Chapter 3.2, Problem 5PP

Interpretation Introduction

Interpretation:

The mass of bromine reacted in the reaction and the mass of compound formed needs to be determined.

Concept introduction:

According to law of conservation of mass, total mass of reactant and product in a chemical reaction remains the same before and after the completion of the reaction.

Answer to Problem 5PP

The mass of bromine reacted and compound formed is 91.8 g and 102.1 g respectively.

Explanation of Solution

The given data for the reaction between aluminium and liquid bromine is as follows:

The mass of aluminium before and after the reaction is 10.3 g and 0 g respectively. The mass of liquid bromine before and after the reaction is 100 g and 8.2 g respectively.

Now, the grams of bromine reacted can be calculated using the initial and final mass of the bromine as follows:

$m_{\text{bromine reacted}}=m_{\text{before reaction}}-m_{\text{after reaction}}$

Putting the values,

$m_{\text{bromine reacted}}=100\text{ g}-8.2\text{ g}=91.8\text{ g}$

Thus, the mass of bromine reacted is 91.8 g.

Now, the mass of compound formed can be calculated using the law of conservation of mass as follows:

The mass if aluminium reacted is 10.3 g and that of bromine reacted is 91.8 g thus, the total mass of compound formed will be sum of the two masses.

$m_{compound}=91.8+10.3=102.1\text{ g}$

Therefore, the mass of compound formed is 102.1 g.

Conclusion

Therefore, the mass of bromine reacted and compound formed is 91.8 g and 102.1 g respectively.