Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
expand_more
expand_more
format_list_bulleted
Question
Chapter 22.4, Problem 30LC
(a)
Interpretation Introduction
Interpretation: Below drawn compounds should be named using the IUPAC system.
Concept Introduction: The benzene molecule has 6 Carbon atoms joined in a planar ring having alternate double bonds.
(a)
Expert Solution
Answer to Problem 30LC
IUPAC name is Ethyl Benzene
Explanation of Solution
Benzene ring linked to an Ethyl group (-CH2-CH3) makes Ethyl benzene. It has a formula C6H5CH2CH3.
Therefore, IUPAC name is Ethyl Benzene.
(b)
Interpretation Introduction
Interpretation: Below drawn compounds should be named using the IUPAC system.
Concept Introduction: The benzene molecule has 6 Carbon atoms joined in a planar ring having alternate double bonds.
(b)
Expert Solution
Answer to Problem 30LC
IUPAC name is BiPhenyl
Explanation of Solution
When two benzene rings are connected by a single covalent bond, it forms Bi-Phenyl.
Therefore, the IUPAC name is Bi-Phenyl.
(c)
Interpretation Introduction
Interpretation: Below drawn compounds should be named using the IUPAC system.
Concept Introduction: The benzene molecule has 6 Carbon atoms joined in a planar ring having alternate double bonds.
(c)
Expert Solution
Answer to Problem 30LC
IUPAC name is 1-Ethyl, 3-Propyl Benzene
Explanation of Solution
When the Benzene ring is connected with the Ethyl group (-CH2-CH3) on Carbon atom 1 and the propyl group (-CH2-CH2-CH3) on Carbon atom 3. It forms 1-Ethyl, 3-Propyl Benzene.
Therefore, the IUPAC name is 1-Ethyl, 3-Propyl Benzene.
Chapter 22 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
Ch. 22.1 - Prob. 1SPCh. 22.1 - Prob. 2SPCh. 22.1 - Prob. 3SPCh. 22.1 - Prob. 4SPCh. 22.1 - Prob. 5SPCh. 22.1 - Prob. 6SPCh. 22.1 - Prob. 7LCCh. 22.1 - Prob. 8LCCh. 22.1 - Prob. 9LCCh. 22.1 - Prob. 10LC
Ch. 22.1 - Prob. 11LCCh. 22.1 - Prob. 12LCCh. 22.1 - Prob. 13LCCh. 22.2 - Prob. 14LCCh. 22.2 - Prob. 15LCCh. 22.2 - Prob. 16LCCh. 22.2 - Prob. 17LCCh. 22.2 - Prob. 18LCCh. 22.3 - Prob. 19SPCh. 22.3 - Prob. 20SPCh. 22.3 - Prob. 21LCCh. 22.3 - Prob. 22LCCh. 22.3 - Prob. 23LCCh. 22.3 - Prob. 24LCCh. 22.3 - Prob. 25LCCh. 22.3 - Prob. 26LCCh. 22.3 - Prob. 27LCCh. 22.4 - Prob. 28LCCh. 22.4 - Prob. 29LCCh. 22.4 - Prob. 30LCCh. 22.4 - Prob. 31LCCh. 22.4 - Prob. 32LCCh. 22.5 - Prob. 33LCCh. 22.5 - Prob. 34LCCh. 22.5 - Prob. 35LCCh. 22.5 - Prob. 36LCCh. 22.5 - Prob. 37LCCh. 22.5 - Prob. 38LCCh. 22.5 - Prob. 39LCCh. 22.5 - Prob. 40LCCh. 22 - Prob. 41ACh. 22 - Prob. 42ACh. 22 - Prob. 43ACh. 22 - Prob. 44ACh. 22 - Prob. 45ACh. 22 - Prob. 46ACh. 22 - Prob. 47ACh. 22 - Prob. 48ACh. 22 - Prob. 49ACh. 22 - Prob. 50ACh. 22 - Prob. 51ACh. 22 - Prob. 52ACh. 22 - Prob. 53ACh. 22 - Prob. 54ACh. 22 - Prob. 55ACh. 22 - Prob. 56ACh. 22 - Prob. 57ACh. 22 - Prob. 58ACh. 22 - Prob. 59ACh. 22 - Prob. 60ACh. 22 - Prob. 61ACh. 22 - Prob. 62ACh. 22 - Prob. 63ACh. 22 - Prob. 64ACh. 22 - Prob. 65ACh. 22 - Prob. 66ACh. 22 - Prob. 67ACh. 22 - Prob. 68ACh. 22 - Prob. 69ACh. 22 - Prob. 70ACh. 22 - Prob. 71ACh. 22 - Prob. 72ACh. 22 - Prob. 73ACh. 22 - Prob. 74ACh. 22 - Prob. 75ACh. 22 - Prob. 76ACh. 22 - Prob. 77ACh. 22 - Prob. 78ACh. 22 - Prob. 79ACh. 22 - Prob. 80ACh. 22 - Prob. 81ACh. 22 - Prob. 82ACh. 22 - Prob. 84ACh. 22 - Prob. 85ACh. 22 - Prob. 86ACh. 22 - Prob. 87ACh. 22 - Prob. 89ACh. 22 - Prob. 90ACh. 22 - Prob. 91ACh. 22 - Prob. 92ACh. 22 - Prob. 93ACh. 22 - Prob. 94ACh. 22 - Prob. 95ACh. 22 - Prob. 96ACh. 22 - Prob. 97ACh. 22 - Prob. 98ACh. 22 - Prob. 99ACh. 22 - Prob. 100ACh. 22 - Prob. 101ACh. 22 - Prob. 102ACh. 22 - Prob. 103ACh. 22 - Prob. 104ACh. 22 - Prob. 105ACh. 22 - Prob. 106ACh. 22 - Prob. 107ACh. 22 - Prob. 108ACh. 22 - Prob. 109ACh. 22 - Prob. 110ACh. 22 - Prob. 111ACh. 22 - Prob. 1STPCh. 22 - Prob. 2STPCh. 22 - Prob. 3STPCh. 22 - Prob. 4STPCh. 22 - Prob. 5STPCh. 22 - Prob. 6STPCh. 22 - Prob. 7STPCh. 22 - Prob. 8STPCh. 22 - Prob. 9STPCh. 22 - Prob. 10STPCh. 22 - Prob. 11STPCh. 22 - Prob. 12STPCh. 22 - Prob. 13STPCh. 22 - Prob. 14STPCh. 22 - Prob. 15STPCh. 22 - Prob. 16STP
Knowledge Booster
Similar questions
- how to get limiting reactant and % yield based off this data Compound Mass 6) Volume(mL Ben zaphone-5008 ne Acetic Acid 1. Sam L 2-propanot 8.00 Benzopin- a col 030445 Benzopin a Colone 0.06743 Results Compound Melting Point (°c) Benzopin acol 172°c - 175.8 °c Benzoping to lone 1797-180.9arrow_forwardAssign ALL signals for the proton and carbon NMR spectra on the following pages.arrow_forward7.5 1.93 2.05 C B A 4 3 5 The Joh. 9 7 8 1 2 7.5 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 ppm 9 7 8 0.86 OH 10 4 3 5 1 2 7.5 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 ppm 9 7 8 CI 4 3 5 1 2 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 2.21 4.00 1.5 2.00 2.07 1.0 ppm 2.76arrow_forward
- Assign the functional group bands on the IR spectra.arrow_forwardFind the pH of a 0.120 M solution of HNO2. Find the pH ignoring activity effects (i.e., the normal way). Find the pH in a solution of 0.050 M NaCl, including activityarrow_forwardPlease help me answer these three questions. Required info should be in data table.arrow_forward
- Draw the major organic substitution product or products for (2R,3S)-2-bromo-3-methylpentane reacting with the given nucleophile. Clearly drawn the stereochemistry, including a wedged bond, a dashed bond and two in-plane bonds at each stereogenic center. Omit any byproducts. Bri CH3CH2O- (conc.) Draw the major organic product or products.arrow_forwardTartaric acid (C4H6O6) is a diprotic weak acid. A sample of 875 mg tartaric acid are dissolved in 100 mL water and titrated with 0.994 M NaOH. How many mL of NaOH are needed to reach the first equivalence point? How many mL of NaOH are needed to reach the second equivalence point?arrow_forwardIncluding activity, calculate the solubility of Pb(IO3)2 in a matrix of 0.020 M Mg(NO3)2.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY