Precalculus with Limits
Precalculus with Limits
3rd Edition
ISBN: 9781133947202
Author: Ron Larson
Publisher: Cengage Learning
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Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.
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Chapter 2, Problem 24RE
To determine

To divide : using the long division

Expert Solution & Answer
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Answer to Problem 24RE

  30x2−3x+85x−3=  (6x+3)  ︷Quotient+      17      ︷Remainder  5x−3  ︸Divisor

Explanation of Solution

Given information : 30x2−3x+85x−3

Concept Involved:

  1. Set up the long division.The divisor goes on the outside of the box. The dividend goes on the inside of the box. When you write out the dividend, make sure that you insert 0's for any missing terms.
  2. Divide 1st term of dividend by first term of divisor to get first term of the quotient.The quotient is written above the division box.Make sure that you line up the first term of the quotient with the term of the dividend that has the same degree.
  3. Take the term found in step 2 and multiply it times the divisor.Make sure that you line up all terms of this step with the term of the dividend that has the same degree.
  4. Subtract this from the line above.Make sure that you subtract EVERY term found in step 3, not just the first one.
  5. Repeat until done.You keep going until the degree of the "new" dividend is less than the degree of the divisor.Use the long division to find the other factor of the function
  6. Write out the answer. Your answer is the quotient that you ended up with on the top of the division box. If you have a remainder, write it over the divisor in your final answer.

The Division Algorithm : If f(x) and  d(x) are polynomials such that d(x)≠0 , and the degree of d(x) isless than or equal to the degree of f(x) , then there exist unique polynomials q(x) and  r(x) such that f (x)Dividend↑ = d(x)Divisor↑⋅q(x)Quotient↑ + r (x)Remainder↑  where r(x)=0 or the degree of r(x) is less than the degree of d(x) . If theremainder r(x) is zero, then d(x) divides evenly into f(x) and k can be called as zero of the polynomial.

Calculation:

Step 1: Set up the long division. The divisor goes on the outside of the box. The dividend goes on the inside of the box. When you write out the dividend, make sure that you insert 0's for any missing terms.

  5x−3)30x2−3x+8    ¯

Step 2: Divide 1st term of dividend by first term of divisor to get first term of the quotient. The quotient is written above the division box. Make sure that you line up the first term of the quotient with the term of the dividend that has the same degree.

                    6x5x−3)30x2−3x+8    ¯30x25x=6x

Step 3: Take the term found in previous and multiply it times the divisor. Make sure that you line up all terms of this step with the term of the dividend that has the same degree.

                    6x5x−3)30x2−3x+8    ¯               30x2−18x6x(5x−3)=30x2−18x

Step 4: Subtract this from the line above.Make sure that you subtract EVERY term found in step 3, not just the first one.

                    6x5x−3)   30x2  −    3x+8    ¯              +(−) 30x2  −(+)18x         _                                 15x+8

Step 5: Repeat until done. You keep going until the degree of the "new" dividend is less than the degree of the divisor. Use the long division to find the other factor of the function

                    6x+35x−3)   30x2  −    3x+8    ¯              +(−) 30x2  −(+)18x         _                                 15x+815x5x=3

Step 6: Take the term found in previous and multiply it times the divisor. Make sure that you line up all terms of this step with the term of the dividend that has the same degree.

                    6x+35x−3)   30x2  −    3x+8    ¯              +(−) 30x2  −(+)18x         _                                 15x+8                                 15x−93(5x−3)=15x−9

Step 7: Subtract this from the line above.Make sure that you subtract EVERY term found in step 3, not just the first one.

                    6x+35x−3)   30x2  −    3x+8    ¯              +(−) 30x2  −(+)18x         _                                 15x+8                            +(−)  15x−(+)9   _                                               17←Remainder

Conclusion:

By dividing the given polynomial  30x2−3x+8   by  5x−3  using the long division we get the quotient as 6x+3 and the remainder as 17 .

