
Concept explainers
Interpretation:
The values of
Concept Introduction:
Quantum Numbers
The distribution of electron density in an atom is defined by Quantum numbers. They are derived from the mathematical solution of Schrodinger’s equaaation in the hydrogen atom. The four types of quantum numbers are the principal quantum number (
Principal Quantum Number (
The size of an orbital and the energy of an electron are specified by the principal quantum number (
Angular Momentum Quantum Number (
The shape of the atomic orbital is given by the angular momentum quantum number (
Magnetic Quantum Number (
The orientation of the orbital in space is given the magnetic quantum number (
There is one possible
There are three
There are five
There are seven
For a particular
To find: Get the values of

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Chapter 3 Solutions
Chemistry: Atoms First
- Predict the major products of this reaction: ་ ་ + H NaOH ? Δ excess Note that the second reactant is used in excess, that is, there is much more of the second reactant than the first. If there won't be any products, just check the box under the drawing area instead.arrow_forwardP A student claims the right-hand side of the reaction in the drawing area below shows the product of a Claisen condensation. • If the student is correct, complete the reaction by adding the necessary organic reactants to the left-hand side, and by adding any necessary reagents and reaction conditions above and below the arrow. • If the student is incorrect, because it's not possible to obtain this product from a Claisen condensation, check the box under the drawing area instead. those that will minimize any byproducts or competing • Note for advanced students: If you have a choice, use the most efficient reactants and reagents reactions. - ☐ ☐ : ☐ + I Х Click and drag to start drawing a structure.arrow_forwardidentify the relationship between the structures and H- OH HO H H- OH and HO H H -ОН HO H Br and Brarrow_forward
- The right-hand side of this reaction shows the product of an aldol condensation. What are the reactants missing from the left-hand side? Draw them below. ? NaOH Δ If there aren't any reactants that would lead to these products under the reaction conditions given, just check the box under the drawing area. Note for advanced students: don't worry if the reactants you propose might also make some other products under these reaction conditions. Just make sure the product above is one of the major products.arrow_forwardPlease help! I need to identify four labeled unknown bottles based off of their colors doing titration using phenlphtalein. I've included my answers, but I wanted to make sure they were correct and if not, what will be correct thank you in advance.arrow_forwardAn organic chemistry Teaching Assistant (TA) suggested in your last discussion section that there is only one major organic product of the following reaction and that this reaction builds a ring. If the TA is right, draw the product in the drawing area below. If the TA is wrong, just check the box below the drawing area. NaOH ?arrow_forward
- A student suggests that the molecule on the right can be made from a single molecule that doesn't have a ring. If the student is correct, draw the starting material below, otherwise, check the box under the drawing area. Click and drag to start drawing a structure. : ☐ + NaOH टेarrow_forwardRate = k [I]1.7303[S2O82-]0.8502, Based on your rate, write down a mechanism consistent with your results and indicate which step is the rate determining step.arrow_forward36. Give the major product(s) of each of the following reactions. Aqueous work-up steps (when necessary) have been omitted. a. CH3CH=CHCH3 b. CH3CH2CH2CCH3 H,PO₂, H₂O, A (Hint: See Section 2-2.) 1. LIAIH. (CH,CH,),O 2. H', H₂O H NaBH, CH,CH₂OH d. Br LIAIH. (CH,CH,)₂O f. CH3 NaBH, CH,CH,OH (CH3)2CH H NaBH, CH,CH₂OH Harrow_forward
- Predict the major products of this reaction: + H excess NaOH Δ ? Note that the second reactant is used in excess, that is, there is much more of the second reactant than the first. If there won't be any products, just check the box under the drawing area instead.arrow_forwardAn organic chemistry Teaching Assistant (TA) suggested in your last discussion section that there is only one major organic product of the following reaction and that this reaction builds a ring. If the TA is right, draw the product in the drawing area below. If the TA is wrong, just check the box below the drawing area. 1. NaOMe CH3O N. OCH3 ? 2. H3O+arrow_forwardComplete the reaction in the drawing area below by adding the major products to the right-hand side. If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead. Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule to represent each pair of enantiomers, using line bonds at the chiral center. + More... ☐ ☐ : ☐ + G 1. NaOMe Click and drag to start drawing a structure. 2. H +arrow_forward
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