a.
Interpretation: To give the isomerization reaction between pentane and 2-methyl butane.
Concept Introduction: A chemical process in which the compound is changed into different isomers is known as an isomerization reaction.
a.
Answer to Problem 82A
The isomerization reaction between pentane and 2-methyl butane is shown as follows:
Explanation of Solution
Pentane and 2-methyl butane are structural isomers or they can be classified as chain isomers.
Pentane isomerizes into 2-methyl butane and 2,2-dimethyl propane.
The isomerization reaction can be depicted as follows:
b.
Interpretation: To give the type of isomers.
Concept Introduction: The isomers in which the arrangement of atoms is in a different order while the molecular formulas of the compound remain the same are known as structural isomers.
b.
Answer to Problem 82A
Pentane and 2-methyl butane are chain isomers.
Explanation of Solution
In chain isomers, the molecular formula is the same for both compounds while how carbon chains are arranged is different.
Both pentane and 2-methyl butane have the same molecular formula that is
c.
Interpretation: To predict which isomer has the lowest boiling point.
Concept Introduction: The isomers in which the arrangement of atoms is in a different order while the molecular formulas of the compound remain the same are known as structural isomers.
c.
Answer to Problem 82A
2-methyl butane has the lowest boiling point than pentane.
Explanation of Solution
The boiling point is the temperature at which the vapor pressure of the substance becomes identical to the pressure surrounding the liquid.
The boiling point decreases as the branching in the compound increases. Both pentane and 2-methyl butane are chain isomers of each other. In pentane, the carbon atoms are arranged in a straight-chain isomer while in 2-methyl butane the carbon atoms are arranged in branches.
Therefore, the boiling point of 2-methyl butane is less than pentane.
Chapter 22 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Rank the following compounds most to least acidic: a) О OH 요애 OH .OH flow flow О F F F F OH F b) Ha EN-Ha CI Ha F F CI Haarrow_forwarda) b) Provide arrows to show the mechanisms and then predict the products of the following acid base reaction. Use pKas to determine which way the reaction will favor (Hint: the lower pka acid will want to dissociate) Дон OH Ha OH NH2 c) H H-O-Harrow_forwardMATERIALS. Differentiate between interstitial position and reticular position.arrow_forward
- For each of the following, indicate whether the arrow pushes are valid. Do we break any rules via the arrows? If not, indicate what is incorrect. Hint: Draw the product of the arrow and see if you still have a valid structure. a. b. N OH C. H N + H d. e. f. مه N COHarrow_forwardDecide which is the most acidic proton (H) in the following compounds. Which one can be removed most easily? a) Ha Нь b) Ha Нь c) CI CI Cl Ha Ньarrow_forwardProvide all of the possible resonanse structures for the following compounds. Indicate which is the major contributor when applicable. Show your arrow pushing. a) H+ O: b) c) : N :O : : 0 d) e) Оarrow_forward
- Draw e arrows between the following resonance structures: a) b) : 0: :0: c) :0: N t : 0: بار Narrow_forwardDraw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. Cl Substitution will not occur at a significant rate. Explanation Check :☐ O-CH + Х Click and drag to start drawing a structure.arrow_forwardDraw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. Cl C O Substitution will not occur at a significant rate. Explanation Check + O-CH3 Х Click and drag to start drawing a structure.arrow_forward
- ✓ aw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. C Cl HO–CH O Substitution will not occur at a significant rate. Explanation Check -3 ☐ : + D Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Cearrow_forwardPlease correct answer and don't used hand raitingarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
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