Fundamentals of Physics Extended
10th Edition
ISBN: 9781118230725
Author: David Halliday, Robert Resnick, Jearl Walker
Publisher: Wiley, John & Sons, Incorporated
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Chapter 39, Problem 31P
To determine
To find:
Ratio of the shortest wavelength of the Balmer series to that of the Lyman series.
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The shortest wavelength
of the Lyman series is
equal to RH RH/21/RH
2/ (3RH)
What is the ratio of the shortest wavelength of the Balmer series to the shortest wavelength of the Lyman series?
The ratio of wavelengths of the last line of Balmer
series and the last line of Lyman series is
(b) 4
(a) 1
(c) 0.5
(d) 2
Chapter 39 Solutions
Fundamentals of Physics Extended
Ch. 39 - Prob. 1QCh. 39 - Prob. 2QCh. 39 - Prob. 3QCh. 39 - Prob. 4QCh. 39 - Prob. 5QCh. 39 - Prob. 6QCh. 39 - Prob. 7QCh. 39 - Prob. 8QCh. 39 - Prob. 9QCh. 39 - Prob. 10Q
Ch. 39 - Prob. 11QCh. 39 - Prob. 12QCh. 39 - Prob. 13QCh. 39 - Prob. 14QCh. 39 - Prob. 15QCh. 39 - Prob. 1PCh. 39 - Prob. 2PCh. 39 - Prob. 3PCh. 39 - Prob. 4PCh. 39 - Prob. 5PCh. 39 - Prob. 6PCh. 39 - Prob. 7PCh. 39 - Prob. 8PCh. 39 - Prob. 9PCh. 39 - Prob. 10PCh. 39 - Prob. 11PCh. 39 - Prob. 12PCh. 39 - Prob. 13PCh. 39 - Prob. 14PCh. 39 - Prob. 15PCh. 39 - Prob. 16PCh. 39 - Prob. 17PCh. 39 - Prob. 18PCh. 39 - Prob. 19PCh. 39 - Prob. 20PCh. 39 - Prob. 21PCh. 39 - Prob. 22PCh. 39 - Prob. 23PCh. 39 - Prob. 24PCh. 39 - Prob. 25PCh. 39 - Prob. 26PCh. 39 - Prob. 27PCh. 39 - Prob. 28PCh. 39 - Prob. 29PCh. 39 - Prob. 30PCh. 39 - Prob. 31PCh. 39 - Prob. 32PCh. 39 - Prob. 33PCh. 39 - Prob. 34PCh. 39 - Prob. 35PCh. 39 - Prob. 36PCh. 39 - Prob. 37PCh. 39 - Prob. 38PCh. 39 - Prob. 39PCh. 39 - Prob. 40PCh. 39 - Prob. 41PCh. 39 - Prob. 42PCh. 39 - Prob. 43PCh. 39 - Prob. 44PCh. 39 - Prob. 45PCh. 39 - Prob. 46PCh. 39 - Prob. 47PCh. 39 - Prob. 48PCh. 39 - Prob. 49PCh. 39 - Prob. 50PCh. 39 - Prob. 51PCh. 39 - Prob. 52PCh. 39 - Prob. 53PCh. 39 - Prob. 54PCh. 39 - Prob. 55PCh. 39 - Prob. 56PCh. 39 - Prob. 57PCh. 39 - Prob. 58PCh. 39 - Prob. 59PCh. 39 - Prob. 60PCh. 39 - Prob. 61PCh. 39 - Prob. 62PCh. 39 - Prob. 63PCh. 39 - Prob. 64PCh. 39 - A diatomic gas molcculc consistsof two atoms of...Ch. 39 - Prob. 66PCh. 39 - Prob. 67PCh. 39 - Prob. 68PCh. 39 - Prob. 69PCh. 39 - Prob. 70PCh. 39 - An old model of a hydrogen atom has the charge e...Ch. 39 - Prob. 72PCh. 39 - Prob. 73P
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- Do the Balmer series and the Lyman series overlap? Why? Why not? (Hint: calculate the shortest Balmer line and the longest Lyman line.)arrow_forwardCalculate the wavelength of the fifth line in the Lyman series and show that this line lies in the ultraviolet part of the spectrum.arrow_forwardCalculate the wavelength of the first line in the Lyman series and show that this line lies in the ultraviolet part of the spectrum.arrow_forward
- If an atom has an election in the n = 5 state with m = 3, what are the possible values of l?arrow_forward(a) If one subshell of an atom has nine electrons in it, what is the minimum value of (b) What is the spectroscopic notation for this atom, if this subshell is part of the n = 3 shell?arrow_forward(a) Using the Pauli exclusion principle and the rules relating the allowed values of the quantum numbers (n,l,ml,ms), prove that the maximum number of electrons in a subshell is 2n2. (b) In a similar manner, prove that the maximum number of electrons in a shell is 2n2.arrow_forward
- When the absorption spectrum of hydrogen at room temperature is analyzed, absorption lines for the Lyman series are found, but none are found for the Balmer series. What does this tell us about the energy state of most hydrogen atoms at room temperature?arrow_forwardIdentify the shell, subshell, and number of electrons for the following: (a) 2P3. (b)4d9. (c) 3s1. (d) 5g16.arrow_forwardThe shortest wavelength of a Lyman series equal to RH RH/2 1/RH 2/ (3RH) معدلة 11:31 صarrow_forward
- The wavelengths of the Lyman series for hydrogen are given by 1 λ = RH 1 − 1 n2 ,n = 2, 3, 4, . . . (a) Calculate the wavelengths of the first three lines in this series. nm nm nm (b) Identify the region of the electromagnetic spectrum in which these lines appear. infrared regionvisible light region x-ray regionultraviolet regiongamma ray regionarrow_forwardThe wavelengths of the Lyman series for hydrogen are given by = RH(1-2), = 2, 3, 4, ... 1/2 (a) Calculate the wavelengths of the first three lines in this series. nm nm nm (b) Identify the region of the electromagnetic spectrum in which these lines appear. O ultraviolet region O infrared region O x-ray region O visible light region O gamma ray regionarrow_forwardRatio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is:- 9 3 (1) 31 (2) 27 (3) 23 7 (4) 29arrow_forward
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