
Interpretation:
The four quantum numbers which is applied to characterize an electron in an atom should be described.
Concept Introduction:
The electron density gives the probability of finding an electron in a particular region in an atom. An atomic orbital is the region of three-dimensional space, defined by ψ2 (the square of the wave function, ψ), where the probability of finding an electron is high. An atomic orbital can accommodate a maximum of two electrons.
A wave function for an electron in an atom is called an atomic orbital; this atomic orbital describes a region of space in which there is a high probability of finding the electron. Energy changes within an atom are the result of an electron changing from a wave pattern with one energy to a wave pattern with a different energy (usually accompanied by the absorption or emission of a photon of light).
Each electron in an atom is described by four different quantum numbers. The first three (n, l, ml) specify the particular orbital of interest, and the fourth (ms) specifies how many electrons can occupy that orbital.
Principal Quantum Number (n)
The principal quantum number (n) assigns the size of the orbital and specifies the energy of an electron. If the value of n is larger, then the average distance of an electron in the orbital from the nucleus will be greater. Therefore the size of the orbital is large. The principal quantum numbers have the integral values of 1, 2, 3 and so forth and it corresponds to the quantum number in
The angular momentum quantum number (l) explains the shape of the atomic orbital. The values of l are integers which depend on the value of the principal quantum number, n. For a given value of n, the possible values of l range are from 0 to n − 1. If n = 1, there is only one possible value of l (l=0). If n = 2, there are two values of l: 0 and 1. If n = 3, there are three values of l: 0, 1, and 2. The value of l is selected by the letters s, p, d, and f. If l = 0, we have an s orbital; if l = 1, we have a p orbital; if l = 2, we have a d orbital and finally if l = 3, we have a f orbital. A collection of orbitals with the same value of n is called a shell. One or more orbitals with the same n and l values are referred to a subshell (sublevel). The value of l also has a slight effect on the energy of the subshell; the energy of the subshell increases with l (s < p < d < f).
Magnetic Quantum Number (ml)
The magnetic quantum number (ml ) explains the orientation of the orbital in space. The value of ml depends on the value of l in a subshell. This number divides the subshell into individual orbitals which hold the electrons. For a certain value of l, there are (2l + 1) integral values of ml which is explained as follows:
ml = ‒ l, ..., 0, ..., +l
If l = 0, there is only one possible value of ml: 0.
If l = 1, then there are three values of ml: −1, 0, and +1.
If l = 2, there are five values of ml, namely, −2, −1, 0, +1, and +2.
If l = 3, there are seven values of ml, namely, −3, −2, −1, 0, +1, +2, and +3, and so on.
The number of ml values indicates the number of orbitals in a subshell with a particular l value. Therefore, each ml value refers to a different orbital.
Electron Spin Quantum Number (ms)
It specifies the orientation of the spin axis of an electron. An electron can spin in only one of two directions. There are two possible ways to represent ms values. They are +½ and ‒½. One electron spins in the clockwise direction. Another electron spins in the anticlockwise direction. But, no two electrons should have the same spin quantum number.

Want to see the full answer?
Check out a sample textbook solution
Chapter 3 Solutions
Chemistry: Atoms First
- [Review Topics] [References] Write an acceptable IUPAC name for the compound below. (Only systematic names, not common names are accepted by this question.) Keep the information page open for feedback reference. The IUPAC name is Submit Answer Retry Entire Group 9 more group attempts remainingarrow_forwardPlease draw.arrow_forwardA chromatogram with ideal Gaussian bands has tR = 9.0 minutes and w1/2 = 2.0 minutes. Find the number of theoretical plates that are present, and calculate the height of each theoretical plate if the column is 10 centimeters long.arrow_forward
- An open tubular column has an inner diameter of 207 micrometers, and the thickness of the stationary phase on the inner wall is 0.50 micrometers. Unretained solute passes through in 63 seconds and a particular solute emerges at 433 seconds. Find the distribution constant for this solute and find the fraction of time spent in the stationary phase.arrow_forwardConsider a chromatography column in which Vs= Vm/5. Find the retention factor if Kd= 3 and Kd= 30.arrow_forwardTo improve chromatographic separation, you must: Increase the number of theoretical plates on the column. Increase the height of theoretical plates on the column. Increase both the number and height of theoretical plates on the column. Increasing the flow rate of the mobile phase would Increase longitudinal diffusion Increase broadening due to mass transfer Increase broadening due to multiple paths You can improve the separation of components in gas chromatography by: Rasing the temperature of the injection port Rasing the temperature of the column isothermally Rasing the temperature of the column using temperature programming In GC, separation between two different solutes occurs because the solutes have different solubilities in the mobile phase the solutes volatilize at different rates in the injector the solutes spend different amounts of time in the stationary phasearrow_forward
- please draw and example of the following: Show the base pair connection(hydrogen bond) in DNA and RNAarrow_forwardNaming and drawing secondary Write the systematic (IUPAC) name for each of the following organic molecules: CH3 Z structure CH3 CH2 CH2 N-CH3 CH3-CH2-CH2-CH-CH3 NH CH3-CH-CH2-CH2-CH2-CH2-CH2-CH3 Explanation Check ☐ name ☐ 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C Garrow_forwardC This question shows how molecular orbital (MO) theory can be used to understand the chemical properties of elemental oxygen O₂ and its anionic derivative superoxide Oz. a) Draw the MO energy diagram for both O2 and O2. Clearly label your diagram with atomic orbital names and molecular orbital symmetry labels and include electrons. Draw the Lewis structure of O2. How does the MO description of O2 differ from the Lewis structure, and how does this difference relate to the high reactivity and magnetic properties of oxygen? ) Use the MO diagram in (a) to explain the difference in bond length and bond energy between superoxide ion (Oz, 135 pm, 360 kJ/mol) and oxygen (O2, 120.8 pm, 494 kJ/mol).arrow_forward
- Please drawarrow_forward-Page: 8 nsition metal ions have high-spin aqua complexes except one: [Co(HO)₁]". What is the d-configuration, oxidation state of the metal in [Co(H:O))"? Name and draw the geometry of [Co(H2O)]? b) Draw energy diagrams showing the splitting of the five d orbitals of Co for the two possible electron configurations of [Co(H2O)]: Knowing that A = 16 750 cm and Пl. = 21 000 cm, calculate the configuration energy (.e., balance or ligand-field stabilization energy and pairing energy) for both low spin and high spin configurations of [Co(H2O)]. Which configuration seems more stable at this point of the analysis? (Note that 349.76 cm = 1 kJ/mol) Exchange energy (IT) was not taken into account in part (d), but it plays a role. Assuming exchange an occur within t29 and within eg (but not between tz, and ea), how many exchanges are possible in the low in configuration vs in the high spin configuration? What can you say about the importance of exchange energy 07arrow_forwardDraw everything please on a piece of paper explaining each steparrow_forward
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning




