
Concept explainers
(a)
To find:The zeroes of the given polynomial
(a)

Explanation of Solution
Given: The given function is f(x)=3x3−12x2+3x
Consider the given polynomial.
f(x)=3x3−12x2+3x
The zeroes of the polynomial is calculated as,
f(x)=3x3−12x2+3x=3x(x2−4x+1)=3x[(x2−4x+4)−4+1]=3x[(x−2)2−3]
Solve further,
f(x)=3x(x−2−√3)(x−2+√3)0=3x(x−2−√3)(x−2+√3)x=0, 2+√3, 2−√3
Therefore, the zeroes of the polynomial are 0, 2+√3 and 2−√3 .
(b)
To find :The multiplicity of each zero.
(b)

Explanation of Solution
Given: The zeroes of the polynomial are 0, 2+√3 and 2−√3 .
Consider the given polynomial.
f(x)=3x3−12x2+3x
The zeroes of the polynomial are 0, 2+√3 and 2−√3 .
The multiplicity of 2+√3 is odd.
The multiplicity of 2−√3 is odd.
The multiplicity of 0 is odd.
Therefore, the multiplicity of 0 is odd, 2+√3 is odd, 2−√3 is odd.
(c)
To find :The number of turning points.
(c)

Explanation of Solution
Given: The zeroes of the polynomial are 0, 2+√3 and 2−√3 .
Consider the given polynomial.
f(x)=3x3−12x2+3x
If n is the degree of the of polynomial, then the number of turning point is n−1 .
Turning point=n−1=3−1=2
Therefore, the number of turning point is 2 .
(d)
To find :The graph of the function.
(d)

Explanation of Solution
Given: The zeroes of the polynomial are 0, 2+√3 and 2−√3 .
Consider the given polynomial.
f(x)=3x3−12x2+3x
The graph of the function is shown in figure below.
Figure (1)
Therefore, graph of the function is shown in Figure (1).
Chapter 2 Solutions
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