Concept explainers
Interpretation:
The value for % Cl and % F, should be determined for sample II.
Concept introduction:
The mass percentage is defined as the percentage of component present in it. The mass percentage of the element is the mass of element divided by the total mass of the compound and multiplied by 100.

Answer to Problem 1STP
Correct answer: The correct option is (d).
Explanation of Solution
Reason for correct option:
According to the given table:
Mass Analysis of two chlorine-fluorine sample | ||||
Sample | Mass of chlorine (g) | Mass of fluorine (g) | % Cl | %F |
I | ||||
II | ? | ? |
The mass percentage of the elements is calculated as-
The given value of mass of Cl for sample II from the table = 5.753
The given value of mass of F for sample II from the table = 9.248
The complete table is:
Mass Analysis of two chlorine-fluorine sample | ||||
Sample | Mass of chlorine (g) | Mass of fluorine (g) | % Cl | %F |
I | ||||
II |
Hence, the correct option is (d).
Reasons for incorrect options:
Option (a) Value given in this option is not equals to
Option (b)Value given in this option is not equals to
Option (c) Value given in this option is not equals to
Chapter 3 Solutions
Chemistry: Matter and Change
Additional Science Textbook Solutions
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
Campbell Essential Biology (7th Edition)
Microbiology: An Introduction
Introductory Chemistry (6th Edition)
Biology: Life on Earth (11th Edition)
Campbell Biology (11th Edition)
- Could someone answer this NMR and explain please Comment on the general features of the 1H-NMR spectrum of isoamyl ester provided below.arrow_forwardMacmillan Learning Draw the acyl chloride that would give the ketone shown using the Friedel-Crafts acylation reaction. Select Draw Templates More с H о Cl 2Q Erase AICI₂arrow_forwardDraw the complete mechanism for this reaction: .OH مدید OH H2SO4 + H₂O To save you some time, the starting material has been copied into the first drawing area. However, you will still need to add any other reactants or catalysts that take part in the reaction. ན ི.. OH Add/Remove step Х ด ك Click and drag to start drawing a structure.arrow_forward
- 9:27 AM Tue Mar 4 ← Problem 64 of 15 #63% Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. 0:0 0:0 :0: N. :0: :O :0: H H. :0: Select to Add Arrows O :0: H O :0: 0:0. S. H Select to Add Arrows S :0: :0: H Harrow_forwardOrder the following organic reactions by relative rate. That is, select '1' next to the reaction that will have the fastest initial rate, select '2' next to the reaction that will have the next fastest initial rate, and so on. If two reactions will have very similar initial rates, you can select the same number next to both. If a reaction will have zero or nearly zero initial rate, don't select a number and check the box in the table instead. Note: the "Nu" in these reactions means "a generic nucleophile." ملی CI :Nu 2 он 3 H Reaction Relative Rate (Choose one) ▼ Nu :CI: zero or nearly zero Nu :Nu bi (Choose one) zero or nearly zero : Nu لی Nu :H (Choose one) zero or nearly zeroarrow_forward9:12 AM Tue Mar 4 66% Problem 38 of 15 Submit Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the product formed in this reaction or mechanistic step(s). Include all lone pairs and charges as appropriate. Ignore inorganic byproducts. Br2 FeBrз H (+) Br: H : Br----FeBr3 く a SU 00 nd earrow_forward
- Under aqueous acidic conditions, nitriles will react to form a neutral organic intermediate 1 that has an N atom in it first, and then they will continue to react to form the final product 2: ☐ : P Draw the missing intermediate 1 and the final product 2 in the box below. You can draw the two structures in any arrangement you like. CN H₂O H₂O H+ H+ Click and drag to start drawing a structure. Хarrow_forwardOrganic bases have lone pairs of electrons that are capable of accepting protons. Lone pair electrons in a neutral or negatively charged species, or pi electron pairs. Explain the latter case (pi electron pairs).arrow_forwardDescribe the propyl anion.arrow_forward
- Indicate the names of these compounds (if they exist). 0: HỌC—NH CH3CH2-CH2arrow_forwardN Classify each of the following molecules as aromatic, antiaromatic, or nonaromatic. NH O aromatic O antiaromatic O nonaromatic O aromatic O antiaromatic O nonaromatic O aromatic O antiaromatic O nonaromatic Garrow_forwardThe conjugate base of alkanes is called alkides. Correct?.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





