Chapter 10.3, Problem 33E

To determine

To calculate the area.

Answer to Problem 33E

4 : 3

Explanation of Solution

Given Information: BottomTrapezoid Base1 = 6 in, Base2 = $6+2+2=10$ in and Height = 2 in.

SideTrapezoid Base1 = 4 in, Base2 = $4+2+2=8$ in and Height = 2 in.

Formula Used:Area of Trapezoid = $\frac{1}{2}\times Sumofparallelbases\times Height$

Calculation:

Area of bottom Trapezoid: $\frac{1}{2}\times Sumofparallelbases\times Height$

Now, parallel sides is of Base1 = 6 in, Base2 = $6+2+2=10$ in and Height = 2 in.

Area of bottom Trapezoid: $\frac{1}{2}\times (6+10)\times 2$ square inch

Area of bottom Trapezoid: $\frac{1}{2}\times 16\times 2$ square inch

Area of bottom Trapezoid:16 square inch

Area of side Trapezoid: $\frac{1}{2}\times Sumofparallelbases\times Height$

Now, parallel sides is of Base1 = 4 in, Base2 = $4+2+2=8$ in and Height = 2 in.

Area of side Trapezoid: $\frac{1}{2}\times (4+8)\times 2$ square inch

Area of side Trapezoid: $\frac{1}{2}\times 12\times 2$ square inch

Area of side Trapezoid:12 square inch

Ratio of Area of bottom Trapezoid to Area of side Trapezoid

16 square inch : 12 square inch

4 : 3