Interpretation:
The values of
Concept introduction:
Different linearly independent wavefunctions that have same energy are called degenerate. This is expressed in terms of degeneracy. If two functions are having same energy then they are called doubly degenerate and so on. The electronic partition function is represented as,
Where,
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Physical Chemistry
- Chlorine dioxide (C1O2), which is produced by the reaction 2NaC1O2(aq)+Cl2(g)2ClO2(g)+2NaCl(aq) has been tested as a disinfectant for municipal water treatment. Using data from Table 17-1, calculate and G at 25C for the production of ClO2.arrow_forwardTable 16-1 shows the possible arrangements of four molecules in a two-bulbed flask. What are the possible arrangements if there is one molecule in this two-bulbed flask or two molecules or three molecules? For each, what arrangement is most likely?arrow_forwardThe Ostwald process for the commercial production of nitric acid involves three steps: 4NH3(g)+5O2(g)825CPt4NO(g)+6H2O(g)2NO(g)+O2(g)2NO2(g)3NO2(g)+H2O(l)2HNO3(l)+NO(g) a. Calculate H, S,G and K (at 298 K) for each of the three steps in the Ostwald process (see Appendix 4). b. Calculate the equilibrium constant for the first step at 825C, assuming H and S do not depend on temperature. c. Is there a thermodynamic reason for the high temperature in the first step, assuming standard conditions?arrow_forward
- Hydrogen sulfide can be removed from natural gas by the reaction 2H2S(g)+SO2(g)3S(s)+2H2O(g) Calculate G and K (at 298 K) for this reaction. Would this reaction be favored at a high or low temperature?arrow_forwardUnder what conditions is N2O3(g)NO(g)+NO2(g) spontaneous?arrow_forwardUsing data from Appendix 4, calculate H, G, and K (at 298 K) for the production of ozone from oxygen: 3O2(g)2O3(g) At 30 km above the surface of the earth, the temperature is about 230. K and the partial pressure of oxygen is about 1.0 103 atm. Estimate the partial pressure of ozone in equilibrium with oxygen at 30 km above the earth's surface. Is it reasonable to assume that the equilibrium between oxygen and ozone is maintained under these conditions? Explain.arrow_forward
- Given the dissociation of methane to graphite (C) and hydrogen gas. For the methane at 298K, Given the following data: kJ = -74.85- mol = -80.67 mol · K A,GE.graphite = A,Gån = 0 %3D Solve the following: a. Calculate the equilibrium constant (K) of the dissociation of methane at 298K with the appropriate units. b. Assuming that enthalpy is independent of temperature, Calculate the equilibrium constant (K) of methane dissociation at 1000 K. C. Calculate the ratio between the amounts of methane and hydrogen gas at 298 K and 0.2 bar.arrow_forwardCarbon dioxide dissolves in water to form carbonic acid. Estimate the thermodynamic equilibrium constant for this reaction using the AG; values in the table. Substance AG; (kJ/mol) H,CO, (aq) -616.1 H,O(1) -237.1 CO,(g) -394.4 K = Carbonic acid then ionizes in water (K = 4.5 x 10-7). Ignoring K2, estimate K for the overall process by which CO, and H,O form H* and HCO,. K = What is the pressure of CO, in equilibrium with carbonated water at 25 °C and pH = 4.78? Роо, atmarrow_forwardCarbon dioxide dissolves in water to form carbonic acid. Estimate the thermodynamic equilibrium constant for this reaction using the AG; values in the table. Substance AG; (kJ/mol) H,CO, (aq) -616.1 H, O(1) -237.1 CO,(g) -394.4 K = .002 Carbonic acid then ionizes in water (Kal = 4.5 x 10-7). Ignoring Ka2, estimate K for the overall process by which CO, and H,0 form H* and HCO, . К — Incorrect What is the pressure of CO, in equilibrium with carbonated water at 25 °C and pH = 4.78? Pco, atm Incorrectarrow_forward
- )AG for a chemical reaction is-18.3 kJ/mol. Determine the equilibrium constant for this reaction at 355 K.arrow_forwardConsider the system A(g)B(g) at25C. a. Assuming that GAo=8996J/molandGBo=11,718J/mol, calculate the value of the equilibrium constant for this reaction. b. Calculate the equilibrium pressures that result if 1.00 mole of A(g) at 1.00 atm and 1.00 mole of B(g) at 1.00 atm are mixed at 25C. c. Show by calculations that G = 0 at equilibrium.arrow_forwardConsider a system similar to the one in Figure 16.8, except that it contains six particles instead of four. What is the probability of having all the particles in only one of the two boxes in the case? Compare this with the similar probability for the system of four particles that we have derived to be equal to 18 . What does this comparison tell us about even larger systems?arrow_forward
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