  30x2−3x+85x−3=  (6x+3)  ︷Quotient+      17      ︷Remainder  5x−3  ︸Divisor

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Chapter 2, Problem 23RE
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Chapter 2, Problem 25RE

Chapter 2 Solutions

Precalculus with Limits

Ch. 2.1 - Prob. 1ECh. 2.1 - Prob. 2ECh. 2.1 - Prob. 3ECh. 2.1 - Prob. 4ECh. 2.1 - Prob. 5ECh. 2.1 - Prob. 6ECh. 2.1 - Prob. 7ECh. 2.1 - Prob. 8ECh. 2.1 - Prob. 9ECh. 2.1 - Prob. 10E
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Prob. 78ECh. 2.5 - Prob. 79ECh. 2.5 - Prob. 80ECh. 2.5 - Prob. 81ECh. 2.5 - Prob. 82ECh. 2.5 - Prob. 83ECh. 2.5 - Prob. 84ECh. 2.5 - Prob. 85ECh. 2.5 - Prob. 86ECh. 2.5 - Prob. 87ECh. 2.5 - Prob. 88ECh. 2.5 - Prob. 89ECh. 2.5 - Prob. 90ECh. 2.5 - Prob. 91ECh. 2.5 - Prob. 92ECh. 2.5 - Prob. 93ECh. 2.5 - Prob. 94ECh. 2.5 - Prob. 95ECh. 2.5 - Prob. 96ECh. 2.5 - Prob. 97ECh. 2.5 - Prob. 98ECh. 2.5 - Prob. 99ECh. 2.5 - Prob. 100ECh. 2.5 - Prob. 101ECh. 2.5 - Prob. 102ECh. 2.5 - Prob. 103ECh. 2.5 - Prob. 104ECh. 2.5 - Prob. 105ECh. 2.5 - Prob. 106ECh. 2.5 - Prob. 107ECh. 2.5 - Prob. 108ECh. 2.5 - Prob. 109ECh. 2.5 - Prob. 110ECh. 2.5 - Prob. 111ECh. 2.5 - Prob. 112ECh. 2.5 - Prob. 113ECh. 2.5 - Prob. 114ECh. 2.5 - Prob. 115ECh. 2.5 - Prob. 116ECh. 2.5 - Prob. 117ECh. 2.5 - Prob. 118ECh. 2.5 - Prob. 119ECh. 2.5 - Prob. 120ECh. 2.5 - Prob. 121ECh. 2.5 - Prob. 122ECh. 2.5 - Prob. 123ECh. 2.5 - Prob. 124ECh. 2.5 - Prob. 125ECh. 2.5 - Prob. 126ECh. 2.5 - Prob. 127ECh. 2.5 - Prob. 128ECh. 2.5 - Prob. 129ECh. 2.5 - Prob. 130ECh. 2.5 - Prob. 131ECh. 2.6 - Prob. 1ECh. 2.6 - Prob. 2ECh. 2.6 - Prob. 3ECh. 2.6 - Prob. 4ECh. 2.6 - Prob. 5ECh. 2.6 - Prob. 6ECh. 2.6 - Prob. 7ECh. 2.6 - Prob. 8ECh. 2.6 - Prob. 9ECh. 2.6 - Prob. 10ECh. 2.6 - Prob. 11ECh. 2.6 - Prob. 12ECh. 2.6 - Prob. 13ECh. 2.6 - Prob. 14ECh. 2.6 - Prob. 15ECh. 2.6 - Prob. 16ECh. 2.6 - Prob. 17ECh. 2.6 - Prob. 18ECh. 2.6 - Prob. 19ECh. 2.6 - Prob. 20ECh. 2.6 - Prob. 21ECh. 2.6 - Prob. 22ECh. 2.6 - Prob. 23ECh. 2.6 - Prob. 24ECh. 2.6 - Prob. 25ECh. 2.6 - Prob. 26ECh. 2.6 - Prob. 27ECh. 2.6 - Prob. 28ECh. 2.6 - Prob. 29ECh. 2.6 - Prob. 30ECh. 2.6 - Prob. 31ECh. 2.6 - Prob. 32ECh. 2.6 - Prob. 33ECh. 2.6 - Prob. 