Physical Chemistry
Physical Chemistry
2nd Edition
ISBN: 9781133958437
Author: Ball, David W. (david Warren), BAER, Tomas
Publisher: Wadsworth Cengage Learning,
Question
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Chapter 18, Problem 18.59E
Interpretation Introduction

Interpretation:

The set of equations (or a small program) to evaluate the constant-volume heat capacity for a moleculeis to be stated. The graph of the result is to be plotted. The trend for the same is to be stated. The heat capacity versus temperature (say from 298K to 1000K) for H2O and CH4 is to be determined using these algorithm.

Concept introduction:

The heat capacity at constant volume for nonlinear polyatomic molecule is given by the formula,

CV=Nk[32+32+j=13N*6(θjT)2eθj/T(1eθj/T)2]

Where,

N is the Avogadro number.

T is the temperature.

k is the Boltzmann constant.

θj is the rotational temperature.

Expert Solution & Answer
Check Mark

Answer to Problem 18.59E

The set of equations (or a small program) to evaluate the constant-volume heat capacity for a molecule are,

Nk

(θjT)2

eθj/T

1eθj/T

(1eθj/T)2

eθj/T(1eθj/T)2

(θjT)2eθj/T(1eθj/T)2

The plot between CV and T for CH4 is,

Physical Chemistry, Chapter 18, Problem 18.59E , additional homework tip  1

The plot between CV and T for H2O is,

Physical Chemistry, Chapter 18, Problem 18.59E , additional homework tip  2

Explanation of Solution

The heat capacity at constant volume for nonlinear polyatomic molecule is given by the formula,

CV=Nk[32+32+j=13N*6(θjT)2eθj/T(1eθj/T)2]…(1)

The set of equations(or a small program) to evaluate the constant-volume heat capacity for a molecule are shown below.

Nk

(θjT)2

eθj/T

1eθj/T

(1eθj/T)2

eθj/T(1eθj/T)2

(θjT)2eθj/T(1eθj/T)2

The vibrational temperatures for CH4 are 7.54K.

Substitute the value of vibrational temperatures for CH4 and 298K in equation (1).

CV=(6.02×1023mol1)(1.381×1023JK1){32+32+(7.54K298K)2exp(7.54K298K)[1exp(7.54K298K)]2}

The value of CV at different temperature is shown below.

T(θjT)2eθj/T(1eθj/T)2CV

29888804243994320275925348121104453765637707923398158404776330964513102448200704124631171.04E+08

498248004190297021.58E+08548300304279020972.32E+08598357604395657453.29E+08648419904545524984.53E+08

698487204734406156.1E+08748559504968547698.05E+087986368041.25E+081.04E+098487191041.6E+081.33E+09

8988064042.01E+081.67E+099488987042.5E+082.08E+099989960043.07E+082.55E+09

The plot between CV and T is shown below.

Physical Chemistry, Chapter 18, Problem 18.59E , additional homework tip  3

Figure 1

The three vibrational temperatures for H2O are 13.4K, 20.9K and 40.1K.

Substitute the value of vibrational temperatures for H2O and 298K in equation (1).

CV=(6.02×1023mol1)(1.381×1023JK1){32+32+(13.4K298K)2exp(13.4K298K)[1exp(13.4K298K)]2+(20.9K298K)2exp(20.9K298K)[1exp(20.9K298K)]2+(40.1K298K)2exp(40.1K298K)[1exp(40.1K298K)]2}

The value of CV at different temperature is shown below.

T(θjT)2eθj/T(1eθj/T)2CV

298    2.997914     24.912674482.99907724.922335982.99948224.925697482.99966924.92725

898      2.99977       24.92809

The plot between CV and T for H2O is shown below.

Physical Chemistry, Chapter 18, Problem 18.59E , additional homework tip  4

Figure 2

Conclusion

The set of equations (or a small program) to evaluate the constant-volume heat capacity for a molecule are,

Nk

(θjT)2

eθj/T

1eθj/T

(1eθj/T)2

eθj/T(1eθj/T)2

(θjT)2eθj/T(1eθj/T)2

The plot between CV and T for CH4 and H2O is shown in Figure 1 and Figure 2.

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Students have asked these similar questions
Part A: Methane at low temperatures Methane (CH4) is a tetrahedral molecule. Determine its specific heat capacity (at constant volume) at very low temperatures. Enter the value in units of the universal gas constant R. Hint: Remember that both vibrational and rotational modes are "frozen out" at low temperatures. What does the motion of a polyatomic gas molecule look like if it cannot vibrate or rotate? Cv,low = ? Part B: Methane at moderate temperatures Determine the specific heat capacity (at constant volume) of methane at moderate temperatures.
The French chemists, Pierre L. Dulong and Alexis T. Petit, noted in 1819 that the molar heat capacity of many solids at ordinary temperatures is proportional to the number of atoms per formula unit of the solid. They quantified their observations in what is known as Dulong and Petit's rule, which says that the molar heat capacity, ??CP , of a solid can be expressed as   ??=?⋅3?CP=N⋅3⁢R   where ?N is the number of atoms per formula unit and ?R is the universal gas constant. The observed heat capacity per gram of a compound containing thallium and chlorine is 0.21 J·K−1·g−10.21 J·K−1·g−1 . Use Dulong and Petit's rule to determine the empirical formula of the compound.
2. Explain why the heat capacity per mole of a crystal made of molecules, such as an amino acid, can become larger than that of a crystal that is an atomic solid (e.g. solid Al)
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