(a) Explanation Given Information: The transistor parameters are: K p = 0.12 mA V 2 λ = 0 R D = 30 k Ω The circuit parameters are shown below: I Q = 0.15 mA R D = 30 k Ω V T P = − 0.5 V The input vaues are: ( i ) v 1 = + 0.05 V, v 2 = − 0.05 V ( ii ) v 1 = + 0.10 V, v 2 = − 0.10 V The circuit diagram is shown below: Calculation: The transconductance of the transistor is given by the expression as shown below: g m = 2 K p I D Q Plugging the given values in the above expression, g m = 2 0.12 × 0.075 mA V g m = 0 (b) To determine The chang in v D 2 for the given changes in input voltage.

MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)

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ISBN: 9781266368622

Author: NEAMEN

Publisher: MCG

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Chapter 11, Problem 11.40P

(a)

To determine

The value of vD1−vD2 for the given values.

(b)

To determine

The chang in vD2 for the given changes in input voltage.

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Chapter 11, Problem 11.39P

Chapter 11, Problem 11.41P

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Chapter 11 Solutions

MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)

Ch. 11 - The circuit parameters for the differential...Ch. 11 - Consider the de transfer characteristics shown in...Ch. 11 - Prob. 11.1CSP Ch. 11 - Consider the diff-amp described in Example 11.3 ....Ch. 11 - Prob. 11.4EP Ch. 11 - Prob. 11.1TYU Ch. 11 - Prob. 11.2TYU Ch. 11 - Assume the differential-mode gain of a diff-amp is...Ch. 11 - Prob. 11.5EP Ch. 11 - Consider the diff-amp shown in Figure 11.15 ....

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The value of v D 1 − v D 2 for the given values.

Solution Summary: The author calculates the transconductance of the transistor by the expression as follows: lK_p=0.12

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The value of vD1−vD2 for the given values.

The chang in vD2 for the given changes in input voltage.

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Chapter 11 Solutions