A Geiger-Mueller tube is a radiation detector that consists of a closed, hollow, metal cylinder (the cathode) of inner radius ra and a coaxial cylindrical wire (the anode) of radius г (see figure below) with a gas filling thespace between the electrodes. Assume that the internal diameter of a Geiger-Mueller tube is 3.00 cm and that the wire along the axis has a diameter of 0.190 mm. The dielectric strength of the gas between the central wireand the cylinder is 1.15 × 106 V/m. Use the equation 2πrlE =9into calculate the maximum potential difference that can be applied between the wire and the cylinder before breakdown occurs in the gas.VAnodeCathode

Answered: Image /qna-images/answer/cfc4e827-6040-49e4-813e-b8df740a367a.jpg

Answered: A Geiger-Mueller tube is a radiation…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: Electric Potential And Capacitance

Section: Chapter Questions

Problem 75P

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(a) Will the electric field strength between two parallel conducting plates exceed the breakdown strength of dry air, which is 3.00106 V/m, if the plates are separated by 2.00 mm and a potential difference of 5.010V is applied? (b) How close together can the plates be with this applied voltage?
(a) Will the electric field strength between two parallel conducting plates exceed the breakdown strength for air ( 3.0 106 V/m) if the plates are separated by 2.00 mm and a potential difference of 5.0 103 V is applied? (b) How close together can the plates be with this applied voltage?
A pair of capacitors with capacitances CA = 3.70 F and CB = 6.40 F are connected in a network. What is the equivalent capacitance of the pair of capacitors if they are connected a. in parallel and b. in series?
By what factor is the capacitance of a metal sphere multiplied if its volume is tripled? (a) 3 (b) 31/3 (c) 1 (d) 31/3 (e) 13
A parallel-plate capacitor has square plates of side s = 2.50 cm and plate separation d = 2.50 mm. The capacitor is charged by a battery to a charge Q = 4.00 C, after which the battery is disconnected. A porcelain dielectric ( = 6.5) is then inserted a distance y = 1.00 cm into the capacitor (Fig. P27.88). Hint: Consider the system as two capacitors connected in parallel. a. What is the effective capacitance of this capacitor? b. How much energy is stored in the capacitor? c. What are the magnitude and direction of the force exerted on the dielectric by the plates of the capacitor? Figure P27.88
A parallel-plate capacitor with an air gap has capacitance C0. It is connected to a battery with potential V0 that gives it charge Q0 and stored energy U0. After the capacitor is disconnected from the battery, a dielectric with constant = 3 is inserted into the air gap, completely filling it. In terms of the initial values, find the new capacitance C, charge Q, potential V, and stored energy U.
Why do we need to be careful about work done on the system versus work done by the system in calculations?
A parallel-plate capacitor filled with air carries a charge Q. The battery is disconnected, and a slab of material with dielectric constant = 2 is inserted between the plates. Which of the following statements is true? (a) The voltage across the capacitor decreases by a factor of 2. (b) The voltage across the capacitor is doubled. (c) The charge on the plates is doubled. (d) The charge on the plates decreases by a factor of 2. (e) The electric field is doubled.
An arrangement of capacitors is shown in Figure P27.23. a. If C = 9.70 105 F, what is the equivalent capacitance between points a and b? b. A battery with a potential difference of 12.00 V is connected to a capacitor with the equivalent capacitance. What is the energy stored by this capacitor? Figure P27.23 Problems 23 and 24.
Given the arrangement of capacitors in Figure P27.23, find an expression for the equivalent capacitance between points a and b. Figure P27.23 Problems 23 and 24.
A spherical capacitor is made up of two concentric spherical conductors. The inner sphere has positive charge +Q, and the outer sphere has negative charge Q. The radius of the inner sphere is rin, and the radius of the outer sphere is rout. Show that its capacitance is C = 40[rinrout/(rout rin)].
A parallel-plate capacitor in air has a plate separation of 1.50 cm and a plate area of 25.0 cm2. The plates are charged to a potential difference of 250 V and disconnected from the source. The capacitor is then immersed in distilled water. Assume the liquid is an insulator. Determine (a) the charge on the plates before and after immersion, (b) the capacitance and potential difference after immersion, and (c) the change in energy of the capacitor.

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