Chapter 10, Problem 14PTTS

To determine

To find the area of the sign

Answer to Problem 14PTTS

  $104i{n}^2$

Explanation of Solution

Given information:

In right angle triangle

  $base=8in,height=5in$

The rectangle which is middle portion

  $length=16in,breadth=4in$

The parallelogram which is in the shape of wings

  $base=5in,height=2in$

Formula used:

To calculate the area of right angle triangle

  $area=\frac{1}{2}\times b\times h$

To calculate area of the rectangle

  $area=l\times b$

To calculate the area of the two parallelogram

  $area=2(b\times h)$

Calculation:

For right angle triangle, substituting the values of $b$ and $h$ in the formula

  $area=\frac{1}{2}\times 8\times 5$

Calculating area for the triangle

  $area=20i{n}^2$

For rectangle, substituting the values of $l$ and $b$

  $area=16\times 4=64i{n}^2$

For 2 parallelograms, substituting the values of $b$ and $h$

  $area=2(5\times 2)=20i{n}^2$

In order to calculate the area of the sign, add area of the triangle, rectangle and parallelogram

Area of the sign= area of the triangle+ area of the rectangle+ area of the parallelogram

Substituting the area of all the shapes

  $area=20+60+20$

The area of the sign is

  $area=104i{n}^2$