The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy. Concept Introduction: Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( J ) . Energy is in the form of kinetic energy or potential energy . Kinetic energy is the energy associated with motion . Kinetic energy (in joule) is calculated using the formula: E k = 1 2 mu 2 Where m ‒ mass in kilograms; u – velocity in meters per second.

Question

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Answer 1

Question

Chapter 3, Problem 3.8QP

(a)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy.

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(a)

Expert Solution

Answer to Problem 3.8QP

The velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

Explanation of Solution

To find: Determine the velocity of an electron that have $Ek= 3.41 × 10-21 J$ .

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formula:

$u = 2Ekm$

By considering the given problem, the mass of an electron $m = 9.10938×10−28 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of an electron in kilograms is

$m = 9.10938 × 10−28 g × 1 kg1 × 103 gm = 9.10938 × 10−31 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)9.10938 × 10-31 kgu = 8.6 × 104 m/s$

Therefore, the velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

(b)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(b)

Expert Solution

Answer to Problem 3.8QP

The velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2018.4 m/s$

Explanation of Solution

To find: Determine the velocity of a neutron that has $Ek= 3.41 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where, $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formulae:

$u = 2Ekm$

By considering the given problem, the mass of a neutron $m = 1.67493×10−24 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of a neutron in kilograms is

$m = 1.67493 × 10−24 g × 1 kg1 × 103 gm = 1.67493 × 10−27 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)1.67493 × 10-27 kgu = 2017.8 m/s$

Therefore, the velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2017.8 m/s$

(c)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(c)

Expert Solution

Answer to Problem 3.8QP

The mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton

Explanation of Solution

To find: Determine the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, mass in kilograms is calculated using the formula:

$m = 2Eku2$

By considering the given problem, the mass of a $Kr$ atom $m = 83.80 amu$ ; $Ek= 2.0509 × 10-21 J$ . $Ek$ Value in $2.0509 × 10-21 J$ is equal to $Ek$ value in $2.0509 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation.

The mass of a subatomic particle in kilograms is

$m = 2 × (2.0509 × 10-21 kg×m2/s2)(1.566 × 103 m/s)2m = 1.67 × 10-27 kg$

If the mass in $kg$ is converted into the mass in $g$ , the identity of a subatomic particle will be determined. The factor for conversion of $kg → g$ is given as follows:

$1 × 103 g1 kg$

By substituting the mass value in the above expression, the identity of a subatomic particle will be determined as follows:

$1.67 × 10-27 kg × 1 × 103 g1 kg1.67 × 10-24 g$

The subatomic particle with a mass of $1.67 × 10-24 g$ is a proton. Therefore, the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton.

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Answer 2

Question

Chapter 3, Problem 3.8QP

(a)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy.

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(a)

Expert Solution

Answer to Problem 3.8QP

The velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

Explanation of Solution

To find: Determine the velocity of an electron that have $Ek= 3.41 × 10-21 J$ .

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formula:

$u = 2Ekm$

By considering the given problem, the mass of an electron $m = 9.10938×10−28 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of an electron in kilograms is

$m = 9.10938 × 10−28 g × 1 kg1 × 103 gm = 9.10938 × 10−31 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)9.10938 × 10-31 kgu = 8.6 × 104 m/s$

Therefore, the velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

(b)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(b)

Expert Solution

Answer to Problem 3.8QP

The velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2018.4 m/s$

Explanation of Solution

To find: Determine the velocity of a neutron that has $Ek= 3.41 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where, $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formulae:

$u = 2Ekm$

By considering the given problem, the mass of a neutron $m = 1.67493×10−24 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of a neutron in kilograms is

$m = 1.67493 × 10−24 g × 1 kg1 × 103 gm = 1.67493 × 10−27 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)1.67493 × 10-27 kgu = 2017.8 m/s$

Therefore, the velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2017.8 m/s$

(c)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(c)

Expert Solution

Answer to Problem 3.8QP

The mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton

Explanation of Solution

To find: Determine the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, mass in kilograms is calculated using the formula:

$m = 2Eku2$

By considering the given problem, the mass of a $Kr$ atom $m = 83.80 amu$ ; $Ek= 2.0509 × 10-21 J$ . $Ek$ Value in $2.0509 × 10-21 J$ is equal to $Ek$ value in $2.0509 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation.

The mass of a subatomic particle in kilograms is

$m = 2 × (2.0509 × 10-21 kg×m2/s2)(1.566 × 103 m/s)2m = 1.67 × 10-27 kg$

If the mass in $kg$ is converted into the mass in $g$ , the identity of a subatomic particle will be determined. The factor for conversion of $kg → g$ is given as follows:

$1 × 103 g1 kg$

By substituting the mass value in the above expression, the identity of a subatomic particle will be determined as follows:

$1.67 × 10-27 kg × 1 × 103 g1 kg1.67 × 10-24 g$

The subatomic particle with a mass of $1.67 × 10-24 g$ is a proton. Therefore, the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton.

