
Concept explainers
(a)
Interpretation:
Using VSEPR Theory, the geometry of each central atom present in given structure of ATP is to be identified.
Concept IntroductionBond angles in the molecules can be predicted by using valence shell electron pair repulsion (VSEPR) model. According to this model, the valence electrons of an atom are involved in the formation of single, double or triple bond. The valence electrons can also be unshared and exist as lone pair on atoms. The combination forms a negatively charged region of electron density around a nucleus. Since, like charges do not attract, the region of electron density around a nucleus spread out so that each atom is as far away from each other at different angles.
(b)
Interpretation:
Using VSEPR theory, the various relative bond angles associated with each central atom of the ATP molecule is to be determined.
Concept Introduction:
Bond angles in the molecules can be predicted by using valence shell electron pair repulsion (VSEPR) model. According to this model, the valence electrons of an atom are involved in the formation of single, double or triple bond. The valence electrons can also be unshared and exist as lone pair on atoms. The combination forms a negatively charged region of electron density around a nucleus. Since, like charges do not attract, the region of electron density around a nucleus spread out so that each atom is as far away from each other at different angles.
(c)
Interpretation:
The most polar bond in ATP is to be predicted.
Concept Introduction:
A molecule is polar if it has polar bonds and the centers of its partial positive and partial negative charge do not coincide.
(d)
Interpretation:
Observing the bonds of ATP molecule, it has to be determined whether ATP is polar or nonpolar.
Concept Introduction:
A molecule is polar if it has polar bonds and if the centers of partial positive charge and partial negative charge lie at different places with in the molecule.

Want to see the full answer?
Check out a sample textbook solution
Chapter 3 Solutions
Introduction to General, Organic and Biochemistry
- A 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 10.0 mL of the base solution, what is the pH of the resulting solution?arrow_forwardGiven a complex reaction with rate equation v = k1[A] + k2[A]2, what is the overall reaction order?arrow_forwardPlease draw the structure in the box that is consistent with all the spectral data and alphabetically label all of the equivalent protons in the structure (Ha, Hb, Hc....) in order to assign all the proton NMR peaks. The integrations are computer generated and approximate the number of equivalent protons. Molecular formula: C13H1802 14 13 12 11 10 11 (ppm) Structure with assigned H peaks 2.08 3.13arrow_forward
- CHEMICAL KINETICS. One of the approximation methods for solving the rate equation is the steady-state approximation method. Explain what it consists of.arrow_forwardCHEMICAL KINETICS. One of the approximation methods for solving the rate equation is the limiting or determining step approximation method. Explain what it consists of.arrow_forwardCHEMICAL KINETICS. Indicate the approximation methods for solving the rate equation.arrow_forward
- TRANSMITTANCE เบบ Please identify the one structure below that is consistent with the 'H NMR and IR spectra shown and draw its complete structure in the box below with the protons alphabetically labeled as shown in the NMR spectrum and label the IR bands, including sp³C-H and sp2C-H stretch, indicated by the arrows. D 4000 OH LOH H₂C CH3 OH H₂C OCH3 CH3 OH 3000 2000 1500 HAVENUMBERI-11 1000 LOCH3 Draw your structure below and label its equivalent protons according to the peak labeling that is used in the NMR spectrum in order to assign the peaks. Integrals indicate number of equivalent protons. Splitting patterns are: s=singlet, d=doublet, m-multiplet 8 3Hb s m 1Hd s 3Hf m 2Hcd 2Had 1He 鄙视 m 7 7 6 5 4 3 22 500 T 1 0arrow_forwardRelative Transmittance 0.995 0.99 0.985 0.98 Please draw the structure that is consistent with all the spectral data below in the box and alphabetically label the equivalent protons in the structure (Ha, Hb, Hc ....) in order to assign all the proton NMR peaks. Label the absorption bands in the IR spectrum indicated by the arrows. INFRARED SPECTRUM 1 0.975 3000 2000 Wavenumber (cm-1) 1000 Structure with assigned H peaks 1 3 180 160 140 120 100 f1 (ppm) 80 60 40 20 0 C-13 NMR note that there are 4 peaks between 120-140ppm Integral values equal the number of equivalent protons 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 fl (ppm)arrow_forwardCalculate the pH of 0.0025 M phenol.arrow_forward
- In the following reaction, the OH- acts as which of these? NO2-(aq) + H2O(l) ⇌ OH-(aq) + HNO2(aq)arrow_forwardUsing spectra attached, can the unknown be predicted? Draw the predicition. Please explain and provide steps. Molecular focrmula:C16H13ClOarrow_forwardCalculate the percent ionization for 0.0025 M phenol. Use the assumption to find [H3O+] first. K = 1.0 x 10-10arrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning


