
(a)
To approximate: .The relative extreme of the model over its domain..
(a)

Explanation of Solution
Given: The revenue is modelled by R=−0.1685t4+4.298t3−39.044t2+149.9t−185 and the domain is 3≤t≤10 .
The graph of the revenue function is shown below.
Figure (1)
The relative
The relative
Therefore, the relative maxima occurs at y13y (4.105, 21.869) and (9.018, 29.251) and the relative minima occurs at
(6.007, 18.808)
(b)
To approximate: .The interval over which the revenue of the company is increasing and decreasing over its domain.
(b)

Explanation of Solution
Given: The revenue is modelled by R=−0.1685t4+4.298t3−39.044t2+149.9t−185 and the domain is 3≤t≤10 .
The graph of the revenue function is shown below.
Figure (1)
The increasing interval is at (3, 4.105) and (6.007, 9.018)
The relative minima is at (4.105, 6.007) and (9.018, 10)
Therefore, the revenue is increasing in the interval (3, 4.105) and (6.007, 9.018) and decreasing in the interval (4.105, 6.007) and (9.018, 10) .
(c)
To find: .The company’s revenue during this time period.
(c)

Explanation of Solution
Given: The revenue is modelled by R=−0.1685t4+4.298t3−39.044t2+149.9t−185 and the domain is 3≤t≤10 .
From 2003 to the end of 2004 , the revenue of the company is increasing. From 2004 to start of 2006 the revenue of company is decreasing.
The revenue starts to increase again until early 2009 and lastly it decreases from 2009 to 2010 .
Chapter 2 Solutions
Precalculus with Limits
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