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Answer 3

Question

Chapter 3, Problem 3.8QP

(a)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy.

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(a)

Expert Solution

Answer to Problem 3.8QP

The velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

Explanation of Solution

To find: Determine the velocity of an electron that have $Ek= 3.41 × 10-21 J$ .

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formula:

$u = 2Ekm$

By considering the given problem, the mass of an electron $m = 9.10938×10−28 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of an electron in kilograms is

$m = 9.10938 × 10−28 g × 1 kg1 × 103 gm = 9.10938 × 10−31 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)9.10938 × 10-31 kgu = 8.6 × 104 m/s$

Therefore, the velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

(b)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(b)

Expert Solution

Answer to Problem 3.8QP

The velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2018.4 m/s$

Explanation of Solution

To find: Determine the velocity of a neutron that has $Ek= 3.41 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where, $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formulae:

$u = 2Ekm$

By considering the given problem, the mass of a neutron $m = 1.67493×10−24 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of a neutron in kilograms is

$m = 1.67493 × 10−24 g × 1 kg1 × 103 gm = 1.67493 × 10−27 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)1.67493 × 10-27 kgu = 2017.8 m/s$

Therefore, the velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2017.8 m/s$

(c)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(c)

Expert Solution

Answer to Problem 3.8QP

The mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton

Explanation of Solution

To find: Determine the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, mass in kilograms is calculated using the formula:

$m = 2Eku2$

By considering the given problem, the mass of a $Kr$ atom $m = 83.80 amu$ ; $Ek= 2.0509 × 10-21 J$ . $Ek$ Value in $2.0509 × 10-21 J$ is equal to $Ek$ value in $2.0509 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation.

The mass of a subatomic particle in kilograms is

$m = 2 × (2.0509 × 10-21 kg×m2/s2)(1.566 × 103 m/s)2m = 1.67 × 10-27 kg$

If the mass in $kg$ is converted into the mass in $g$ , the identity of a subatomic particle will be determined. The factor for conversion of $kg → g$ is given as follows:

$1 × 103 g1 kg$

By substituting the mass value in the above expression, the identity of a subatomic particle will be determined as follows:

$1.67 × 10-27 kg × 1 × 103 g1 kg1.67 × 10-24 g$

The subatomic particle with a mass of $1.67 × 10-24 g$ is a proton. Therefore, the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton.

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Answer 4

Question

Chapter 3, Problem 3.8QP

(a)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy.

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(a)

Expert Solution

Answer to Problem 3.8QP

The velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

Explanation of Solution

To find: Determine the velocity of an electron that have $Ek= 3.41 × 10-21 J$ .

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formula:

$u = 2Ekm$

By considering the given problem, the mass of an electron $m = 9.10938×10−28 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of an electron in kilograms is

$m = 9.10938 × 10−28 g × 1 kg1 × 103 gm = 9.10938 × 10−31 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)9.10938 × 10-31 kgu = 8.6 × 104 m/s$

Therefore, the velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

(b)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(b)

Expert Solution

Answer to Problem 3.8QP

The velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2018.4 m/s$

Explanation of Solution

To find: Determine the velocity of a neutron that has $Ek= 3.41 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where, $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formulae:

$u = 2Ekm$

By considering the given problem, the mass of a neutron $m = 1.67493×10−24 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of a neutron in kilograms is

$m = 1.67493 × 10−24 g × 1 kg1 × 103 gm = 1.67493 × 10−27 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)1.67493 × 10-27 kgu = 2017.8 m/s$

Therefore, the velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2017.8 m/s$

(c)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(c)

Expert Solution

Answer to Problem 3.8QP

The mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton

Explanation of Solution

To find: Determine the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, mass in kilograms is calculated using the formula:

$m = 2Eku2$

By considering the given problem, the mass of a $Kr$ atom $m = 83.80 amu$ ; $Ek= 2.0509 × 10-21 J$ . $Ek$ Value in $2.0509 × 10-21 J$ is equal to $Ek$ value in $2.0509 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation.

The mass of a subatomic particle in kilograms is

$m = 2 × (2.0509 × 10-21 kg×m2/s2)(1.566 × 103 m/s)2m = 1.67 × 10-27 kg$

If the mass in $kg$ is converted into the mass in $g$ , the identity of a subatomic particle will be determined. The factor for conversion of $kg → g$ is given as follows:

$1 × 103 g1 kg$

By substituting the mass value in the above expression, the identity of a subatomic particle will be determined as follows:

$1.67 × 10-27 kg × 1 × 103 g1 kg1.67 × 10-24 g$

The subatomic particle with a mass of $1.67 × 10-24 g$ is a proton. Therefore, the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton.

