
Tograph: Graph the quadratic function f(x)=−(x2+x−30) and identify vertex, axis of symmetry and x-intercepts.

Explanation of Solution
Given information: we have the given quadratic function is f(x)=−(x2+x−30)
Graph:
Using graphing calculator, the graph of the function is shown below
Interpretation:
We know that the standard for of a quadratic function f(x)=a(x−h)2+k, a≠0 whose axis of symmetry is x=h and vertex (h,k) .
For, the above form if a>0 then the graph is open upward and when a<0 the graph is open downward.
We have the given function is f(x)=−(x2+x−30)
It can further written as
f(x)=−(x2+x−30)=−(x+12)2+1214
Comparing with above we get
a=−1<0h=12k=1214
Therefore, the vertex of the parabola is (−12,1214) axis of symmetry is x=−12 and the graph is open downward.
To get the x-intercept we put f(x)=0 and solve for x which gives
−(x2+2x−3)=0x=5,6
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