To find: The solution set for the given inequality.
Answer to Problem 27E
Solution set:
Explanation of Solution
Given information:
An inequality is given as -
Concept used:
Key numbers of a polynomial are its zeros. Real zeros of a polynomial divides real line into intervals in which the polynomial does not change its sign. A test value is taken from each interval and corresponding value of inequality is calculated (whether positive or negative). The inequality maintains same sign for whole interval.
Calculation:
Given inequality is -
Key numbers are
Test interval | Test | Polynomial value | Conclusion |
Negative | |||
Positive | |||
Negative | |||
Positive |
From above table, it can be concluded that inequality is satisfied in the interval
Hence, solution set for the given inequality will be
Graph of the solution set is drawn below.
Chapter 2 Solutions
Precalculus with Limits
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