
Concept explainers
(a)
To find: The sketch for the graph of the function by the leading coefficient test.
(a)

Answer to Problem 76E
The by the leading coefficient method the graph of the function rise to the left and then fall to the right.
Explanation of Solution
Given:
The given equation is
Calculation:
For the leading coefficient test as the
Firstly, when the
Second when the value of
As the degree of the polynomial is even and the leading coefficient is positive, then by the leading coefficient test it is seen that the graph of the polynomial function then will rise to the left and then it will fall to the right.
Hence, the graph of the function falls to the left and then rise to the right.
(b)
To find: The sketch for the graph by the zero of the polynomial function.
(b)

Answer to Problem 76E
The zero of the polynomial is
Explanation of Solution
Given:
The given equation is
Calculation:
The zeros of the polynomial function is obtained by substituting
Then,
(c)
To find: The sketch for the function by plotting the sufficient solution points.
(c)

Answer to Problem 76E
The solution will vary.
Explanation of Solution
Given:
The given equation is
Calculation:
The number of sufficient points are fixed so the solution will vary.
(d)
To find: The sketch for the graph with the continuous curve through the points,
(d)

Answer to Problem 76E
The required equation is shown in Figure 1
Explanation of Solution
Given:
The given equation is
Calculation:
The sketch for the graph with the curve through the point is shown in Figure 1
Figure 1
Chapter 2 Solutions
Precalculus with Limits
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