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Answer 5

Chapter 3, Problem 3.8QP

(a)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy.

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(a)

Expert Solution

Answer to Problem 3.8QP

The velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

Explanation of Solution

To find: Determine the velocity of an electron that have $Ek= 3.41 × 10-21 J$ .

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formula:

$u = 2Ekm$

By considering the given problem, the mass of an electron $m = 9.10938×10−28 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of an electron in kilograms is

$m = 9.10938 × 10−28 g × 1 kg1 × 103 gm = 9.10938 × 10−31 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)9.10938 × 10-31 kgu = 8.6 × 104 m/s$

Therefore, the velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

(b)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(b)

Expert Solution

Answer to Problem 3.8QP

The velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2018.4 m/s$

Explanation of Solution

To find: Determine the velocity of a neutron that has $Ek= 3.41 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where, $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formulae:

$u = 2Ekm$

By considering the given problem, the mass of a neutron $m = 1.67493×10−24 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of a neutron in kilograms is

$m = 1.67493 × 10−24 g × 1 kg1 × 103 gm = 1.67493 × 10−27 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)1.67493 × 10-27 kgu = 2017.8 m/s$

Therefore, the velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2017.8 m/s$

(c)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(c)

Expert Solution

Answer to Problem 3.8QP

The mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton

Explanation of Solution

To find: Determine the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, mass in kilograms is calculated using the formula:

$m = 2Eku2$

By considering the given problem, the mass of a $Kr$ atom $m = 83.80 amu$ ; $Ek= 2.0509 × 10-21 J$ . $Ek$ Value in $2.0509 × 10-21 J$ is equal to $Ek$ value in $2.0509 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation.

The mass of a subatomic particle in kilograms is

$m = 2 × (2.0509 × 10-21 kg×m2/s2)(1.566 × 103 m/s)2m = 1.67 × 10-27 kg$

If the mass in $kg$ is converted into the mass in $g$ , the identity of a subatomic particle will be determined. The factor for conversion of $kg → g$ is given as follows:

$1 × 103 g1 kg$

By substituting the mass value in the above expression, the identity of a subatomic particle will be determined as follows:

$1.67 × 10-27 kg × 1 × 103 g1 kg1.67 × 10-24 g$

The subatomic particle with a mass of $1.67 × 10-24 g$ is a proton. Therefore, the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton.

Answer 6

Chapter 3, Problem 3.8QP

(a)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy.

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(a)

Expert Solution

Answer to Problem 3.8QP

The velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

Explanation of Solution

To find: Determine the velocity of an electron that have $Ek= 3.41 × 10-21 J$ .

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formula:

$u = 2Ekm$

By considering the given problem, the mass of an electron $m = 9.10938×10−28 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of an electron in kilograms is

$m = 9.10938 × 10−28 g × 1 kg1 × 103 gm = 9.10938 × 10−31 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)9.10938 × 10-31 kgu = 8.6 × 104 m/s$

Therefore, the velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

Answer 7

Chapter 3, Problem 3.8QP

(a)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy.

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

Answer 8

(a)

Expert Solution

Answer to Problem 3.8QP

The velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

To find: Determine the velocity of an electron that have $Ek= 3.41 × 10-21 J$ .

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formula:

$u = 2Ekm$

By considering the given problem, the mass of an electron $m = 9.10938×10−28 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of an electron in kilograms is

$m = 9.10938 × 10−28 g × 1 kg1 × 103 gm = 9.10938 × 10−31 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)9.10938 × 10-31 kgu = 8.6 × 104 m/s$

Therefore, the velocity of an electron that has $Ek= 3.41 × 10-21 J$ is $8.6 × 104 m/s$

Answer 13

(b)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(b)

Expert Solution

Answer to Problem 3.8QP

The velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2018.4 m/s$

Explanation of Solution

To find: Determine the velocity of a neutron that has $Ek= 3.41 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where, $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formulae:

$u = 2Ekm$

By considering the given problem, the mass of a neutron $m = 1.67493×10−24 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of a neutron in kilograms is

$m = 1.67493 × 10−24 g × 1 kg1 × 103 gm = 1.67493 × 10−27 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)1.67493 × 10-27 kgu = 2017.8 m/s$

Therefore, the velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2017.8 m/s$

Answer 14

(b)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

Answer 15

(b)

Expert Solution

Answer to Problem 3.8QP

The velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2018.4 m/s$

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

To find: Determine the velocity of a neutron that has $Ek= 3.41 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where, $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, velocity in meters per second is calculated using the formulae:

$u = 2Ekm$

By considering the given problem, the mass of a neutron $m = 1.67493×10−24 g$ ; $Ek= 3.41 × 10-21 J$ .

