-C = C - C - + Br₂ + I" -> -C-C-c -C = C -C- + Br² + I₂ -C=C Br I + Brū + Iz -7- C - C-C- I Br Mechanism; - C = c - c - + Br - Br > - C-c-c- Br -C-C-C- + 1 - - -Ċ-Ċ'-c' - Br Br I
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- H₂C-HC O O O CH3 CHO CH₂ H₂C-C=CH₂ CH 3 H3C-C-CH3 OH Na₂Cr₂O, H₂SO, CH, O H3C-CH-C-H CH3 O | 11 H₂C-CH-C-OH O || H3C-C-CH3 ?For each of the following, circle the portion of the molecule that determines its functional group classification and state whether the functional group is an acyl halide, aldehyde, amide, anhydride, carboxylic acid, ester, ketone, lactam, lactone, or nitrile. Then, unless otherwise indicated, write both the IUPAC and common name of the molecule.Provide the IUPAC name for each one
- O O O O F F H-C-C-C-H CI CI FL LL F CI F F F C=C XE F CI F C=C1C-FProvide an IUPAC name for each of the compounds shown. (Specify (E)/(Z) stereochemistry, if relevant, for straight chain alkenes only. Pay attention to commas, dashes, etc.) H H C=C CHCH(CH3)2 ČH3 ÇH3 CH3 CH3 CH3 CH3CHC H CH3For each organic compound in the table below, name the highlighted side chain. Note for advanced students: don't include the locant of the side chain. compound H-C=0 name of highlighted side chain - - CH₂ — CH₂ — CH₂ — CH₂ — CH₂— CH₂· - CH G H C 0 H C 0 CH3 CH - CH2-CH₂ CH2 | H C 0 CH₂ CH₂2 I CH₂ CH₂ O HOC CH - CH2CH2 CH₂ — CH₂ CH=CH2 ☑ ☐