(a)
To calculate the base.
(a)
Answer to Problem 26E
Parking lot A = 45 ft.
Parking lot B = 63.5 ft.
Explanation of Solution
Given Information: Parallelogram Parking lot A Base1 = 9 ft. and Height = 18.5 ft.
Parallelogram Parking lot B Base1 = 12.7 ft. and Height = 17.5 ft.
Each Parking lot have 5 similar base.
Formula Used:Total Base =
Calculation:
Base1 of Parking lot A = 9 ft.
Total Base of Parking lot A =
Base1 of Parking lot B = 12.7 ft.
Total Base of Parking lot B =
(b)
To calculate the area.
(b)
Answer to Problem 26E
Parking lot A =
Parking lot B =
Explanation of Solution
Given Information:Parallelogram Parking lot A Base = 45 ft. and Height = 18.5 ft.
Parallelogram Parking lot B Base = 63.5 ft. and Height = 17.5 ft.
Formula Used:Area of Parallelogram =
Calculation:
Area of Parking lot A =
Now, Base = 45 ft. and Height = 18.5 ft.
Area of Parking lot A=
Area of Parking lot A=
Area of Parking lot B =
Now, Base = 63.5 ft. and Height = 17.5 ft.
Area of Parking lot B =
Area of Parking lot B =
(c)
To compare area.
(c)
Answer to Problem 26E
Parking lot A
Explanation of Solution
Given Information:Parallelogram Parking lot A Base = 45 ft. and Height = 18.5 ft.
Parallelogram Parking lot B Base = 63.5 ft. and Height = 17.5 ft.
Area of Parking lot A and Area of Parking lot B.
Formula Used:Comparison Parking lot A : Parking lot B
Calculation:
Area of Parking lot A =
Area of Parking lot B =
Hence,
So,
Parking lot A covers less area to park 5 cars as compared to Parking lot Bto park 5 cars.
Chapter 10 Solutions
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
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