Explanation Concept: The best way to describe the reason why the sky diver lost control of the pumpkin is through drawing the free-body diagram. Given: In 1987, as a Halloween stunt, two sky divers passed a pumpkin back and forth between them while they were in free fall just west of Chicago. The stunt was great fun until the last sky diver with the pumpkin opened his parachute. The pumpkin broke free from his grip, plummeted about 0.5 km, ripped through the roof of a house, slammed into the kitchen floor, and splattered all over the newly remodelled kitchen. F is the applied force, F → N is the normal force on the pumpkin by the skydiver, f is the force of friction , and mg is the force of gravity

10th Edition

ISBN: 9781118230725

Author: David Halliday, Robert Resnick, Jearl Walker

Publisher: Wiley, John & Sons, Incorporated

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Chapter 6, Problem 10Q

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To explain:

The reason why the sky diver lost control of the pumpkin (from the skydiver’s point of view and the pumpkin’s point of view).

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Chapter 6, Problem 9Q

Chapter 6, Problem 11Q

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Chapter 6 Solutions

Fundamentals of Physics Extended

Ch. 6 - In Fig. 6-12, if the box is stationary and the...Ch. 6 - Prob. 2Q Ch. 6 - In Fig. 6-13, horizontal force F1 of magnitude 10...Ch. 6 - In three experiments, three different horizontal...Ch. 6 - If you press an apple crate against a wall so hard...Ch. 6 - In Fig. 6-14, a block of mass m is held stationary...Ch. 6 - Reconsider Question 6 but with the force F now...Ch. 6 - In Fig. 6-15, a horizontal force of 100 N is to be...Ch. 6 - Prob. 9Q Ch. 6 - Prob. 10Q

