Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 22, Problem 6STP
Interpretation Introduction

Interpretation: To predict which molecule has an enantiomer.

Concept Introduction: Stereoisomers are molecules that have the same number of carbon atoms but differ in the arrangement of atoms.

The two categories of stereoisomers are as follows:

  • Cis-trans isomers
  • Enantiomers

Expert Solution & Answer
Check Mark

Answer to Problem 6STP

Correct answer: The enantiomer is possible in the case of CFClBrI .

Explanation of Solution

Reason for the correct option:

Stereoisomers in which all the four groups on a carbon atom are different, thus enantiomers exist. This carbon is therefore termed an asymmetric carbon atom.

The pair of molecules that are mirror images of each other and are not superimposable are known as enantiomers.

Out of the given compound, the enantiomer is possible in the case of CFClBrI , since it has all different groups on the carbon atom.

Conclusion

Reasons for incorrect options: In CFClBrI molecules, enantiomers are possible as all the four groups on a carbon atom are different. Thus, all the other options stand incorrect.

Chapter 22 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 22.1 - Prob. 11LCCh. 22.1 - Prob. 12LCCh. 22.1 - Prob. 13LCCh. 22.2 - Prob. 14LCCh. 22.2 - Prob. 15LCCh. 22.2 - Prob. 16LCCh. 22.2 - Prob. 17LCCh. 22.2 - Prob. 18LCCh. 22.3 - Prob. 19SPCh. 22.3 - Prob. 20SPCh. 22.3 - Prob. 21LCCh. 22.3 - Prob. 22LCCh. 22.3 - Prob. 23LCCh. 22.3 - Prob. 24LCCh. 22.3 - Prob. 25LCCh. 22.3 - Prob. 26LCCh. 22.3 - Prob. 27LCCh. 22.4 - Prob. 28LCCh. 22.4 - Prob. 29LCCh. 22.4 - Prob. 30LCCh. 22.4 - Prob. 31LCCh. 22.4 - Prob. 32LCCh. 22.5 - Prob. 33LCCh. 22.5 - Prob. 34LCCh. 22.5 - Prob. 35LCCh. 22.5 - Prob. 36LCCh. 22.5 - Prob. 37LCCh. 22.5 - Prob. 38LCCh. 22.5 - Prob. 39LCCh. 22.5 - Prob. 40LCCh. 22 - Prob. 41ACh. 22 - Prob. 42ACh. 22 - Prob. 43ACh. 22 - Prob. 44ACh. 22 - Prob. 45ACh. 22 - Prob. 46ACh. 22 - Prob. 47ACh. 22 - Prob. 48ACh. 22 - Prob. 49ACh. 22 - Prob. 50ACh. 22 - Prob. 51ACh. 22 - Prob. 52ACh. 22 - Prob. 53ACh. 22 - Prob. 54ACh. 22 - Prob. 55ACh. 22 - Prob. 56ACh. 22 - Prob. 57ACh. 22 - Prob. 58ACh. 22 - Prob. 59ACh. 22 - Prob. 60ACh. 22 - Prob. 61ACh. 22 - Prob. 62ACh. 22 - Prob. 63ACh. 22 - Prob. 64ACh. 22 - Prob. 65ACh. 22 - Prob. 66ACh. 22 - Prob. 67ACh. 22 - Prob. 68ACh. 22 - Prob. 69ACh. 22 - Prob. 70ACh. 22 - Prob. 71ACh. 22 - Prob. 72ACh. 22 - Prob. 73ACh. 22 - Prob. 74ACh. 22 - Prob. 75ACh. 22 - Prob. 76ACh. 22 - Prob. 77ACh. 22 - Prob. 78ACh. 22 - Prob. 79ACh. 22 - Prob. 80ACh. 22 - Prob. 81ACh. 22 - Prob. 82ACh. 22 - Prob. 84ACh. 22 - Prob. 85ACh. 22 - Prob. 86ACh. 22 - Prob. 87ACh. 22 - Prob. 89ACh. 22 - Prob. 90ACh. 22 - Prob. 91ACh. 22 - Prob. 92ACh. 22 - Prob. 93ACh. 22 - Prob. 94ACh. 22 - Prob. 95ACh. 22 - Prob. 96ACh. 22 - Prob. 97ACh. 22 - Prob. 98ACh. 22 - Prob. 99ACh. 22 - Prob. 100ACh. 22 - Prob. 101ACh. 22 - Prob. 102ACh. 22 - Prob. 103ACh. 22 - Prob. 104ACh. 22 - Prob. 105ACh. 22 - Prob. 106ACh. 22 - Prob. 107ACh. 22 - Prob. 108ACh. 22 - Prob. 109ACh. 22 - Prob. 110ACh. 22 - Prob. 111ACh. 22 - Prob. 1STPCh. 22 - Prob. 2STPCh. 22 - Prob. 3STPCh. 22 - Prob. 4STPCh. 22 - Prob. 5STPCh. 22 - Prob. 6STPCh. 22 - Prob. 7STPCh. 22 - Prob. 8STPCh. 22 - Prob. 9STPCh. 22 - Prob. 10STPCh. 22 - Prob. 11STPCh. 22 - Prob. 12STPCh. 22 - Prob. 13STPCh. 22 - Prob. 14STPCh. 22 - Prob. 15STPCh. 22 - Prob. 16STP
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