Chapter 22, Problem 103A

a.

Interpretation Introduction

Interpretation: To give the reaction of dissociation for sodium hydroxide with water.

Concept Introduction: When a base reacts with the acid, a neutralization reaction occurs.

Answer to Problem 103A

  $\text{NaOH}\left(aq\right)+{\text{H}}_{\text{2}}\text{O}\left(l\right)\rightleftharpoons {\text{Na}}^{\text{+}}\left(aq\right)+{\text{OH}}^{-}\left(aq\right)$

Explanation of Solution

Sodium hydroxide is a strong base (dissociates completely into water), when it reacts with water it dissociates into sodium and hydroxide ions.

The dissociation of sodium hydroxide with water takes place as follows:

  $\text{NaOH}\left(aq\right)+{\text{H}}_{\text{2}}\text{O}\left(l\right)\rightleftharpoons {\text{Na}}^{\text{+}}\left(aq\right)+{\text{OH}}^{-}\left(aq\right)$

b.

Interpretation Introduction

Interpretation: To give the reaction of dissociation for barium hydroxide with water.

Concept Introduction: When a base reacts with the acid, a neutralization reaction occurs.

Answer to Problem 103A

  $\text{Ba}{\left(\text{OH}\right)}_2\left(aq\right)+{\text{H}}_{\text{2}}\text{O}\left(l\right)\rightleftharpoons {\text{Ba}}^{\text{2+}}\left(aq\right)+{\text{OH}}^{-}\left(aq\right)$

Explanation of Solution

Barium hydroxide is a strong base (dissociates completely into water), when it reacts with water it dissociates into barium and hydroxide ions.

The dissociation of barium hydroxide with water takes place as follows:

  $\text{Ba}{\left(\text{OH}\right)}_2\left(aq\right)+{\text{H}}_{\text{2}}\text{O}\left(l\right)\rightleftharpoons {\text{Ba}}^{\text{2+}}\left(aq\right)+{\text{OH}}^{-}\left(aq\right)$