34ECh. 2.6 - Prob. 35ECh. 2.6 - Prob. 36ECh. 2.6 - Prob. 37ECh. 2.6 - Prob. 38ECh. 2.6 - Prob. 39ECh. 2.6 - Prob. 40ECh. 2.6 - Prob. 41ECh. 2.6 - Prob. 42ECh. 2.6 - Prob. 43ECh. 2.6 - Prob. 44ECh. 2.6 - Prob. 45ECh. 2.6 - Prob. 46ECh. 2.6 - Prob. 47ECh. 2.6 - Prob. 48ECh. 2.6 - Prob. 49ECh. 2.6 - Prob. 50ECh. 2.6 - Prob. 51ECh. 2.6 - Prob. 52ECh. 2.6 - Prob. 53ECh. 2.6 - Prob. 54ECh. 2.6 - Prob. 55ECh. 2.6 - Prob. 56ECh. 2.6 - Prob. 57ECh. 2.6 - Prob. 58ECh. 2.6 - Prob. 59ECh. 2.6 - Prob. 60ECh. 2.6 - Prob. 61ECh. 2.6 - Prob. 62ECh. 2.6 - Prob. 63ECh. 2.6 - Prob. 64ECh. 2.6 - Prob. 65ECh. 2.6 - Prob. 66ECh. 2.6 - Prob. 67ECh. 2.6 - Prob. 68ECh. 2.6 - Prob. 69ECh. 2.6 - Prob. 70ECh. 2.6 - Prob. 71ECh. 2.6 - Prob. 72ECh. 2.6 - Prob. 73ECh. 2.6 - Prob. 74ECh. 2.6 - Prob. 75ECh. 2.6 - Prob. 76ECh. 2.6 - Prob. 77ECh. 2.6 - Prob. 78ECh. 2.6 - Prob. 79ECh. 2.6 - Prob. 80ECh. 2.6 - Prob. 81ECh. 2.6 - Prob. 82ECh. 2.7 - Prob. 1ECh. 2.7 - Prob. 2ECh. 2.7 - Prob. 3ECh. 2.7 - Prob. 4ECh. 2.7 - Prob. 5ECh. 2.7 - Prob. 6ECh. 2.7 - Prob. 7ECh. 2.7 - Prob. 8ECh. 2.7 - Prob. 9ECh. 2.7 - Prob. 10ECh. 2.7 - Prob. 11ECh. 2.7 - Prob. 12ECh. 2.7 - Prob. 13ECh. 2.7 - Prob. 14ECh. 2.7 - Prob. 15ECh. 2.7 - Prob. 16ECh. 2.7 - Prob. 17ECh. 2.7 - Prob. 18ECh. 2.7 - Prob. 19ECh. 2.7 - Prob. 20ECh. 2.7 - Prob. 21ECh. 2.7 - Prob. 22ECh. 2.7 - Prob. 23ECh. 2.7 - Prob. 24ECh. 2.7 - Prob. 25ECh. 2.7 - Prob. 26ECh. 2.7 - Prob. 27ECh. 2.7 - Prob. 28ECh. 2.7 - Prob. 29ECh. 2.7 - Prob. 30ECh. 2.7 - Prob. 31ECh. 2.7 - Prob. 32ECh. 2.7 - Prob. 33ECh. 2.7 - Prob. 34ECh. 2.7 - Prob. 35ECh. 2.7 - Prob. 36ECh. 2.7 - Prob. 37ECh. 2.7 - Prob. 38ECh. 2.7 - Prob. 39ECh. 2.7 - Prob. 40ECh. 2.7 - Prob. 41ECh. 2.7 - Prob. 42ECh. 2.7 - Prob. 43ECh. 2.7 - Prob. 44ECh. 2.7 - Prob. 45ECh. 2.7 - Prob. 46ECh. 2.7 - Prob. 47ECh. 2.7 - Prob. 48ECh. 2.7 - Prob. 49ECh. 2.7 - Prob. 50ECh. 2.7 - Prob. 51ECh. 2.7 - Prob. 52ECh. 2.7 - Prob. 53ECh. 2.7 - Prob. 54ECh. 2.7 - Prob. 55ECh. 2.7 - Prob. 56ECh. 2.7 - Prob. 57ECh. 2.7 - Prob. 58ECh. 2.7 - Prob. 59ECh. 2.7 - Prob. 60ECh. 2.7 - Prob. 61ECh. 2.7 - Prob. 62ECh. 2.7 - Prob. 63ECh. 2.7 - Prob. 64ECh. 2.7 - Prob. 65ECh. 2.7 - Prob. 66ECh. 2.7 - Prob. 67ECh. 2.7 - Prob. 68ECh. 2.7 - Prob. 69ECh. 2.7 - Prob. 70ECh. 2.7 - Prob. 71ECh. 2.7 - Prob. 72ECh. 2.7 - Prob. 73ECh. 2.7 - Prob. 74ECh. 2.7 - Prob. 75ECh. 2.7 - Prob. 76ECh. 2.7 - Prob. 77ECh. 2.7 - Prob. 78ECh. 2.7 - Prob. 79ECh. 2.7 - Prob. 80ECh. 2.7 - Prob. 81ECh. 2.7 - Prob. 82ECh. 2.7 - Prob. 83ECh. 2.7 - Prob. 84ECh. 2.7 - Prob. 85ECh. 2.7 - Prob. 86ECh. 2.7 - Prob. 87ECh. 2.7 - Prob. 88ECh. 2.7 - Prob. 89ECh. 2.7 - Prob. 90ECh. 2 - Prob. 1RECh. 2 - Prob. 2RECh. 2 - Prob. 3RECh. 2 - Prob. 4RECh. 2 - Prob. 5RECh. 2 - Prob. 6RECh. 2 - Prob. 7RECh. 2 - Prob. 8RECh. 2 - Prob. 9RECh. 2 - Prob. 10RECh. 2 - Prob. 11RECh. 2 - Prob. 12RECh. 2 - Prob. 13RECh. 2 - Prob. 14RECh. 2 - Prob. 15RECh. 2 - Prob. 16RECh. 2 - Prob. 17RECh. 2 - Prob. 18RECh. 2 - Prob. 19RECh. 2 - Prob. 20RECh. 2 - Prob. 21RECh. 2 - Prob. 22RECh. 2 - Prob. 23RECh. 2 - Prob. 24RECh. 2 - Prob. 25RECh. 2 - Prob. 26RECh. 2 - Prob. 27RECh. 2 - Prob. 28RECh. 2 - Prob. 29RECh. 2 - Prob. 30RECh. 2 - Prob. 31RECh. 2 - Prob. 32RECh. 2 - Prob. 33RECh. 2 - Prob. 34RECh. 2 - Prob. 35RECh. 2 - Prob. 36RECh. 2 - Prob. 37RECh. 2 - Prob. 38RECh. 2 - Prob. 39RECh. 2 - Prob. 40RECh. 2 - Prob. 41RECh. 2 - Prob. 42RECh. 2 - Prob. 43RECh. 2 - Prob. 44RECh. 2 - Prob. 45RECh. 2 - Prob. 46RECh. 2 - Prob. 47RECh. 2 - Prob. 48RECh. 2 - Prob. 49RECh. 2 - Prob. 50RECh. 2 - Prob. 51RECh. 2 - Prob. 52RECh. 2 - Prob. 53RECh. 2 - Prob. 54RECh. 2 - Prob. 55RECh. 2 - Prob. 56RECh. 2 - Prob. 57RECh. 2 - Prob. 58RECh. 2 - Prob. 59RECh. 2 - Prob. 60RECh. 2 - Prob. 61RECh. 2 - Prob. 62RECh. 2 - Prob. 63RECh. 2 - Prob. 64RECh. 2 - Prob. 65RECh. 2 - Prob. 66RECh. 2 - Prob. 1CTCh. 2 - Prob. 2CTCh. 2 - Prob. 3CTCh. 2 - Prob. 4CTCh. 2 - Prob. 5CTCh. 2 - Prob. 6CTCh. 2 - Prob. 7CTCh. 2 - Prob. 8CTCh. 2 - Prob. 9CTCh. 2 - Prob. 10CTCh. 2 - Prob. 11CTCh. 2 - Prob. 12CTCh. 2 - Prob. 13CTCh. 2 - Prob. 14CTCh. 2 - Prob. 15CTCh. 2 - Prob. 16CTCh. 2 - Prob. 17CTCh. 2 - Prob. 18CTCh. 2 - Prob. 1PSCh. 2 - Prob. 2PSCh. 2 - Prob. 3PSCh. 2 - Prob. 4PSCh. 2 - Prob. 5PSCh. 2 - Prob. 6PSCh. 2 - Prob. 7PSCh. 2 - Prob. 8PSCh. 2 - Prob. 9PSCh. 2 - Prob. 10PSCh. 2 - Prob. 11PSCh. 2 - Prob. 12PSCh. 2 - Prob. 13PS
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