Chapter 22, Problem 65A

Interpretation Introduction

Interpretation- To write equation of combustion of octane.

Concept Introduction-

Combustion −

It is burning of hydrocarbons in presence of oxygen gas to produce carbon dioxide gas and steam. It produces heat energy and light.

It is highly exothermic reaction, In this oxidation of hydrocarbon takes place.

Example: ${\text{CH}}_{\text{4(g)}}{\text{+2O}}_{\text{2(g)}}\to {\text{CO}}_{\text{2(g)}}{\text{+2H}}_{\text{2}}{\text{O}}_{\text{(g)}}\text{+heat}$

Explanation of Solution

Octane is a hydrocarbon which burns in presence of oxygen gas to produce $\text{16}$ mole of carbon dioxide and $\text{18}$ moles of water with heat and light.

Combustion reaction of octane:

  ${\text{2C}}_{\text{8}}{\text{H}}_{\text{18(l)}}{\text{+25O}}_{\text{2(g)}}\to {\text{16CO}}_{\text{2(g)}}{\text{+18H}}_{\text{2}}{\text{O}}_{\text{(g)}}\text{+heat}$