Answer 163 in 2 Explanation Given information: Slant Height( l ) of the cone is 9 inches Base radius( r ) of the cone is 4 inches Formula used: Surface area of a cone, Calculation: Substituting the value of radius( r ) and height( h ) in the formula, Putting value of pi upto 2 decimal point as 3.14 On solving nearly answer is, =163.28 in 2 Hence, approximate answer is =163 in 2

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

See similar textbooks

Question

Chapter 10.7, Problem 30E

To determine

To calculate approximate surface area of a cone

Expert Solution & Answer

Answer to Problem 30E

163 in²

Explanation of Solution

Given information: Slant Height( l ) of the cone is 9 inches

Base radius( r ) of the cone is 4 inches

Formula used:Surface area of a cone,

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 30E , additional homework tip 1

Calculation:Substituting the value of radius( r ) and height( h ) in the formula,

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 30E , additional homework tip 2

Putting value of pi upto 2 decimal point as 3.14

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 10.7, Problem 30E , additional homework tip 3

On solving nearly answer is,

=163.28 in²

Hence, approximate answer is

=163 in²

Chapter 10.7, Problem 29E

Chapter 10.7, Problem 31E

Chapter 10 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 10.1 - Prob. 1C Ch. 10.1 - Prob. 2C Ch. 10.1 - Prob. 3C Ch. 10.1 - Prob. 1E Ch. 10.1 - Prob. 2E Ch. 10.1 - Prob. 3E Ch. 10.1 - Prob. 4E Ch. 10.1 - Prob. 5E Ch. 10.1 - Prob. 6E Ch. 10.1 - Prob. 7E

Ch. 10.1 - Prob. 8E Ch. 10.1 - Prob. 9E Ch. 10.1 - Prob. 10E Ch. 10.1 - Prob. 11E Ch. 10.1 - Prob. 12E Ch. 10.1 - Prob. 13E Ch. 10.1 - Prob. 14E Ch. 10.1 - Prob. 15E Ch. 10.1 - Prob. 16E Ch. 10.1 - Prob. 17E Ch. 10.1 - Prob. 18E Ch. 10.1 - Prob. 19E Ch. 10.1 - Prob. 20E Ch. 10.1 - Prob. 21E Ch. 10.1 - Prob. 22E Ch. 10.1 - Prob. 23E Ch. 10.1 - Prob. 24E Ch. 10.1 - Prob. 25E Ch. 10.1 - Prob. 26E Ch. 10.1 - Prob. 27E Ch. 10.1 - Prob. 28E Ch. 10.1 - Prob. 29E Ch. 10.1 - Prob. 30E Ch. 10.1 - Prob. 31E Ch. 10.1 - Prob. 32E Ch. 10.2 - Prob. 1C Ch. 10.2 - Prob. 2C Ch. 10.2 - Prob. 3C Ch. 10.2 - Prob. 1E Ch. 10.2 - Prob. 2E Ch. 10.2 - Prob. 3E Ch. 10.2 - Prob. 4E Ch. 10.2 - Prob. 5E Ch. 10.2 - Prob. 6E Ch. 10.2 - Prob. 7E Ch. 10.2 - Prob. 8E Ch. 10.2 - Prob. 9E Ch. 10.2 - Prob. 10E Ch. 10.2 - Prob. 11E Ch. 10.2 - Prob. 12E Ch. 10.2 - Prob. 13E Ch. 10.2 - Prob. 14E Ch. 10.2 - Prob. 15E Ch. 10.2 - Prob. 16E Ch. 10.2 - Prob. 17E Ch. 10.2 - Prob. 18E Ch. 10.2 - Prob. 19E Ch. 10.2 - Prob. 20E Ch. 10.2 - 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