the surface
2z = x² + y² below the plane z = 2, by using Stokes' Theorem
Let F =
Use Stokes's Theorem to show that 0 = |J curl(F) - dS where F(r, y, z) = (z, 2ry, x + y) and S
is the surface of a glass oriented outwards whose open cap is a circle with equation r² + (z – 2)² = 9.
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