Ch. 6 - A person riding a Ferris wheel moves through...Ch. 6 - During a routine flight in 1956, test pilot Tom...Ch. 6 - A box is on a ramp that is at angle to the...Ch. 6 - The floor of a railroad flatcar is loaded with...Ch. 6 - In a pickup game of dorm shuffleboard, students...Ch. 6 - SSM WWW A bedroom bureau with a mass of 45 kg,...Ch. 6 - A slide-loving pig slides down a certain 35 slide...Ch. 6 - GO A 2.5 kg block is initially at rest on a...Ch. 6 - A baseball player with mass m 79 kg, sliding into...Ch. 6 - SSM ILW A person pushes horizontally with a force...Ch. 6 - The mysterious sliding stones. Along the remote...Ch. 6 - GO A 3.5 kg block is pushed along a horizontal...Ch. 6 - Figure 6-20 shows an initially stationary block of...Ch. 6 - SSM A 68 kg crate is dragged across a floor by...Ch. 6 - In about 1915, Henry Sincosky of Philadelphia...Ch. 6 - A worker pushes horizontally on a 35 kg crate with...Ch. 6 - Figure 6-22 shows the cross section of a road cut...Ch. 6 - The coefficient of static friction between Teflon...Ch. 6 - A loaded penguin sled weighing 80 N rests on a...Ch. 6 - In Fig. 6-24, a force P acts on a block weighing...Ch. 6 - GO You testify as an expert witness in a case...Ch. 6 - A 12 N horizontal force F pushes a block weighing...Ch. 6 - GO In Fig. 6-27, a box of Cheerios mass mC = 1.0...Ch. 6 - An initially stationary box of sand is to be...Ch. 6 - GO In Fig. 6-23, a sled is held on an inclined...Ch. 6 - When the three blocks in Fig. 6-29 are released...Ch. 6 - A 4.10 kg block is pushed along a floor by a...Ch. 6 - SSM WWW Block B in Fig. 6-31 weighs 711 N. The...Ch. 6 - GO Figure 6-32 shows three crates being pushed...Ch. 6 - GO Body A in Fig. 6-33 weighs 102 N, and body B...Ch. 6 - In Fig. 6-33, two blocks are connected over a...Ch. 6 - GO In Fig. 6-34, blocks A and B have weights of 44...Ch. 6 - A toy chest and its contents have a combined...Ch. 6 - SSM Two blocks, of weights 3.6 N and 7.2 N, are...Ch. 6 - GO A block is pushed across a floor by a constant...Ch. 6 - SSM A 1000 kg boat is traveling at 90 km/h when...Ch. 6 - GO In Fig. 6-37, a slab of mass m1= 40 kg rests on...Ch. 6 - ILW The two blocks m = 16 kg and M = 88 kg in Fig....Ch. 6 - The terminal speed of a sky diver is 160 km/h in...Ch. 6 - Continuation of Problem 8. Now assume that Eq....Ch. 6 - Assume Eq. 6-14 gives the drag force on a pilot...Ch. 6 - Calculate the ratio of the drag force on a jet...Ch. 6 - In downhill speed skiing a skier is retarded by...Ch. 6 - A cat dozes on a stationary merry-go-round in an...Ch. 6 - Suppose the coefficient of static friction between...Ch. 6 - ILW What is the smallest radius of an unbanked...Ch. 6 - During an Olympic bobsled run, the Jamaican team...Ch. 6 - SSM ILW A student of weight 667 N rides a steadily...Ch. 6 - A police officer in hot pursuit drives her car...Ch. 6 - A circular-motion addict of mass 80 kg rides a...Ch. 6 - A roller-coaster car at an amusement park has a...Ch. 6 - GO In Fig. 6-39, a car is driven at constant speed...Ch. 6 - An 85.0 kg passenger is made to move along a...Ch. 6 - SSM WWW An airplane is flying in a horizontal...Ch. 6 - An amusement park ride consists of a car moving in...Ch. 6 - An old streetcar rounds a flat corner of radius...Ch. 6 - In designing circular rides for amusement parks,...Ch. 6 - A bolt is threaded onto one end of a thin...Ch. 6 - GO A banked circular highway curve is designed for...Ch. 6 - GO A puck of mass m = 1.50 kg slides in a circle...Ch. 6 - Brake or turn? Figure 6- 44 depicts an overhead...Ch. 6 - SSM ILW In Fig. 6-45, a 1.34 kg ball is connected...Ch. 6 - GO In Fig. 6-46, a box of ant aunts total mass m1...Ch. 6 - SSM A block of mass mt = 4.0 kg is put on top of a...Ch. 6 - A 5.00 kg stone is rubbed across the horizontal...Ch. 6 - In Fig. 6-49, a 49 kg rock climber is climbing a...Ch. 6 - A high-speed railway car goes around a flat,...Ch. 6 - Continuation of Problems 8 and 37. Another...Ch. 6 - GO In Fig. 6-50, block 1 of mass m1 = 2.0 kg and...Ch. 6 - In Fig. 6-51, a crate slides down an inclined...Ch. 6 - Engineering a highway curve. If a car goes through...Ch. 6 - A student, crazed by final exams, uses a force P...Ch. 6 - GO Figure 6-53 shows a conical pendulum, in which...Ch. 6 - An 8.00 kg block of steel is at rest on a...Ch. 6 - A box of canned goods slides down a ramp from...Ch. 6 - In Fig. 6-54, the coefficient of kinetic friction...Ch. 6 - A 110 g hockey puck sent sliding over ice is...Ch. 6 - A locomotive accelerates a 25-car train along a...Ch. 6 - A house is built on the top of a hill with a...Ch. 6 - What is the terminal speed of a 6.00 kg spherical...Ch. 6 - A student wants to determine the coefficients of...Ch. 6 - SSM Block A in Fig. 6-56 has mass mA = 4.0 kg, and...Ch. 6 - Calculate the magnitude of the drag force on a...Ch. 6 - SSM A bicyclist travels in a circle of radius 25.0...Ch. 6 - In Fig. 6-57, a stuntman drives a car without...Ch. 6 - You must push a crate across a floor to a docking...Ch. 6 - In Fig. 6-58, force F is applied to a crate of...Ch. 6 - In the early afternoon, a car is parked on a...Ch. 6 - A sling-thrower puts a stone 0.250 kg in the...Ch. 6 - SSM A car weighing 10.7 kN and traveling at 13.4...Ch. 6 - In Fig. 6-59, block 1 of mass m1 = 2.0 kg and...Ch. 6 - SSM A filing cabinet weighing 556 N rests on the...Ch. 6 - In Fig. 6-60, a block weighing 22 N is held at...Ch. 6 - Prob. 91P Ch. 6 - A circular curve of highway is designed for...Ch. 6 - A 1.5 kg box is initially at rest on a horizontal...Ch. 6 - A child weighing 140 N sits at rest at the top of...Ch. 6 - In Fig. 6-61 a fastidious worker pushes directly...Ch. 6 - A child places a picnic basket on the outer rim of...Ch. 6 - SSM A warehouse worker exerts a constant...Ch. 6 - In Fig. 6-62, a 5.0 kg block is sent sliding up a...Ch. 6 - An 11 kg block of steel is at rest on a horizontal...Ch. 6 - A ski that is placed on snow will stick to the...Ch. 6 - Playing near a road construction site, a child...Ch. 6 - A 100 N force, directed at an angle above a...Ch. 6 - A certain string can withstand a maximum tension...Ch. 6 - A four-person bobsled total mass = 630 kg comes...Ch. 6 - As a 40 N block slides down a plane that is...

Knowledge Booster

The reason why the sky diver lost control of the pumpkin (from the skydiver’s point of view and the pumpkin’s point of view).

Solution Summary: The author explains the reason why the sky diver lost control of the pumpkin by drawing the free-body diagram.

To explain: The reason why the sky diver lost control of the pumpkin (from the skydiver’s point of view and the pumpkin’s point of view).

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Chapter 6 Solutions

To explain:

The reason why the sky diver lost control of the pumpkin (from the skydiver’s point of view and the pumpkin’s point of view).