Chapter 3.2, Problem 9PP

Interpretation Introduction

Interpretation:

The amount of ammonia needs to be determined.

Concept introduction:

The mass percentage is defined as the percentage of component present in it. The mass percentage of the element is the mass of element divided by the total mass of the compound and multiplied by 100.

$\text{Mass percentage=}\frac{\text{mass}\text{of}\text{element}}{\text{mass}\text{of}\text{total}\text{compound}}\text{×100}$

Answer to Problem 9PP

The amount of ${\text{NH}}_{\text{3}}$ gas involved in the reaction is $51\text{g}$.

Explanation of Solution

The mass of the HCl(g) is $106.5\text{g}$ and the formed ammonium chloride is $157.5\text{g}$

So for the amount of ammonia gas participated in the reaction-

$\text{Mass}\text{of}\text{reactant}\text{=}\text{Mass}\text{of}\text{product}$

$\text{Mass}\text{of}\text{product}\text{=}\text{Mass of HCl+}\text{Mass}\text{of}{\text{NH}}_{\text{3}}$

$\text{Mass}\text{of}{\text{NH}}_{\text{4}}\text{Cl}\text{=}\text{Mass of HCl+}\text{Mass}\text{of}{\text{NH}}_{\text{3}}$

$\text{Mass}\text{of}{\text{NH}}_{\text{3}}\text{=}\text{Mass of}{\text{NH}}_{\text{4}}\text{Cl}\text{-}\text{Mass of HCl}$

$\text{=157}\text{.5}\text{g}\text{-}\text{106}\text{.5}\text{g}\text{=}\text{51}\text{g}$

Conclusion

The amount is $\text{51}\text{g}$.