Fundamentals of Physics Extended
10th Edition
ISBN: 9781118230725
Author: David Halliday, Robert Resnick, Jearl Walker
Publisher: Wiley, John & Sons, Incorporated
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Chapter 39, Problem 67P
To determine
To find:
a) The separation energy between the lowest two energy levels for a container
b) The ratio of the thermal energy of the atoms to this energy separation
c) The temperature at which the thermal energy equals the energy separation
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(a) What is the separation in energy between the lowest two energy levels for a container 20 cm on a side containing argon atoms? Assume, for simplicity, that the argon atoms are trapped in a one-dimensional well 20 cm wide. The molar mass of argon is 39.9 g/mol. (b) At 300 K, to the nearest power of ten, what is the ratio of the thermal energy of the atoms to this energy separation? (c) At what temperature does the thermal energy equal the energy separation?
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Consider a B-G cavity chamber with equilibrium thickness copper walls. It is first filled with a mass m of air, then by the same mass of hydrogen. E=0.80 MeV. Assuming identical photo irradiations in the two cases,
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7.129 A technique called photoelectron spectroscopy is usedto measure the ionization energy of atoms. A gaseoussample is irradiated with UV light, and electrons areejected from the valence shell. The kinetic energies ofthe ejected electrons are measured. Because the energyof the UV photon and the kinetic energy of the ejectedelectron are known, we can write where ν is the frequency of the UV light, and m and uare the mass and velocity of the electron, respectively.In one experiment the kinetic energy of the ejectedelectron from potassium is found to be 5.34 × 10−19 Jusing a UV source of wavelength 162 nm. Calculate theionization energy of potassium. How can you be surethat this ionization energy corresponds to the electron inthe valence shell (i.e., the most loosely held electron)?
Chapter 39 Solutions
Fundamentals of Physics Extended
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