The element which has a single atom travelling at 15 percent of the speed of light and having de Broglie wavelength of 1 .06 × 10 − 16 m should be found using the concept of De Broglie’s hypothesis. Concept Introduction: De Broglie’s hypothesis explains the behaviour of waves. Waves can behave like particles while particles can exhibit wave like properties. De Broglie deduced that the particle and wave properties are related by the following expression: λ = h mu where, λ is the wavelength associated with a moving particle; h is Planck’s constant; m is the mass of the particle and u is the velocity of the moving particle. To find: The element which has a single atom travelling at 15 percent of the speed of light and having de Broglie wavelength of 1 .06 × 10 − 16 m
The element which has a single atom travelling at 15 percent of the speed of light and having de Broglie wavelength of 1 .06 × 10 − 16 m should be found using the concept of De Broglie’s hypothesis. Concept Introduction: De Broglie’s hypothesis explains the behaviour of waves. Waves can behave like particles while particles can exhibit wave like properties. De Broglie deduced that the particle and wave properties are related by the following expression: λ = h mu where, λ is the wavelength associated with a moving particle; h is Planck’s constant; m is the mass of the particle and u is the velocity of the moving particle. To find: The element which has a single atom travelling at 15 percent of the speed of light and having de Broglie wavelength of 1 .06 × 10 − 16 m
Solution Summary: The author analyzes De Broglie's hypothesis, which explains the behaviour of waves. Waves behave like particles while particles exhibit wavelike properties.
Definition Definition Rate at which light travels, measured in a vacuum. The speed of light is a universal physical constant used in many areas of physics, most commonly denoted by the letter c . The value of the speed of light c = 299,792,458 m/s, but for most of the calculations, the value of the speed of light is approximated as c = 3 x 10 8 m/s.
Chapter 3, Problem 3.129QP
Interpretation Introduction
Interpretation:
The element which has a single atom travelling at 15 percent of the speed of light and having de Broglie wavelength of 1.06 × 10−16 m should be found using the concept of De Broglie’s hypothesis.
Concept Introduction:
De Broglie’s hypothesis explains the behaviour of waves. Waves can behave like particles while particles can exhibit wave like properties. De Broglie deduced that the particle and wave properties are related by the following expression:
λ =hmu
where, λ is the wavelength associated with a moving particle; h is Planck’s constant; m is the mass of the particle and u is the velocity of the moving particle.
To find: The element which has a single atom travelling at 15 percent of the speed of light and having de Broglie wavelength of 1.06 × 10−16 m
For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check
the appropriate box.
Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below.
Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions
- just focus on the first stable product you expect to form in solution.
?
NH2
MgBr
Will the first product that forms in this reaction
create a new CC bond?
○ Yes
○ No
MgBr
?
Will the first product that forms in this reaction
create a new CC bond?
O Yes
O No
Click and drag to start drawing a
structure.
:☐
G
x
c
olo
Ar
HE
Predicting
As the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule
with a new C - C bond as its major product:
H₂N
O
H
1.
?
2. H3O+
If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more
than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for
example to distinguish between major products with different stereochemistry.
0
If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank.
فا
Explanation
Check
Click and drag to start drawing a
structure.
Highlight the chirality (or stereogenic) center(s) in the given compound. A compound may have one or more stereogenic centers.
OH
OH
OH
OH
OH
OH
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