
To find: The solution set for the given inequality.

Answer to Problem 18E
Solution set:
(−1,7) .
Explanation of Solution
Given information:
An inequality is given as - x2−6x+9<16 .
Concept used:
Key numbers of a polynomial are its zeros. Real zeros of a polynomial divides real line into intervals in which the polynomial does not change its sign. A test value is taken from each interval and corresponding value of inequality is calculated (whether positive or negative). The inequality maintains same sign for whole interval.
Calculation:
Given inequality is - x2−6x+9<16
⇒x2−6x+9−16<0⇒x2−6x−7<0⇒x2+x−7x−7<0⇒(x+1)(x−7)<0
Key numbers are −1,7 .
Test interval | Test x− value | Polynomial value x2−6x−7<0 | Conclusion |
(−∞,−1) | x=−2 | (−2)2−6(−2)−7=9 | Positive |
(−1,7) | x=0 | 02−6(0)−7=−7 | Negative |
(7,∞) | x=5 | (5)2−6(5)−7=−12 | Positive |
From above table, it can be concluded that inequality is satisfied in the open intervals (−1,7) .
Hence, solution set for the given inequality will be (−1,7) .
Graph of the solution set is drawn below.
Chapter 2 Solutions
Precalculus with Limits
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