The mass of a neutron in kilograms is

$m = 1.67493 × 10−24 g × 1 kg1 × 103 gm = 1.67493 × 10−27 kg$

$Ek$ Value in $3.41 × 10-21 J$ is equal to $Ek$ value in $3.41 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation. Substitute the given values in the formula,

$u = 2 × (3.41 × 10-21 kg×m2/s2)1.67493 × 10-27 kgu = 2017.8 m/s$

Therefore, the velocity of a neutron that has $Ek= 3.41 × 10-21 J$ is $2017.8 m/s$

Answer 20

(c)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

(c)

Expert Solution

Answer to Problem 3.8QP

The mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton

Explanation of Solution

To find: Determine the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, mass in kilograms is calculated using the formula:

$m = 2Eku2$

By considering the given problem, the mass of a $Kr$ atom $m = 83.80 amu$ ; $Ek= 2.0509 × 10-21 J$ . $Ek$ Value in $2.0509 × 10-21 J$ is equal to $Ek$ value in $2.0509 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation.

The mass of a subatomic particle in kilograms is

$m = 2 × (2.0509 × 10-21 kg×m2/s2)(1.566 × 103 m/s)2m = 1.67 × 10-27 kg$

If the mass in $kg$ is converted into the mass in $g$ , the identity of a subatomic particle will be determined. The factor for conversion of $kg → g$ is given as follows:

$1 × 103 g1 kg$

By substituting the mass value in the above expression, the identity of a subatomic particle will be determined as follows:

$1.67 × 10-27 kg × 1 × 103 g1 kg1.67 × 10-24 g$

The subatomic particle with a mass of $1.67 × 10-24 g$ is a proton. Therefore, the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton.

Answer 21

(c)

Interpretation Introduction

Interpretation:

The velocity of the given atoms, the mass and identity of a subatomic particle should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force. The SI unit of energy is joule ( $J$ ). Energy is in the form of kinetic energy or potential energy. Kinetic energy is the energy associated with motion. Kinetic energy (in joule) is calculated using the formula:

$Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second.

Answer 22

(c)

Expert Solution

Answer to Problem 3.8QP

The mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

To find: Determine the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$

Kinetic energy (in joule) is calculated using the formula: $Ek = 12mu2$

Where $m$ ‒ mass in kilograms; $u$ – velocity in meters per second. From this equation, mass in kilograms is calculated using the formula:

$m = 2Eku2$

By considering the given problem, the mass of a $Kr$ atom $m = 83.80 amu$ ; $Ek= 2.0509 × 10-21 J$ . $Ek$ Value in $2.0509 × 10-21 J$ is equal to $Ek$ value in $2.0509 × 10-21 kg×m2/s2$ which is used for the purpose of making the unit cancellation.

The mass of a subatomic particle in kilograms is

$m = 2 × (2.0509 × 10-21 kg×m2/s2)(1.566 × 103 m/s)2m = 1.67 × 10-27 kg$

If the mass in $kg$ is converted into the mass in $g$ , the identity of a subatomic particle will be determined. The factor for conversion of $kg → g$ is given as follows:

$1 × 103 g1 kg$

By substituting the mass value in the above expression, the identity of a subatomic particle will be determined as follows:

$1.67 × 10-27 kg × 1 × 103 g1 kg1.67 × 10-24 g$

The subatomic particle with a mass of $1.67 × 10-24 g$ is a proton. Therefore, the mass and identity of a subatomic particle moving at $1.566 × 103 m/s$ that has $Ek= 2.0509 × 10-21 J$ are $1.67 × 10-27 kg$ and a proton.

Answer 27

Ch. 3.1 - Calculate the kinetic energy of a helium atom...Ch. 3.1 - Calculate the energy in joules of a 5.25-g object...Ch. 3.1 - Prob. 1PPB Ch. 3.1 - Prob. 1PPC Ch. 3.1 - Prob. 3.2WE Ch. 3.1 - How much greater is the electrostatic potential...Ch. 3.1 - What must the separation between charges of +2 and...Ch. 3.1 - Prob. 2PPC Ch. 3.1 - Prob. 3.1.1SR Ch. 3.1 - Prob. 3.1.2SR

Answer to Problem 3.8QP

Explanation of Solution

Answer to Problem 3.8QP

Explanation of Solution

Answer to Problem 3.8QP

Explanation of Solution

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