Explanation Given Information: For transistors M 1 and M 2 , λ = 0 and current source is ideal. The given circuit is shown below. Calculation: The small-signal equivalent circuit is shown below. Applying Kirchhoff’s voltage law, v 1 = V g s 1 − V g s 2 + v 2 v 1 − v 2 = V g s 1 − V g s 2 Applying Kirchhoff’s voltage law, g m V g s 1 + g m V g s 2 = 0 V g s 1 = − V g s 2 Then V g s 1 = v 1 − v 2 2 and V g s 2 = − v 1 − v 2 2 Applying Kirchhoff’s current law at v o 1 node, g m V g s 1 + v O 1 R D + v O 1 − v O 2 R L = 0 v O 1 ( 1 R D + 1 R L ) − v O 2 R L = − g m ( v 1 − v 2 2 ) → ( 1 ) Applying Kirchhoff’s current law at v o 2 node, g m V g s 2 + v O 2 R D + v O 2 − v O 1 R L = 0 v O 2 ( 1 R D + 1 R L ) − v O 1 R L = g m ( v 1 − v 2 2 ) → ( 2 ) Summing the two equations, v O 2

MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)

4th Edition

ISBN: 9781266368622

Author: NEAMEN

Publisher: MCG

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Differential amplifier

There are two amplifying stages with common degeneration in a differential amplifier.

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Chapter 11, Problem 11.57P

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To derive: An expression for one-sided differential-mode gains and the two-sided differential mode gain for the given circuit.

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Chapter 11, Problem 11.56P

Chapter 11, Problem 11.58P

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Chapter 11 Solutions

MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)

Ch. 11 - The circuit parameters for the differential...Ch. 11 - Consider the de transfer characteristics shown in...Ch. 11 - Prob. 11.1CSP Ch. 11 - Consider the diff-amp described in Example 11.3 ....Ch. 11 - Prob. 11.4EP Ch. 11 - Prob. 11.1TYU Ch. 11 - Prob. 11.2TYU Ch. 11 - Assume the differential-mode gain of a diff-amp is...Ch. 11 - Prob. 11.5EP Ch. 11 - Consider the diff-amp shown in Figure 11.15 ....

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To derive: An expression for one-sided differential-mode gains and the two-sided differential mode gain for the given circuit.

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To derive: An expression for one-sided differential-mode gains and the two-sided differential mode gain for the given circuit.

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Chapter 11 Solutions